Research notes on every problem, and a library of the papers behind them. Built from the open erdos repository.
Updated
Claim. The statement of Problem 702
as the site prints it, with and no range on , is false. For
and the family of all five four-element subsets of a five-element
set has members, and any two of its members
share three points, so no two meet in exactly one point. The Lean
development Erdos702.lean in Boris Alexeev's repository of Lean proofs,
added on 2026-08-18 and linked above at a pinned commit, records this as its
named theorem not_erdos_702: the negation of the statement quantified over
every , every and every -uniform family of subsets of Fin n
with more than members, proved from the family
allFourSubsetsOfFive by decidable checks of its size, its uniformity and
its pairwise intersections; the alias erdos_702_all_n_false names the same
theorem. The file's header names Frankl as the informal author and the AI
systems Codex and GPT-5.6 Sol as its formal authors, and its module
docstring presents the counterexample as the development's own record that
the all- formulation is false; the submitter of the repository is the
claimant here. The development's main theorem erdos_702_eventually is
Frankl's eventual statement and is a formalization link on
Frankl's claim page.
Depends on. No page of this wiki.
Why it is rejected. It answers the site's wording, not the corrected statement. Problem 702 judges the corrected Statement, which carries Erdős's own range from his statements of the conjecture of Erdős and Sós; the problem page's Notes give the evidence. A failure at shows only that the threshold is at least , so the refutation settles no instance of the corrected Statement. The problem page's Notes credit the result.
Standing. The site's curator labels the problem proved and credits Frankl's
theorem, so no outside reviewer has accepted a refutation of the problem. This
corpus's verification built the Lean file at the pinned commit linked above and
checked Erdos702.not_erdos_702: its axioms are exactly propext,
Classical.choice and Quot.sound, and its statement matches the repository's
comparator challenge ComparatorChallenges/ErdosProblems/Erdos702.lean. The
theorem is correct, but it refutes only the site's wording, so the page stays
rejected.