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Coppersmith phillips 1996 question erdos subsequence sums

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lemma_1_1: Coppersmith and Phillips's layer bound: a sequence of integers in [1,n] in which no sum of two adjacent elements is an element has at most 2n/3 + 3/2(log_4 n + 1) elements, the constant 2/3 being tight when only sums of an even number of adjacent elements are forbidden.

theorem_2_1: Coppersmith and Phillips's lower bound: for every n a sequence of 13n/24 − O(1) integers in [1,n], no one of which equals a sum of two or more consecutive members, built from Table 1's residue classes on twelve subintervals, improving Freud's 19n/36.

theorem_3_7: Coppersmith and Phillips's upper bound: a sequence of integers in [1,n] in which no sum of 2, 3 or 4 adjacent elements is an element has at most 2n/3 − ⌊n/512⌋ + 3 log_4 n − 1/2 elements, the published figure 1/512.


Don Coppersmith and Steven Phillips, On a Question of Erdös on Subsequence Sums, SIAM J. Discrete Math. 9 (1996), no. 2, 173--177, May 1996, DOI 10.1137/S0895480193244139 (the DOI is not printed; the first-page header reads "SIAM J. DISCRETE MATH. Vol. 9, No. 2, pp. 173--177, May 1996", with the copyright line "1996 Society for Industrial and Applied Mathematics" and the article number 002; the title prints the diaeresis "Erdös"); received by the editors February 8, 1993, accepted for publication in revised form April 5, 1995 (footnote, p. 173); the first author at the IBM T. J. Watson Research Center, the second at the Computer Science Department of Stanford University, partly supported by a National Science Foundation grant. Cited as [CoPh96] on the problem page. The edition cited is the publisher's version of record at https://doi.org/10.1137/S0895480193244139; no preprint or repository version is known here. Its two references (p. 177) are [1] Freud, Adding numbers, James Cook Mathematical Notes 6 (1993), 6199--6202, filed as freud_1993_adding_numbers_problem_p, and [2] Erdős, Problem 91:02, in Western Number Theory Problems, R. Guy, ed., "presented December 19, 22, 1992" as printed, not held; the paper does not cite the 1992 Hardy--Ramanujan Journal survey that is the problem page's [Er92c].

The copy read for this card is the publisher's production PDF of the printed article: 5 pages, printed pp. 173--177 = PDF pp. 1--5 (printed p. nn is PDF p. n−172n-172), a scan of the printed pages with a text layer that reads the prose cleanly and garbles the mathematics (the properties SkS_k, floors, subscripts and the entries of Table 1 come out as scattered characters; the file's metadata records the journal title and the citation and no creation date), each page carrying the publisher's download watermark down the left margin (the download date, the downloading machine's address and the license notice; text layer and page images of all five pages). Provenance: obtained from the publisher on 2026-09-22 as a DRM-free production PDF through the library's acquisition, from https://doi.org/10.1137/S0895480193244139; 644,108 bytes. The file prints "© 1996 Society for Industrial and Applied Mathematics" in the header of its first page (printed p. 173) and "Redistribution subject to SIAM license or copyright; see https://epubs.siam.org/terms-privacy" in the download watermark down the left margin of every page, every other right reserved.

Read status: claims checked for the abstract, the definitions of § 1 (the 00/11/−- strings, property SkS_k, layers, forced and unforced 00's), Lemma 1.1 with its proof and the tightness remark (p. 173), Theorem 2.1 and Table 1 (p. 174), Lemma 3.1 (p. 175), Theorem 3.7 (p. 177), the conclusion with Open Question 1 and the two references (p. 177), each read clause by clause on the page images of PDF pp. 1--5 on 2026-09-22; Table 1's twelve row values and their total 13/2413/24 were recomputed here from the printed fractions. The proof of Theorem 2.1 (p. 174, half a page of prose plus the table) was read in full on the page image and its boundary argument was followed and not checked; the proof paragraph of Theorem 3.7 (p. 177) was read in full on the page image and its assembly of Lemmas 3.3, 3.4, 3.6 and 3.1 was followed and not checked; Lemmas 3.2--3.6 with the case analysis of Lemma 3.3 (pp. 175--177) were read on the page images for structure only, and none of their cases was checked. Nothing here is independently reviewed.

