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A tournament is a complete directed graph. Let be such that every tournament on vertices contains a transitive tournament on vertices (i.e. one such that if then ).
Is it true that ?
Source: erdosproblems.com/1216
An accepted solution exists. The statement is false.
Disproved. Reid and Parker proved in 1970 that every tournament on vertices contains a transitive subtournament on vertices (Theorem 4, printed p. 235; with their -vertex tournament free of , pp. 235--236, this is ), so while , and more generally for (Corollary 2, p. 235), which exceeds for in the range of each . Their paper (J. Combinatorial Theory 9 (1970), 225--238, refereed) is in the publisher's open archive: library home Reid and Parker 1970, result pages Theorem 4 and Corollary 2. The claim page Reid and Parker 1970 records the theorem, its postings and the acceptance evidence; the later refutations each have their own claim page (listed under Claims below), and the frontmatter standing is derived from them. The paper states the conjecture in the equivalent form "for each positive integer , there exists a with which contains no " (p. 226) and shows it "false for all " (p. 235). The standing rests on Theorem 4; its proof was followed as a reduction to the paper's Theorems 2 and 3 and is not independently checked. The origin's own bounds, , are cited from the origin itself.