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Problem 272

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claims/: The 4 claim pages of Problem 272, one per claimant's result; the problem's standing derives from them.


Statement. Let N≥1N\geq 1. What is the largest tt such that there are A1,…,At⊆{1,…,N}A_1,\ldots,A_t\subseteq \{1,\ldots,N\} with Ai∩AjA_i\cap A_j a non-empty arithmetic progression for all i≠ji\neq j?

Formulation. The sets A1,…,AtA_1,\ldots,A_t are read as distinct, as Erdős and Graham, Simonovits and Sós, Szabó, Yang and the catalog's statement count them. Read as the site words it, the question allows repeats, and then no largest tt exists (take every Ai={1}A_i=\{1\}).

Status. Open, the site's label. The exact maximum t(N)t(N) is not known for general NN. The refereed bounds are recorded as accepted partial claims on the claim pages of Simonovits and Sós and Szabó, and Yang's reported exact values for 3≤N≤123\leq N\leq12 as a claimed partial claim on his. Szabó's linear-error question, whether t(N)=N2/2+O(N)t(N)=N^2/2+O(N) (the second of the two questions in Section 6 of his 1999 paper), has an affirmative Lean proof that the bounty site Conjectures.io verified on 9 September 2026 and approved; that settles a variant, not the catalog question, and is recorded as an accepted partial claim on its claim page (see Current assessment).

Source. erdosproblems.com/272, accessed 2026-09-04; on 2026-09-28 the page showed the label OPEN, which the site explains as not settled by any finite computation, no proof expositions, seven comments and no proof claims. The Conjectures.io record conjectures.io/results/c3277f4a-d573-42a9-bfca-e45fb2cb39ff showed on the same date: Lean Verified 9 September 2026; Approved in review 11 September 2026; Certified 14 September 2026; Reward Paid. Cite as: T. F. Bloom, Erdős Problem #272, https://www.erdosproblems.com/272.

References.

Formalization. Statement in formal-conjectures pinned to the main-branch commit of 2026-09-18, after the restatement of 2026-09-12. The catalog headline Erdos272.erdos_272 asks for the exact value of maxArithInterCard N for every N≥1N\geq1 with an open answer (restated to the exact maximum on 2026-09-12, PR #5807) and is research open; its variant Erdos272.erdos_272.variants.szabo_strong, (fun N ↦ (maxArithInterCard N - N ^ 2 / 2 : ℝ)) =O[atTop] fun N : ℕ ↦ (N : ℝ), is the statement the Conjectures.io proof establishes, which the catalog's default branch labels research open.

Current assessment

The site formulation asks for the exact largest t=t(N)t=t(N) for each N≥1N\geq1; on 2026-09-28 the page showed the label OPEN, which the site explains as not settled by any finite computation, seven comments from August and September 2025 (among them the computations of t(N)t(N) for N≤9N\leq9 described under Progress) and no proof claim. No source determines t(N)t(N) for general NN, so the site's label is open and every claim page of the problem is partial.

Best known progress. [Sz99] gives t(N)=N2/2+O(N5/3(log⁡N)3)t(N)=N^2/2+O(N^{5/3}(\log N)^3) and t(N)≥(N2)+⌊(N−1)/4⌋+1t(N)\geq\binom N2+\lfloor(N-1)/4\rfloor+1. Yang (arXiv:2607.23004, unrefereed preprint, 2026; card) reports t(N)t(N) exactly for 3≤N≤123\leq N\leq12 by computation and proves the upper bound (N2)+1+⌊(N−1)/4⌋\binom N2+1+\lfloor(N-1)/4\rfloor for every family with a common element, reducing his sharpened conjecture to Szabó's kernel question. A Lean proof accepted by the bounty site Conjectures.io (record c3277f4a-d573-42a9-bfca-e45fb2cb39ff; Conjectures.io's Lean kernel verified it, its review approved it on 11 September 2026 under its policy v2, it certified the record on 14 September 2026 and paid the bounty; solver shown as JenW1N; card; claim page JenW1N 2026) proves t(N)=N2/2+O(N)t(N)=N^2/2+O(N), the affirmative answer to Szabó's linear-error question, the second of the two questions in Section 6 of his 1999 paper.