Contents

  • Abstract (p. 173, page image). The abstract poses Erdős's question as the density a sequence of integers can have when no member is the sum of a consecutive subsequence: an increasing sequence ⟨x1,…,xm⟩\langle x_1,\ldots,x_m\rangle of integers in [1,n][1,n] with no indices 0<i<j<k≤m0<i<j<k\le m for which xi+xi+1+⋯+xj=xkx_i+x_{i+1}+\cdots+x_j=x_k, and the question (quoted) whether "m>n/2+1m>n/2+1 is possible". It reports that a simple argument rules out m>2n/3+O(log⁡n)m>2n/3+O(\log n), that Freud recently constructed a sequence with m=19n/36m=19n/36, and that the note constructs one with m=13n/24−O(1)m=13n/24-O(1) and sharpens the simple upper bound to rule out m>(2/3−ϵ)n+(log⁡n)m>(2/3-\epsilon)n+(\log n) for ϵ=1/512\epsilon=1/512 (the abstract's expression as printed). Key words: sequence, integers, density, extremal problem (printed "external problem"); AMS classifications 05D05, 11B05. The forbidden sums run over blocks xi,…,xjx_i,\ldots,x_j of j−i+1≥2j-i+1\ge2 consecutive members equal to a later member xkx_k; since i<ji<j, every block has at least two members, so this is the problem's condition that no member is a sum of two or more consecutive members.
  • § 1, Preliminaries (p. 173, page image). A subinterval of [1,n][1,n] is described by a string over 11 (an element xix_i), 00 (a nonelement) and −- (either). "Property SkS_k says that the sum of kk adjacent elements is not an element. For a nonnegative integer ii, layer ii is all integers in the interval (n/2i+1,n/2i](n/2^{i+1},n/2^i]". A nonelement (00) is called forced when two adjacent elements add to it, and unforced when none do. Layer 00 by itself gives the trivial lower bound n/2n/2, and the paper attributes to Erdős ([2]) the question whether m>n/2+1m>n/2+1 can occur. Lemma 1.1 (quoted): "A sequence of integers in [1,n][1,n] satisfying S2S_2 contains at most 2n/3+3/2(log⁡4n+1)2n/3+3/2(\log_4n+1) elements." Proof: by S2S_2 the sums of adjacent pairs in layer 2i+12i+1 are distinct nonelements of layer 2i2i, so the two layers together hold at most 1+⌊n/22i⌋−⌊n/22i+1⌋≤3/2+n/22i+11+\lfloor n/2^{2i}\rfloor-\lfloor n/2^{2i+1}\rfloor\le3/2+n/2^{2i+1} elements, summed over 0≤i≤⌊log⁡4n⌋0\le i\le\lfloor\log_4n\rfloor. This is the layer argument the problem page's site commentary credits to Sarosh Adenwalla. The paper remarks that the constant 2/32/3 of Lemma 1.1 cannot be lowered when only the properties SiS_i with ii even are required, the integers not divisible by 33 being such a sequence, the counterpart of Freud's remark that 2/32/3 is best possible when only ai=aj+aj+1a_i=a_j+a_{j+1} is forbidden. Paged on lemma_1_1.
  • § 2, Lower bound (p. 174, page image). Table 1, "The sequence proving the lower bound", lists twelve subintervals [an,bn][an,bn] with the residues kept modulo a modulus and each row's share of nn: [n/5,2n/9][n/5,2n/9] residues 0,1,2,5,6,8,10,11,14,15(mod16)0,1,2,5,6,8,10,11,14,15\pmod{16} (1/721/72); [2n/9,n/4][2n/9,n/4] all (1/361/36); [n/4,8n/27][n/4,8n/27] none; [8n/27,n/3][8n/27,n/3] residues 1,2,3(mod4)1,2,3\pmod4 (1/361/36); [n/3,3n/8][n/3,3n/8] residues 1,2(mod3)1,2\pmod3 (1/361/36); [3n/8,4n/9][3n/8,4n/9] residues 0,2,6,8,9,12,13,16,19,20,23,24,26,30(mod32)0,2,6,8,9,12,13,16,19,20,23,24,26,30\pmod{32} (35/115235/1152); [4n/9,n/2][4n/9,n/2] the even integers (1/361/36); [n/2,16n/27][n/2,16n/27] all (5/545/54); [16n/27,2n/3][16n/27,2n/3] residues 1,2,4,6,7(mod8)1,2,4,6,7\pmod8 (5/1085/108); [2n/3,3n/4][2n/3,3n/4] residues 1,2(mod3)1,2\pmod3 (1/181/18); [3n/4,8n/9][3n/4,8n/9] all residues mod 6464 except 2,8,14,17,21,25,29,35,39,43,47,50,56,622,8,14,17,21,25,29,35,39,43,47,50,56,62 (125/1152125/1152); [8n/9,n][8n/9,n] residues 0,1,3(mod4)0,1,3\pmod4 (1/121/12); "density of elements achieved is 0.541666…0.541666\ldots", and the twelve shares sum to 13/2413/24 (recomputed here). The paper credits the idea to patterns in sequences that J. H. Davenport found experimentally and communicated privately. Theorem 2.1 (quoted): "For any nn there is a sequence of 