Research notes on every problem, and a library of the papers behind them. Built from the open erdos repository.
Updated
Claim. Theorem 1 of [Er55d], printed p. 124, with the least integer such that the product of consecutive integers, each greater than , always contains a prime greater than : "There is a constant so that ." The constant is not specified. The statement is the library result page erdos_1955_consecutive_integers / theorem_1. The paper does not state a binomial form. For Problem 683 it applies to the numerator block of , whose members all exceed when : a prime greater than dividing a member of the block is not canceled by , so it divides . Applied with the threshold in place of , the theorem gives a prime factor greater than , hence , whenever , which holds when is at most a constant multiple of ; applied with a threshold of order satisfying , it gives otherwise. Together, for , the form the formal-conjectures file records. The site prints the bound without the minimum, and that form fails at , where .
Covers. The instances with and at most a constant multiple of , where and the inequality of the problem, read as its Formulation states, holds for every . Elsewhere the theorem gives only , no bound of the form ; those instances stay open.
Depends on. No page of this wiki; the result rests on the cited paper, whose statement the library result page above records.
Acceptance. Refereed: P. Erdős, On consecutive integers, Nieuw Arch.
Wisk. (3) 3 (1955), 124--128, a journal paper; the issue carries no month, so
the page is dated to the year. The site's commentary credits the result to
this paper, but the site labels the problem OPEN, so the remark is not
acceptance of a settling claim and no reviewed evidence is listed. The
formal-conjectures statement file
FormalConjectures/ErdosProblems/683.lean
records the bound with the minimum as the variant
erdos_683.variant.erdos_log, tagged research solved with a sorry body; a
statement file is not a formalization of the result.