Research notes on every problem, and a library of the papers behind them. Built from the open erdos repository.
Updated
Statement
Construction (Section 5, p. 21; unnumbered). Let and
a well-intersecting family (Definition 1, p. 3: every two distinct members meet in a non-empty arithmetic progression) with . For each integer with , add to the three sets
and remove the two triples and . The resulting family is well-intersecting, and the paper computes
where is the paper's integer-part bracket. Hence
which exceeds for . The paper states (p. 21) that it had been conjectured that is an extremal family for ; the construction disproves that conjecture (abstract, p. 1, and p. 3).
A further family (p. 21). For the paper builds a well-intersecting family by adding to , for every , the nine-term progression with all of its subprogressions containing (16 new sets for each ) and leaving out the 16 triples that would violate the well-intersecting property, and states . It gives this as one of several equally good constructions, one that contains an arithmetic progression of length nine.
Source. Tibor Szabó, Intersection properties of subsets of integers, European J. Combin. 20 (1999), no. 5, 429--444, DOI 10.1006/eujc.1997.0176. Pages are those of the author's 23-page preprint identified on the source card, not of the journal edition: Section 5 on p. 21.
Read depth. Claims checked: the construction of and its count were read clause by clause on the page image. The paper gives no written check that is well-intersecting; as an observation of this page, not of the paper, an exhaustive pairwise check of for found every pairwise intersection a non-empty arithmetic progression and . The family was read but not checked. Nothing here is independently reviewed.
Proof pointer
Page 21. For each three sets enter and two leave, so each admissible adds one set; the sets entering for different have different common differences and are distinct. The two removed triples are exactly those of that meet one of the added four- or five-term sets in a non-progression.
Dependencies
None beyond Definition 1 of the same paper.
Bears on
- Problem 272: with the sets read as distinct, a lower bound on the problem's largest , which shows that the family of all sets of at most three elements through a fixed point does not attain it for . It does not give the exact value.