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Erdos freud 1984 disjoint sets differences

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counterexample_p100: Erdős and Freud's negative answer to the Erdős–Graham question of Problem 331: with A the integers whose binary expansion uses only even powers of two and B those using only odd powers, a_i − a_j = b_k − b_l has only the trivial solutions while both counting functions exceed (1/√2 − o(1))√x, the liminf of min{A(x), B(x)}/√x being exactly 1/√2.

theorem_4: Erdős and Freud's rigidity theorem for pairs A, B of integer sequences whose differences coincide only trivially: if both counting functions stay above a positive multiple of √x, neither A(x)/√x nor B(x)/√x can converge; it answers the variant of Problem 331 with A(x) ~ c_A √x and B(x) ~ c_B √x in the affirmative.


P. Erdős and R. Freud, On disjoint sets of differences, Journal of Number Theory 18 (1984), no. 1, 99--109, DOI 10.1016/0022-314X(84)90046-5; received 20 January 1982, communicated by H. Zassenhaus; Erdős at the Mathematical Institute of the Academy, Budapest, and Freud at the Department of Algebra and Number Theory, Eötvös Loránd University, Budapest (p. 99). Not a site key for Problem 331, whose page credits the counterexample to Ruzsa. Its three references (p. 109) are [1] Ajtai, Komlós and Szemerédi, A dense infinite Sidon sequence, European J. Combin. 2 (1981), 1--11; [2] Erdős and Graham, Old and New Problems and Results in Combinatorial Number Theory, Monographie No. 28 de L'Enseignement Mathématique, Genève, 1980 (the library card), the source of the question; and [3] Halberstam and Roth, Sequences, Oxford Univ. Press, 1966.

The copy read for this card is the scan of the printed article in the Rényi Institute's archive of Erdős's papers, https://users.renyi.hu/~p_erdos/1984-10.pdf: 11 pages, printed pp. 99--109 = PDF pp. 1--11 (printed p. nn is PDF p. n−98n-98), a 2004 OmniPage capture (the file's metadata) with an OCR text layer that locates passages but garbles the subscripts, radicals and most displays, so every statement below was read on the page images. The publisher's record is https://doi.org/10.1016/0022-314X(84)90046-5. The file prints "Copyright © 1984 by Academic Press, Inc. All rights of reproduction in any form reserved." in the footer of p. 99, every other right reserved; the archive's site footer speaks for the site, not the paper ("(C) 2005-2007 All rights reserved. All material on this site is for scientifics [sic] purposes only.", https://users.renyi.hu/~p_erdos/).

Read status: claims checked for the abstract and introduction with the quoted question of [2, p. 50] and the counterexample (pp. 99--100), the notation SPSP, IPIP, SNSN, ININ, SXSX, IXIX with the values for the example (pp. 100--101), Theorems 1--4 (pp. 101--102), the generalized construction (∗)(*) (p. 102), the proof of Theorem 4 and the closing remarks (25)--(26) (pp. 108--109), each read clause by clause on the page images on 2026-10-07; the counterexample's verification and the proof of Theorem 4 were followed; the proofs of Theorems 1--3 (pp. 102--108) were read in the text layer for structure only. Nothing here is independently reviewed.

