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Bode harborth 2005 directed paths diagonals within polygons

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theorem_1: Bode and Harborth's Theorem 1, Alspach's conjecture for t = n - 1: the only subset of {1, ..., n - 1} with n - 1 elements has sum n(n - 1)/2, nonzero modulo n only for even n, where the zigzag permutation (1, n - 2, 3, n - 4, ..., 2, n - 1) is a directed path; for odd n, hence for every odd prime, the theorem is vacuous.

theorem_2: Bode and Harborth's Theorem 2, Alspach's conjecture for t = n - 2 and every n: for odd n a directed cycle through all n - 1 lengths with one diagonal deleted, for even n an induction on the fixed missing length; the source of the size p - 2 in the near-full range of Problem 475.


Jens-P. Bode and Heiko Harborth, Directed paths of diagonals within polygons, Discrete Mathematics 299 (2005), 3--10, DOI 10.1016/j.disc.2005.05.006 (printed on p. 3); received 25 August 2003, received in revised form 5 May 2004, accepted 5 May 2005, available online 10 August 2005; both authors at Diskrete Mathematik, Technische Universität Braunschweig; "Dedicated to Brian Alspach on his 65th birthday" (p. 3). Cited as [BoHa05] on the problem page; it is reference [9] of hicks_2019_distinct_partial_sums_cyclic_groups_polynomial and [3] of kravitz_2024_rearranging_small_sets_distinct_partial_sums. The edition cited is the publisher's version of record at https://doi.org/10.1016/j.disc.2005.05.006; no preprint or repository version is known here. Its four references (p. 10) are the cycle decomposition papers Alspach's conjecture was meant to shorten: Alspach and Gavlas, Cycle decompositions of KnK_n and Kn−IK_n-I, J. Combin. Theory Ser. B 81 (2001), 77--99; Alspach, Gavlas, Šajna and Verrall, Cycle decompositions IV: complete directed graphs and fixed length directed cycles, J. Combin. Theory Ser. A 103 (2003), 165--208; Šajna, Cycle decompositions III: complete graphs and fixed length cycles, J. Combin. Des. 10 (2002), 27--78; and Šajna, Decomposition of the complete graph plus a 1-factor into cycles of equal length, J. Combin. Des. 11 (2003), 170--207; none is held.

The copy read for this card is the publisher's production PDF: 8 pages, printed pp. 3--10 = PDF pp. 1--8 (printed p. nn is PDF p. n−2n-2), distilled from the typeset article (Acrobat Distiller 4.05, creator Elsevier, created 22 August 2005 and modified 5 September 2005 per the copy's metadata), with a text layer that reads the prose and the theorem statements cleanly, prints the incongruence sign as "/≡", scatters the binomial coefficients and drops the letter π\pi from "rotation by π\pi"; the eleven figures are line drawings without text beyond their length labels. Provenance: the copy was obtained free of charge on 2026-09-22 from the publisher's platform through the library's acquisition, downloaded in a browser from https://www.sciencedirect.com/science/article/pii/S0012365X05002608/pdfft, the DOI https://doi.org/10.1016/j.disc.2005.05.006 resolving to the same article; 412,510 bytes. No other version is known here. That copy prints "© 2005 Elsevier B.V. All rights reserved." on its first page (printed p. 3), every other right reserved.

Read status: claims checked for the abstract, Conjecture 1, the definitions of length and directed path and the reformulation in terms of permutations (p. 3), the example, the motivation, the authors' checks and the scope sentence (p. 4), Theorem 1 with its proof and Theorem 2 with the odd-nn permutation (p. 4), the deletion sentence and the setup of the even case (p. 5), the end of the proof of Theorem 2 and the closing remark (pp. 9--10) and the reference list (p. 10), each read clause by clause on the page images of PDF pp. 1--3, 7 and 8 on 2026-09-22. The induction of the even case (pp. 5--9) was read in the text layer for structure only; its base cases and its step are carried by Figs. 2 and 4--11, which were not checked. The two printed permutations (Theorem 1's zigzag for even nn and Theorem 2's cycle for odd nn) were checked while filing for n≤16n\le16 and odd n≤39n\le39 respectively; that is a check made while filing, not retained evidence and not a review verdict. Nothing here is independently reviewed.

