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Research notes on every problem, and a library of the papers behind them. Built from the open erdos repository.

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Noga Alon and Paul Erdős, An application of graph theory to additive number theory, European J. Combin. 6 (1985), no. 3, 201–203, received 1984-05-20; library card. Inequality (4) of the paper states that every B2(k)B_2^{(k)} sequence of nn terms, one in which no integer has more than kk representations as a sum of two distinct terms, contains a Sidon subsequence of at least c4(k) n2/3c_4(k)\,n^{2/3} terms. In the problem's notation this is Hk(n)≫kn2/3H_k(n)\gg_k n^{2/3}, so Hk(n)/n1/2→∞H_k(n)/n^{1/2}\to\infty and Hk(n)>n1/2+cH_k(n)>n^{1/2+c} for every c<1/6c<1/6 and all large nn: both questions are answered yes. The site's hypothesis ∥1A∗1A∥∞≤k\|1_A\ast 1_A\|_\infty\leq k counts ordered pairs with repetition and the paper's counts unordered pairs of distinct terms; the two differ by a factor at most 22 in kk, which the kk-dependent constant absorbs. The exponent is sharp for k≥4k\geq4 in the site's count (k≥2k\geq2 in the paper's): Erdős's B2(2)B_2^{(2)} set of nn terms of the form 4u+4v4^u+4^v, in which any sum has at most four ordered representations, has no Sidon subset of more than O(n2/3)O(n^{2/3}) elements (Erdős 1984). For k=2,3k=2,3 the site's hypothesis makes Hk(n)H_k(n) of order nn: for k=2k=2 the set AA is itself Sidon, and for k=3k=3 the only coincidences are a+b=2ca+b=2c, each element the midpoint of at most one, so a Sidon subset of ≫n\gg n elements remains. For k=1k=1 the hypothesis is met by no set of two or more elements, since a+ba+b with a≠ba\neq b has the two ordered representations (a,b)(a,b) and (b,a)(b,a); for n≥2n\geq2 it is vacuous, so H1(n)H_1(n) is degenerate and the question is substantive for k≥2k\geq2.

The proof puts a 44-edge on the indices of every nontrivial additive quadruple ai+aj=al+ama_i+a_j=a_l+a_m; the hypothesis bounds the number of edges by fewer than (k−1)n2/4(k-1)n^2/4. Keeping each term independently with probability cn−1/3cn^{-1/3} leaves about cn2/3cn^{2/3} terms and about (k−1)c4n2/3/4(k-1)c^4n^{2/3}/4 edges, and deleting one term from each surviving edge leaves a Sidon subsequence of the required size when c=c(k)c=c(k) is small. Inequality (4) is the main ingredient of the paper's Theorem 1, that such a sequence is a union of Ok(n1/3)O_k(n^{1/3}) Sidon sequences, which is sharp up to the constant.

Acceptance. The paper is refereed (European J. Combin.). The site's curator, T. F. Bloom, records the answer yes with this bound and its proof on the problem page, which is the reviewed evidence named here. The month of the issue, September 1985, supplies the page's date.

Formalization. A Lean 4 formalization of the argument for the site's ordered count, posted on 2026-08-17 in Boris Alexeev's repository of formalized Erdős problems and linked above at a pinned commit, written by Codex and GPT-5.6 Sol with Alon and Erdős named as informal authors, proves both parts for every k≥1k\geq1 (erdos_772, from n2/3≤16(k+1)Hk(n)n^{2/3}\leq16(k+1)H_k(n)); the formal-conjectures statement file names it as its formal proof, and the community database has listed the problem as formalized since 2026-09-20. This corpus has not built it, so formalized is not listed.

Depends on. Nothing beyond the cited paper.