Contents

  • Introduction (pp. 99--100, page images). A Sidon sequence has all differences ai−aja_i-a_j (i≠ji\ne j) distinct, and Erdős's result (i) is recalled: for a Sidon sequence lim inf⁡A(x)/x=0\liminf A(x)/\sqrt x=0, moreover lim inf⁡A(x)/x/log⁡x<∞\liminf A(x)/\sqrt{x/\log x}<\infty, where A(x)A(x) counts the elements of AA up to xx. The question, quoted from [2, p. 50]: "Let A={a1<a2<⋯ }A=\{a_1<a_2<\cdots\} and B={b1<b2<⋯ }B=\{b_1<b_2<\cdots\} be sequences of integers satisfying A(x)>εx1/2A(x)>\varepsilon x^{1/2}, B(x)>εx1/2B(x)>\varepsilon x^{1/2} for some ε>0\varepsilon>0. Is it true that ai−aj=bk−bla_i-a_j=b_k-b_l (1) has infinitely many solutions?" The authors say it had seemed likely that splitting a Sidon sequence into two parts could not raise the density much, and that the situation changes dramatically. The counterexample (p. 100): AA the numbers whose binary expansion uses only even powers of two, BB those using only odd powers; (1) is equivalent to ai+bl=aj+bka_i+b_l=a_j+b_k (2), which by the uniqueness of binary expansion has only trivial solutions, while lim inf⁡min⁡{A(x),B(x)}/x=1/2\liminf\min\{A(x),B(x)\}/\sqrt x=1/\sqrt2, the worst case being just before a new digit appears in BB, B(22s−1−1)=2s−1∼2−1/222s−1−1B(2^{2s-1}-1)=2^{s-1}\sim2^{-1/2}\sqrt{2^{2s-1}-1}; "This settles the original question in the negative (for ε=1/2\varepsilon=1/\sqrt2)." Paged at counterexample_p100.
  • Notation (pp. 100--101). For AA, BB with (1) having only trivial solutions: SPSP and IPIP are the lim sup⁡\limsup and lim inf⁡\liminf of A(x)B(x)/xA(x)B(x)/x; SNSN and ININ those of min⁡{A(x),B(x)}/x\min\{A(x),B(x)\}/\sqrt x; SXSX and IXIX those of max⁡{A(x),B(x)}/x\max\{A(x),B(x)\}/\sqrt x. In the example SP=3/2SP=3/2, IP=1IP=1, SN=3/2SN=\sqrt3/\sqrt2, IN=1/2IN=1/\sqrt2, SX=3SX=\sqrt3, IX=1IX=1.
  • Theorem 1 (p. 101): the largest possible value of SPSP is 22; 1.1, for any function H(x)H(x) with lim sup⁡H(x)=∞\limsup H(x)=\infty there are AA, BB with A(x)B(x)≥2x−H(x)A(x)B(x)\ge2x-H(x) (3) for infinitely many integers xx; 1.2, this is best possible, since for any AA, BB, A(x)B(x)−2x→−∞A(x)B(x)-2x\to-\infty.
  • Theorem 2 (p. 101): 2.1, 52IP+2SP≤7\frac52IP+2SP\le7, in particular IP≤14/9IP\le14/9; 2.2, IP+32SP≤4IP+\frac32SP\le4, in particular SP=2SP=2 implies IP≤1IP\le1. Remark: the authors could not decide whether IP>1IP>1 is possible at all.
  • Theorem 3 (p. 101): 3.1, the largest possible value of SNSN is 2\sqrt2 and that of IXIX is ∞\infty; 3.2, IN>1/24−εIN>1/\sqrt[4]2-\varepsilon is attainable for any ε>0\varepsilon>0; 3.3, for any ε>0\varepsilon>0 there are AA, BB with SP>2−εSP>2-\varepsilon, IN>0IN>0 and SX<∞SX<\infty, but SP=2SP=2 implies IN=0IN=0 and SX=∞SX=\infty. Remark: by 2.1 and 3.2 the largest possible value of ININ lies between 1/241/\sqrt[4]2 and 14/9\sqrt{14/9}.
  • Theorem 4 (p. 102): if IN>0IN>0, then neither A(x)/xA(x)/\sqrt x nor B(x)/xB(x)/\sqrt x can tend to a limit. "We shall consider further generalizations in a next paper." Paged at theorem_4.
  • Proofs (pp. 102--109). The generalized construction (∗)(*) (p. 102, page image): for integers k1,k2,…>1k_1,k_2,\ldots>1, write the integers in the mixed radix with these digit bases; AA takes the numbers whose odd-position digits vanish and BB those whose even-position digits vanish, so (2) has only trivial solutions and IP=1IP=1 for every such pair, the binary example being k1=k2=⋯=2k_1=k_2=\cdots=2. Theorem 1 (pp. 102--103): the sums ai+bja_i+b_j with ai,bj≤xa_i,b_j\le x are distinct, which bounds A(x)B(x)A(x)B(x) by 2x2x; 1.2 from the distinctness of the differences ai−bka_i-b_k (5), 1.1 from (∗)(*) with a large k2sk_{2s}, or by an iterative translation construction. Theorem 3 (pp. 103--107): 3.1 and 3.2 from (∗)(*) with chosen bases, 3.2 best possible for that construction; 3.3 by an interval-counting argument on A(2x)B(2x)>(4−ε)xA(2x)B(2x)>(4-\varepsilon)x. Theorem 2 (pp. 107--108): counting the sums ai+bja_i+b_j in the intervals ((i−1)x,ix]((i-1)x,ix], i≤4i\le4, against the at most 4x4x differences with ∣ai−bj∣≤2x\lvert a_i-b_j\rvert\le2x. Theorem 4 (pp. 108--109, page images): paged at theorem_4. Closing remarks (p. 109): by similar methods, if lim inf⁡B(x)/x>0\liminf B(x)/\sqrt x>0 then for every ε>0\varepsilon>0 there is c>0c>0 with A(x(1+c))−A(x)<εxA(x(1+c))-A(x)<\varepsilon\sqrt x for infinitely many xx (25); the authors ask whether (25) can be replaced by the sum of the two increments being o(x)o(\sqrt x) (26), which they cannot prove.