13n/24−O(1)13n/24-O(1) integers in [1,n][1,n], none of which is the sum of a consecutive subsequence." The proof starts from Freud's construction ([1]) of m≥19n/36m\ge19n/36 as the motivation for the new one, rederives Freud's blocks in the paper's own terms (all integers between 2n/92n/9 and n/4n/4; the even integers between 4n/94n/9 and n/2n/2; the residues 0,1,3(mod4)0,1,3\pmod4 between 8n/98n/9 and nn; the residues 1,2(mod3)1,2\pmod3 between n/3n/3 and 3n/83n/8, whose pair sums excise the multiples of 33 between 2n/32n/3 and 3n/43n/4; the ranges [3n/4,8n/9][3n/4,8n/9] and [3n/8,4n/9][3n/8,4n/9] then filled in any complementary way, the paper's word, with nothing further specified), then adds integers between n/5n/5 and 2n/92n/9 and between 8n/278n/27 and n/3n/3 chosen so that their triples land on integers already excluded, and closes: sums within one interval are nonelements by the table; a sum spanning an interval boundary that lands on an element removes that element (the larger one), which can disturb only sums spanning the gap it leaves, and the paper asserts that only a constant number of elements are removed this way, since each removal acts forward and never back. No count of the eliminated elements is printed. Paged on theorem_2_1.
  • § 3, Upper bound (pp. 175--177, page images). The plan: property S3S_3 applied to elements in [3n/16,n/4][3n/16,n/4] forces at least ϵn\epsilon n unforced 00's, each of which lowers Lemma 1.1's count by one. Lemma 3.1 (p. 175, quoted): "A sequence of integers in [1,n][1,n] satisfying S2S_2 and having kk unforced 00's in even layers contains at most 2n/3−k+3/2(log⁡4n+1)2n/3-k+3/2(\log_4n+1) elements." Lemma 3.2 (p. 175, quoted): "1. 0000 cannot be forced. 2. [2y,2y+2]=010[2y,2y+2]=010 cannot be forced. 3. [2y+1,2y+3]=010[2y+1,2y+3]=010 is forced only if [y,y+2]=111[y,y+2]=111." Lemma 3.3: for y∈[3n/64+2,n/16−3]y\in[3n/64+2,n/16-3] there is a 010010 centered in [y−1,y+2][y-1,y+2] or [3y,3y+3][3y,3y+3], or an unforced 00 in one of [y−2,y+3][y-2,y+3], [3y−2,3y+5][3y-2,3y+5], [4y−1,4y+5][4y-1,4y+5], [12y+2,12y+10][12y+2,12y+10] (six cases A--F over Table 2, pp. 175--176). Lemma 3.4 (p. 176, quoted): "A forced 010010 centered at yy implies a forced 010010 centered at y/4y/4 (implying yy is a multiple of 44) or an unforced 00 in the interval [⌊y/4⌋−1,⌈y/4⌉+1][\lfloor y/4\rfloor-1,\lceil y/4\rceil+1]." Lemma 3.5: kk forced 010010's in layer 2i2i give, for some mm, mm forced 010010's and at least max⁡{(k−m−6)/4,0}\max\{(k-m-6)/4,0\} unforced 00's in layer 2i+22i+2. Lemma 3.6: k>0k>0 forced 010010's in layer 2i2i give at least k/4−(3/2)log⁡4n+3i/2k/4-(3/2)\log_4n+3i/2 unforced 00's in even layers in [1,n/22i+2][1,n/2^{2i+2}]. Theorem 3.7 (p. 177, quoted): "A sequence of integers in [1,n][1,n] satisfying S2S_2, S3S_3, and S4S_4 contains at most 2n/3−⌊n/512⌋+3log⁡4n−1/22n/3-\lfloor n/512\rfloor+3\log_4n-1/2 elements." Its proof counts ⌊n/64⌋−5\lfloor n/64\rfloor-5 values of yy, at most 66 sharing an unforced 00 and at most 22 sharing a forced 010010, and minimizes over mm at m=⌊n/128⌋−2m=\lfloor n/128\rfloor-2 to get ⌊n/512⌋−(3/2)log⁡4n+2\lfloor n/512\rfloor-(3/2)\log_4n+2 unforced 00's in even layers, then applies Lemma 3.1. Paged on theorem_3_7.
  • § 4, Conclusion (p. 177, page image). With m(n)m(n) the length of the longest such sequence in [1,n][1,n], the paper notes that its results show neither trivial bound, m(n)/n≥1/2m(n)/n\ge1/2 below and m(n)/n≤2/3+o(1)m(n)/n\le2/3+o(1) above, to be tight, and expects that neither of its own bounds is tight either. Open Question 1 (quoted): "What is the value of lim inf⁡m(n)/n\liminf m(n)/n? Alternatively, what is the largest constant α\alpha such that for any nn, there is a sequence of αn−O(n)\alpha n-O(n) integers in [1,n][1,n], none of which is the sum of a consecutive subsequence?" (the second form prints O(n)O(n), where Theorem 2.1 reads O(1)O(1); a filing observation, not a review verdict). The infinite sequence questions of Problem 839 (lower and logarithmic density) are not treated.

