Research notes on every problem, and a library of the papers behind them. Built from the open erdos repository.
Updated
In Problem 399, the equation has no solution with and . A fourth power is or modulo as its base is even or odd, and coprime are not both even, so is or modulo , while for ; for , .
Covers. The sum with and . The same case, without the coprimality condition, also follows from the two-squares argument in the introduction of Erdős and Obláth (see their claim page): is a sum of two squares for no , and has no representation as a sum of two fourth powers.
Depends on. No page of this wiki.
Standing. Claimed. The remark is credited to Stijn Cambie in the site's
commentary; it is absent from the archived copy of the site's page of 7 April
2025 and present in the copy of 9 September 2025, the date this page carries.
The site's label settles the problem through Barfield's counterexample and not
through this remark, so reviewed is not listed, and the remark has no written
source of its own. The formal-conjectures file, at the commit of 18 September
2026 linked above, proves erdos_399.variants.cambie from this argument; the
contribution says it formalizes Cambie's argument as the docstring states it
and was developed with Claude. It is third-party Lean that this corpus has not
built or audited, so formalized is not listed.