Compiled scope

The paper is compiled at statement depth for the two results Problem 331 consumes: the counterexample of p. 100, whose two-line verification was followed, and Theorem 4 (p. 102), whose proof (pp. 108--109) was followed on the page images; both paged. Theorems 1--3 are recorded as statements read on the page images with their proofs read for structure only. Nothing here is independently reviewed.

Bears on. #331: the counterexample of p. 100 answers the problem's question in the negative, in the Erdős--Graham form the paper quotes (A(x)>εx1/2A(x)>\varepsilon x^{1/2}, B(x)>εx1/2B(x)>\varepsilon x^{1/2} for some ε>0\varepsilon>0), in the paper's words "for ε=1/2\varepsilon=1/\sqrt2"; it is the construction the site credits to Ruzsa, and the paper credits no one for it. Theorem 4 (p. 102) bears on the problem's hypothesis directly: counts ≫N1/2\gg N^{1/2} for both sets, for all large NN, is IN>0IN>0 in the paper's notation, and the theorem says that a pair with only trivial coincidences of differences and IN>0IN>0 has neither counting function asymptotic to a constant multiple of x\sqrt x; so under A(x)∼cAxA(x)\sim c_A\sqrt x and B(x)∼cBxB(x)\sim c_B\sqrt x with cA,cB>0c_A,c_B>0, the variant the problem's claim pages attribute to Ruzsa, the equation has infinitely many nontrivial solutions (a filing derivation recorded on the result page). The problem's A,B⊆NA,B\subseteq\mathbb N and the paper's sequences, which contain 00, differ by that element, which changes each count by one.

Results.

  • Counterexample (p. 100): the integers using only even, respectively only odd, powers of two; ai−aj=bk−bla_i-a_j=b_k-b_l has only trivial solutions and lim inf⁡min⁡{A(x),B(x)}/x=1/2\liminf\min\{A(x),B(x)\}/\sqrt x=1/\sqrt2.
  • Theorem 4 (p. 102): if IN>0IN>0, neither A(x)/xA(x)/\sqrt x nor B(x)/xB(x)/\sqrt x can tend to a limit.

No file of this source is held: no license on record permits its redistribution, and the card cites the edition it names above.