Contents

  • Abstract and § 1, Introduction (pp. 3--4, page images). The abstract is one sentence stating the result of Theorem 2: for any one fixed length, some directed path in the nn-gon uses each of the other n−2n-2 lengths exactly once; for even nn the omitted length must differ from n/2n/2, a condition the proof states (p. 5) and the abstract omits. Conjecture 1, quoted (p. 3): "Given nn and tt lengths lil_i, 1≤l1<l2<⋯<lt≤n−11\le l_1<l_2<\cdots<l_t\le n-1, of directed diagonals within an nn-gon such that ∑i=1tli≢0(modn)\sum_{i=1}^tl_i\not\equiv0\pmod n. Then there exists a directed path within the nn-gon using each of the given lengths exactly once (and no vertex twice)." The length of a directed diagonal is "the number of sides of the nn-gon between the starting and the end vertex counted in a fixed direction", so sides count as diagonals of length 11 or n−1n-1, and a directed path is a chain (d1,…,dt)(d_1,\ldots,d_t) of directed diagonals, each beginning where the previous one ends. The reformulation, quoted: "In other words, it is conjectured that for any subset of {1,2,…,n−1}\{1,2,\ldots,n-1\} with the sum of its elements ≢0(modn)\not\equiv0\pmod n there exists a permutation of the elements of this subset such that no set of consecutive elements in this permutation has sum ≡0(modn)\equiv0\pmod n." Example (p. 4): n=8n=8, subset {1,2,3,4,5,7}\{1,2,3,4,5,7\}, permutation (1,3,7,2,5,4)(1,3,7,2,5,4) (Fig. 1). Alspach's motivation, as the paper reports it: a proof of Conjecture 1 would shorten parts of the known proofs that complete graphs, and complete graphs with a 1-factor added or removed, decompose into cycles [1,3,4], and that complete symmetric digraphs decompose into directed cycles [2]. The authors' checks, quoted (p. 4): "We have checked that Conjecture 1 is true for t≤5t\le5 and by computer for n≤16n\le16." No detail of either check is printed. The paper then restricts itself to the two cases t=n−1t=n-1 and t=n−2t=n-2.
  • § 2, Conjecture 1 for t=n−1t=n-1 and n−2n-2 (pp. 4--10; the proof of Theorem 2 ends on p. 9 and the closing remark below runs on to p. 10, inside the section). Theorem 1 (p. 4, page image), quoted: "Conjecture 1 is true for t=n−1t=n-1." Its proof is three sentences, restated here: the only (n−1)(n-1)-subset of {1,…,n−1}\{1,\ldots,n-1\} has sum (n2)\binom n2, which is nonzero modulo nn exactly when nn is even, and for even nn the permutation (1,n−2,3,n−4,…,4,n−3,2,n−1)(1,n-2,3,n-4,\ldots,4,n-3,2,n-1) does what the conjecture asks; Fig. 2 draws the corresponding zigzag path for n=12n=12. The paper describes this construction as already known and presents Theorem 2 as the next small step toward the conjecture. Theorem 2 (p. 4, page image), quoted: "Conjecture 1 is true for t=n−2t=n-2." Proof, odd nn (p. 4, page image): the paper first builds a directed cycle that uses each of the lengths 1,2,…,n−11,2,\ldots,n-1 exactly once, the permutation (lengths modulo nn) (1,−2,3,−4,…,(−1)(n+1)/2(n−1)/2,(−1)(n+1)/2(n−3)/2,…,4,−3,2,−1,(−1)(n−1)/2(n−1)/2)(1,-2,3,-4,\ldots,(-1)^{(n+1)/2}(n-1)/2,(-1)^{(n+1)/2}(n-3)/2,\ldots,4,-3,2,-1,(-1)^{(n-1)/2}(n-1)/2), with Fig. 3 for n=9n=9 and 1111; then (p. 5) "By deletion of the missing length a path with n−1n-1 given lengths is constructed." A filing observation, not a review verdict: the path obtained by deleting one diagonal from the cycle has n−2n-2 diagonals, the n−2n-2 given lengths, and the printed "n−1n-1" is read here as a slip. Proof, even nn (pp. 5--9, text layer for structure): for the omitted length xx the proof builds a path through all n−1n-1 lengths whose first diagonal has length xx, and dropping that first diagonal leaves the required path; it suffices to take x<n/2x<n/2, since reversing all directions turns a path starting with xx into one starting with n−xn-x, and (n2)−n/2≡0(modn)\binom n2-n/2\equiv0\pmod n excludes