Wiki
Wiki

Research notes on every problem, and a library of the papers behind them. Built from the open erdos repository.

Updated


Claim. Let f(n,m)f(n,m) be the greatest number of edges in a bipartite graph whose parts have nn and mm vertices and which has no C4C_4 and no C6C_6. De Caen and Székely, The maximum size of 44- and 66-cycle free bipartite graphs on m,nm,n vertices, in: Sets, graphs and numbers, Colloq. Math. Soc. János Bolyai 60, North-Holland (1992), 135--142, prove, as the site records, n10/9≫f(n,⌊n2/3⌋)≫n58/57+o(1)n^{10/9}\gg f(n,\lfloor n^{2/3}\rfloor)\gg n^{58/57+o(1)} for m∼n2/3m\sim n^{2/3}, and more generally f(n,m)≪(nm)2/3f(n,m)\ll(nm)^{2/3} for n1/2≤m≤nn^{1/2}\le m\le n. The lower bound is a family of bipartite graphs with parts of sizes about n2/3n^{2/3} and nn, no C4C_4 and no C6C_6, and n1+εn^{1+\varepsilon} edges with ε=1/57−o(1)\varepsilon=1/57-o(1). Such a family answers Problem 1080 in the negative: for every c>0c>0 the graphs have more than cncn edges and no C6C_6 once nn is large, and the adjustment recorded under the problem page's Formulation note turns the parts into exactly the site's shape, NN vertices with one part of exactly ⌊N2/3⌋\lfloor N^{2/3}\rfloor vertices, at the cost of an o(1)o(1) fraction of the edges. A positive answer would have forced f(n,⌊n2/3⌋)≪nf(n,\lfloor n^{2/3}\rfloor)\ll n. The upper bound is the case m=n2/3m=n^{2/3} of the general bound, since (n⋅n2/3)2/3=n10/9(n\cdot n^{2/3})^{2/3}=n^{10/9}; the site also attributes the general bound to Faudree and Simonovits, without a reference.

What the corpus holds. Nothing of the chapter. The zbMATH record Zbl 0795.05083 identifies it, Crossref has no record of it, and the one open route tried answered HTTP 404; the problem page records the routes. The exponents are quoted from the site's commentary, no theorem is paged, and the construction was not read. The claim consumes no page of this wiki.

Acceptance. Reviewed: the site's curator, T. F. Bloom, credits de Caen and Székely with the negative answer and states their bounds in the problem's commentary (erdosproblems.com/1080, page last edited 14 October 2025, accessed 2026-09-18); the proof-claim tab is empty, and the dated search recorded on the problem page found no dispute. Not counted as refereed: the chapter appears in an edited Bolyai Society colloquium volume, not a journal, and its refereeing is not documented. The later construction of Lazebnik, Ustimenko and Woldar improves the lower bound, and the Lean file described below formalizes a disproof along that construction; neither is this page's evidence.

The formalization. The file src/v4.24.0/ErdosProblems/Erdos1080.lean of the plby/lean-proofs repository, linked above at the commit of 15 September 2026 that the link pins (the file's first commit is dated 28 December 2025), declares itself a Lean formalization of a solution to Problem 1080 whose original proof was found by de Caen and Székely; its header says that a proof of ChatGPT's choice was auto-formalized by Aristotle (from Harmonic), under the toolchain leanprover/lean4:v4.24.0, from the statement of the Formal Conjectures project. It defines the Lazebnik--Ustimenko--Woldar bipartite graph B(q)B(q) of points (p1,p2,p3)(p_1,p_2,p_3) and lines [l1,l2,l3][l_1,l_2,l_3] over a field, with adjacency l2−p2=l1p1l_2-p_2=l_1p_1 and l3−p3=l1qp2+l1p2ql_3-p_3=l_1^qp_2+l_1p_2^q, proves B_C6_free (the graph has no cycle of length 66) and, in thm_counterexamples_nonempty, that for every c>0c>0 there are nn and a graph on Fin n with a vertex set AA such that AA and its complement are both independent, ∣A∣=⌊n2/3⌋|A|=\lfloor n^{2/3}\rfloor, the graph has at least cncn edges and no 66-cycle; the parameters are an odd prime qq and integers k≤qk\le q, y≤q5y\le q^5 with kq3=⌊(kq3+y)2/3⌋kq^3=\lfloor(kq^3+y)^{2/3}\rfloor and ky≥c(kq3+y)ky\ge c(kq^3+y), the small part having kq3kq^3 vertices and the graph kyky edges. Its def erdos_1080 : Prop restates the formal-conjectures statement of the problem in the same shape, def not_erdos_1080 : ¬erdos_1080 is derived from that theorem, and a closing comment records #print axioms not_erdos_1080 as propext, Classical.choice and Quot.sound. Whatever its header says of the original proof, its route is the construction of Lazebnik, Ustimenko and Woldar, and with yy of order q5q^5 and kk of order q1/3q^{1/3} its parameters give about n16/15n^{16/15} edges on n≈q5n\approx q^5 vertices (an arithmetic remark made on the problem page, not a statement of the file). The thread post of 28 December 2025 announcing the file reports that Aristotle auto-formalized a solution from the Formal Conjectures statement; the formal-conjectures file at its pin states erdos_1080 as answer(False) with proof sorry and a formal_proof attribute naming this file on the repository's unpinned main branch, and is a statement file, not a formalization. The file (1,389 lines, import Mathlib) contains no sorry, axiom, native_decide or unsafe; this corpus has not built it, printed its axioms or audited its statement against the question, so the file is a link and not formalized evidence; the axiom list above is the file's own comment. The site's label DISPROVED (LEAN) and the community database's Lean formal status, as of its last update on 28 December 2025, record the catalog's acceptance of the file as the formalization of the disproof. Only the pinned commit is described; later commits, and the repository's copies of the file for later toolchains, are unexamined.

Depends on. No page of this wiki.