The formal statement it verified is the catalog's Erdos272.erdos_272.variants.szabo_strong (FormalConjectures/ErdosProblems/272.lean at the catalog commit the bounty task pinned): with IsArithInterSet N A requiring A⊆P({1,…,N})A\subseteq\mathcal P(\{1,\ldots,N\}) and every pair of distinct members to intersect in a set that IsAPOfLength l for some l>0l>0 (the catalog's shared definition: exactly ll elements of the form a+nda+nd, n<ln<l, so nonempty, with one- and two-element sets counted as progressions, as the site's own (N2)+1\binom N2+1 example presumes), and maxArithInterCard N the attained supremum of ∣A∣|A|, the statement is t(N)−N2/2=O(N)t(N)-N^2/2=O(N) read clause for clause. This is a variant of the catalog question: it improves Szabó's error term to linear but gives neither the exact value nor the kernel conjecture; the bounty site's review note itself says that the approval concerns only the unrestricted linear-error asymptotic and asserts neither an exact extremal formula nor that every extremal family has a common element.

The accepted file proves theorem target : fcTypeOfName% "Erdos272.erdos_272.variants.szabo_strong" (its final theorem) from a lower bound (N2)+1\binom N2+1 and an upper bound (N2)+22051N\binom N2+22051N for all large NN, the latter by reducing any family with at least N2/2N^2/2 members, at a loss of at most 2048N2048N members, to a family with a common point or with a long common interval core, each bounded by (N2)+O(N)\binom N2+O(N) by private-witness and progression-matching counts.

The accepting body is Conjectures.io alone: its verification report records a static scan (no imports, axiom declarations, sorry, native_decide or unsafe options), "Statement unchanged", permitted axioms propext, Quot.sound, Classical.choice, "Lean kernel accepted" and a fresh isolated replay on 10 September 2026, with the second kernel not run, so that the verdict rests on one kernel implementation, and the review describes itself as a decision on eligibility that does not vouch for originality; there was no refereed publication, no write-up, no erdosproblems.com acceptance and no formal-conjectures catalog agreement (the erdosproblems.com forum carried no proof claim, and the catalog labeled the variant research open).

This corpus has not built or audited the proof file, so it gives no formalized evidence. The file's target, header and the reduction chain named above agree with Conjectures.io's statement; the 12,791-line file contains no sorry, axiom, native_decide, unsafe, implemented_by, extern, partial, opaque, set_option or import; its header declares no author and no AI system, and one comment says a lemma comes "from the third supplied proof". The catalog commit the bounty task pinned was not reachable in the catalog's repository on 2026-09-27; the default branch's szabo_strong statement is identical, and Conjectures.io's "source type hash matches" check is the evidence that the pinned statement agrees.

Search scope: erdosproblems.com (the page, its discussion thread and its proof-claims thread), the community database, conjectures.io (results listing, the record, its solution page and Lean download, the problem page and the papers directory), the conjectures-io task and contribution repositories, the formal-conjectures catalog (272.lean, its history, PR #5807 and issue #5632) and arXiv (searches for "Erdős Problem 272" and "arithmetic progression intersections": only Yang's preprint, v1 of 2026-07-25). Remaining gaps: t(N)t(N) for N≥13N\geq13 and Szabó's kernel conjecture; no proof of the problem has been compiled or independently reviewed by this corpus.

Provenance of the proof file. Conjectures.io serves the file at https://conjectures.io/results/c3277f4a-d573-42a9-bfca-e45fb2cb39ff/solution/download (600,125 bytes, 12,791 lines,); this corpus has not built it.