x=n/2x=n/2. For odd xx the proof is an induction on xx over (n,x)(n,x)-paths, "zigzag paths in an n1n_1-gon using all diagonal lengths exactly once, being invariant under rotation by π\pi, and starting with a diagonal of length x1x_1 which is parallel to the diagonal of length 1" (p. 6); the base is Fig. 2 for x=1x=1, Fig. 4 for x=3x=3, n=14+4sn=14+4s, and Fig. 5 for x=11x=11, n=28+12sn=28+12s, s≥0s\ge0; the step writes n=2(x+i)+(x+1)sn=2(x+i)+(x+1)s with s≥0s\ge0 and 1≤i≤(x+1)/21\le i\le(x+1)/2, takes an (n1,x1)(n_1,x_1)-path with n1=x−1n_1=x-1 and x1=ix_1=i or i+1i+1 by parity of ii (Fig. 6 when x1=n1/2x_1=n_1/2; when x1>n1/2x_1>n_1/2 the induction hypothesis gives the path by switching the directions), and assembles a starting block, ss periodic blocks of x+1x+1 vertices and the rotated image of the starting block (Figs. 7 and 8). The one exception, x=3x=3 and n=10n=10, is Fig. 9; the paper notes (p. 9) that a check of all cases finds no zigzag path for x=3x=3 and n=10n=10, which is why x=11x=11, n=28+12sn=28+12s needed its own base case. For even xx the (n+2,x+1)(n+2,x+1)-path just constructed has "the diagonals of lengths 1 and n−1n-1" (as printed) contracted, removing two vertices and lowering the remaining lengths by 11 (Fig. 10), with x=2x=2, n=8n=8 by Fig. 11. The proof closes on p. 9.
  • Closing remark of § 2 (pp. 9--10, page images). The paths constructed satisfy more than Conjecture 1 asks, and in general many more suitable paths exist; the paper's example is x=2x=2, n=8n=8, where only 33 paths use all lengths and start with 22, while 2626 paths for the subset {1,3,4,5,6,7}\{1,3,4,5,6,7\} satisfy the conjecture and admit no added diagonal of length 22.
  • Translation to the problem's notation. Number the vertices of the nn-gon by Zn\mathbb Z_n in the fixed direction; a directed diagonal of length ll from vv ends at v+lv+l, so a directed path (d1,…,dt)(d_1,\ldots,d_t) from v0v_0 visits vm=v0+smv_m=v_0+s_m with sm=∑k≤mdks_m=\sum_{k\le m}d_k, and "no vertex twice" says exactly that s0=0,s1,…,sts_0=0,s_1,\ldots,s_t are pairwise distinct modulo nn, equivalently that no block of consecutive elements sums to 00. Conjecture 1 is therefore Alspach's conjecture as Hicks, Ollis and Schmitt (Conjecture 1.1) and Costa and Pellegrini (Conjecture 1.1, posed there for every abelian group, here in Zn\mathbb Z_n) state it: a subset A⊆Zn∖{0}A\subseteq\mathbb Z_n\setminus\{0\} with nonzero sum has an ordering with pairwise distinct partial sums s0,…,sks_0,\ldots,s_k, that is, distinct and nonzero proper partial sums. The site's statement for Problem 475 (Graham's) asks only that s1,…,sts_1,\ldots,s_t be distinct, allows st=0s_t=0 and puts no condition on the sum. For n=pn=p an odd prime, Theorem 2 gives every (p−2)(p-2)-subset of Zp∖{0}\mathbb Z_p\setminus\{0\} (its sum is −x≠0-x\ne0, xx the missing element) an ordering with distinct nonzero partial sums, and Theorem 1 is vacuous, since the only (p−1)(p-1)-subset sums to 00. The odd-nn half of Theorem 2's proof is what Hicks, Ollis and Schmitt record as their Theorem 4.3, attributed to this paper ("Let nn be odd and take x∈Zn∖{0}x\in\mathbb Z_n\setminus\{0\}. Then the elements of Zn∖{0,x}\mathbb Z_n\setminus\{0,x\} can be ordered so that the partial sums are distinct and nonzero", their p. 12, text layer), and their p. 2 reports the two theorems as "Conjecture 1.1 is true whenever ∣A∣=n−1,n−2|A|=n-1,n-2". A reading made here, not a statement of the paper: the odd-nn permutation of p. 4 uses every element of Zn∖{0}\mathbb Z_n\setminus\{0\} once, its n−1n-1 vertices are distinct and it returns to its start, so its partial sums s1,…,sn−1s_1,\ldots,s_{n-1} are pairwise distinct with sn−1=0s_{n-1}=0; for n=pn=p this is a valid ordering of the whole of Zp∖{0}\mathbb Z_p\setminus\{0\} in the site's sense, the case t=p−1t=p-1 that the site and Erdős attribute to Graham.

