Research notes on every problem, and a library of the papers behind them. Built from the open erdos repository.
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Claim. For every fixed there are infinitely many such that the consecutive integers are all -smooth, where is the four-fold iterated logarithm (Theorem 1, p. 267). Since , for every and there are infinitely many with all -smooth. The source card is Balog and Wooley 1998.
Covers. The wording of Problem 369, which is trivially true, since are -smooth once , as the site notes; the theorem gives it with a nontrivial run: fix one of the infinitely many ; for every the run lies in and each member is -smooth, hence -smooth. The first of the two readings described on the problem page, that each member of the run be -smooth, follows directly, since . The second, that the run lie in , follows for infinitely many (take with ). Not covered: the second reading for all large , which needs the further construction of Yang 2026 or the theorem of Bober, Fretwell, Martin and Wooley 2020. The site's curator reports that Wooley described the paper's problem as slightly different, with a stronger uniformity that yields only infinitely many .
Acceptance. Published in J. Austral. Math. Soc. Ser. A 64 (1998), no. 2,
266–276, a refereed journal, in the issue dated April 1998 in the publisher's
record, which dates this page (refereed). The site's curator, Thomas F.
Bloom, records in the problem's commentary (page last edited 2026-04-28) that
the first strengthening follows from this result and that the second follows
from it for infinitely many (reviewed). Eggleton and Selfridge [EgSe76]
had earlier given, for every , infinitely many runs of five
consecutive integers each -smooth, which the site
notes sits oddly with Erdős and Graham's remark that the problem was open
even for ; that result is the partial claim
Eggleton and Selfridge 1976,
and the paper's section 2 comparison (pp. 267–268) records its smoothness
bounds and corrects a minor oversight in that result's source.
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