Compiled scope

The paper is compiled at statement depth for the three results the citing problem consumes: Lemma 1.1 (p. 173), Theorem 2.1 (p. 174) and Theorem 3.7 (p. 177), read on the page images with Lemma 3.1 and Table 1, and paged on lemma_1_1, theorem_2_1 and theorem_3_7. Table 1's total was recomputed; no proof was checked, and nothing is independently reviewed.

Bears on. #867: Theorem 2.1 (printed p. 174, PDF p. 2), "For any nn there is a sequence of 13n/24−O(1)13n/24-O(1) integers in [1,n][1,n], none of which is the sum of a consecutive subsequence", is the refereed lower bound the site records as 1324N−O(1)≤∣A∣\tfrac{13}{24}N-O(1)\le|A|; since 13n/24−O(1)−n/2=n/24−O(1)→∞13n/24-O(1)-n/2=n/24-O(1)\to\infty, it is itself a disproof of the problem's ∣A∣≤N/2+O(1)|A|\le N/2+O(1), alongside Freud's construction of density 19/3619/36, which the paper cites as its [1] and builds on. Theorem 3.7 (printed p. 177, PDF p. 5), "A sequence of integers in [1,n][1,n] satisfying S2S_2, S3S_3, and S4S_4 contains at most 2n/3−⌊n/512⌋+3log⁡4n−1/22n/3-\lfloor n/512\rfloor+3\log_4n-1/2 elements", is the source of the site's upper bound (23−1512)N+log⁡N(\tfrac23-\tfrac1{512})N+\log N: it gives the density 23−1512\tfrac23-\tfrac1{512} with an error of order log⁡N\log N, while the site's form read literally is smaller than the printed bound for every N≥2N\ge2 (3log⁡4N−123\log_4N-\tfrac12 exceeds the natural logarithm log⁡N\log N from N=2N=2 on); its hypotheses (no sum of 22, 33 or 44 adjacent elements is an element) are weaker than the problem's condition, so it applies to every set the problem admits. The published figure is 1/5121/512; the paper nowhere prints the 1/35841/3584 that Freud's note reports for the pair's upper bound, which settles the site-versus-source difference the problem page recorded in favor of the site's figure. Lemma 1.1 (p. 173), "A sequence of integers in [1,n][1,n] satisfying S2S_2 contains at most 2n/3+3/2(log⁡4n+1)2n/3+3/2(\log_4n+1) elements", is the layer argument for the upper bound (23+o(1))N(\tfrac23+o(1))N the site credits to Adenwalla, with an explicit error term; it bounds the problem's sets from above and does not decide the problem. The abstract restates Erdős's question as "if m>n/2+1m>n/2+1 is possible", and § 1 (p. 173) cites for it a Western Number Theory Problems entry ([2]) rather than the problem page's [Er92c]. Open Question 1 (p. 177) leaves the exact value of lim inf⁡m(n)/n\liminf m(n)/n open between 13/2413/24 and 2/3−1/5122/3-1/512, which is not the site's question.

Results.

  • Theorem 2.1 (p. 174): for every nn a sequence of 13n/24−O(1)13n/24-O(1) integers in [1,n][1,n], no one of which equals a sum of two or more consecutive members, from Table 1.
  • Theorem 3.7 (p. 177): under S2S_2, S3S_3 and S4S_4 at most 2n/3−⌊n/512⌋+3log⁡4n−1/22n/3-\lfloor n/512\rfloor+3\log_4n-1/2 elements, from Lemma 3.1 (p. 175) and the unforced-zero count of Lemmas 3.2--3.6.
  • Lemma 1.1 (p. 173): under S2S_2 alone at most 2n/3+3/2(log⁡4n+1)2n/3+3/2(\log_4n+1) elements, its constant 2/32/3 tight for sequences required to satisfy only the SiS_i with ii even.
  • Open Question 1 (p. 177): the value of lim inf⁡m(n)/n\liminf m(n)/n; not paged.

No file of this source is held: no license on record permits its redistribution, and the card cites the edition it names above.