Compiled scope

The paper is compiled at statement depth for the results Problem 475 consumes: Theorem 1 and Theorem 2 (p. 4), read on the page image and paged on theorem_1 and theorem_2. The one-line proof of Theorem 1 and the odd-nn half of the proof of Theorem 2 were read in full on the page images and their permutations checked for small parameters while filing; the even-nn induction was read in the text layer for structure only and its figures were not checked. The authors' checks for t≤5t\le5 and n≤16n\le16 are statements without printed detail. Nothing here is independently reviewed.

Bears on. #475: Theorem 2 (printed p. 4, PDF p. 2), "Conjecture 1 is true for t=n−2t=n-2", is the source of the size p−2p-2 in the site's range p−3≤t≤p−1p-3\le t\le p-1, which Hicks, Ollis and Schmitt's Theorem 4.6 completes with the size p−3p-3 and the implication of Archdeacon, Dinitz, Mattern and Stinson (not held) carries to the site's statement, except for the (p−3)(p-3)-sets of sum 00, which Alspach's conjecture leaves out (Hicks, Ollis and Schmitt set them aside, their p. 16). Theorem 1 (p. 4), "Conjecture 1 is true for t=n−1t=n-1", is the paper's size n−1n-1, and its proof says in which cases it has content: "(n2)\binom n2, which is ≢0(modn)\not\equiv0\pmod n only for nn even", so for every odd prime the theorem is vacuous and the site's case t=p−1t=p-1 remains Graham's, which the paper does not state; the reading recorded above, that the odd-nn cycle of Theorem 2's proof is such an ordering, is made here. The paper's own checks (t≤5t\le5; n≤16n\le16 by computer, p. 4) are superseded for the problem by Costa and Pellegrini's Proposition 4.2. The paper does not settle the problem; the page's status is unchanged.

Results.

  • Theorem 1 (p. 4): Conjecture 1 is true for t=n−1t=n-1; the only such subset has sum (n2)\binom n2, nonzero modulo nn only for even nn, where the zigzag permutation (1,n−2,3,n−4,…,4,n−3,2,n−1)(1,n-2,3,n-4,\ldots,4,n-3,2,n-1) is a directed path.
  • Theorem 2 (p. 4): Conjecture 1 is true for t=n−2t=n-2; for odd nn by the directed cycle through all n−1n-1 lengths with one diagonal deleted (pp. 4--5), for even nn by an induction on the fixed missing length (pp. 5--9).

No file of this source is held: no license on record permits its redistribution, and the card cites the edition it names above.