Progress

The asymptotic t(N)=(1/2+o(1))N2t(N)=(1/2+o(1))N^2 is Szabó's, with error O(N5/3(log⁡N)3)O(N^{5/3}(\log N)^3) [Sz99]; the Conjectures.io-accepted Lean proof of 2026 sharpens the error to O(N)O(N), which Szabó had asked for. The exact value is reported only for 3≤N≤123\leq N\leq12: computations posted on the site's discussion thread in August 2025 by Stijn Cambie (user StijnC, whom the site's commentary thanks) gave t(N)=4,7,12,17,23,30,39t(N)=4,7,12,17,23,30,39 for 3≤N≤93\leq N\leq9 and the formula (N2)+⌈N/4⌉\binom N2+\lceil N/4\rceil, verified for N≤9N\leq9 and, under the assumption that an extremal family contains a singleton, for 10≤N≤1410\leq N\leq14; Yang's unrefereed preprint of 2026 reports the same values and adds N=10,11,12N=10,11,12 (code unavailable). In that range t(N)t(N) equals Szabó's lower bound (N2)+1+⌊(N−1)/4⌋\binom N2+1+\lfloor(N-1)/4\rfloor; Yang proves that bound exact for families with a common element and conjectures it for every NN, which would follow from Szabó's kernel conjecture. Neither is settled. The thread computations have no claim page, since they are thread posts and not a dated manuscript; Yang's are recorded on his claim page.

Known Results

  • [SiSo81] Simonovits and Sós (card; claim page Simonovits and Sós 1981): t(N)≪N2t(N)\ll N^2, through Theorem 3's bound t(N)≤(π2/24+1/2+o(1))N2t(N)\leq(\pi^2/24+1/2+o(1))N^2; the Erdős–Graham candidate (all arithmetic progressions in {1,…,N}\{1,\ldots,N\} through a fixed element, about (π2/24)N2(\pi^2/24)N^2 sets) is not extremal, since all sets of at most three elements through a fixed element give (N2)+1\binom N2+1 admissible sets, which they conjectured optimal.
  • [GSS80] Graham, Simonovits and Sós (card): if empty intersections are allowed, the largest family has exactly (N3)+(N2)+(N1)+1\binom N3+\binom N2+\binom N1+1 members.
  • [Sz99] Szabó (card; claim page Szabó 1999): t(N)=N2/2+O(N5/3(log⁡N)3)t(N)=N^2/2+O(N^{5/3}(\log N)^3); the construction t(N)≥(N2)+⌊(N−1)/4⌋+1t(N)\geq\binom N2+\lfloor(N-1)/4\rfloor+1, refuting the Simonovits–Sós conjecture; asks whether t(N)=(N2)+O(N)t(N)=\binom N2+O(N) and whether every extremal family has a common element (the kernel question).
  • Yang (arXiv:2607.23004v1, 2026, unrefereed; card; claim page Yang 2026): t(N)=4,7,12,17,23,30,39,48,58,69t(N)=4,7,12,17,23,30,39,48,58,69 for N=3,…,12N=3,\ldots,12 by exhaustive computation (code unavailable; the values for N≤9N\leq9 had been posted on the site's discussion thread in August 2025), so Szabó's bound is exact there; Theorem 1.4: every family with a common element has at most (N2)+1+⌊(N−1)/4⌋\binom N2+1+\lfloor(N-1)/4\rfloor members; Conjecture 1.3: equality for every NN; Section 7: structural constraints on a putative non-starred extremal family.
  • Conjectures.io-accepted Lean proof (record c3277f4a-d573-42a9-bfca-e45fb2cb39ff; verified 2026-09-09, approved 2026-09-11, certified 2026-09-14; solver shown as JenW1N; card; claim page JenW1N 2026): t(N)=N2/2+O(N)t(N)=N^2/2+O(N), answering Szabó's linear-error question (the second of the two questions in Section 6 of his paper) affirmatively and improving his error term to linear. Route in the file: lower bound (N2)+1\binom N2+1 (from {1}\{1\} and all two- and three-element sets containing 11); for N≥N0N\geq N_0 any admissible family with at least N2/2N^2/2 members reduces, losing at most 2048N2048N members, to one with a common point (at most (N2)+20001N\binom N2+20001N members) or with a long common interval core (at most (N2)+20003N\binom N2+20003N), so t(N)≤(N2)+22051Nt(N)\leq\binom N2+22051N for N≥N0N\geq N_0 (big-O constant 3000030000 as Conjectures.io's record quotes it). Scope: linear-error asymptotic only; not the exact value, not the kernel conjecture; Conjectures.io-accepted, no refereed publication, no erdosproblems.com or catalog acceptance; the kernel check is the bounty site's, on a single kernel, and this corpus has not built the file.

Linked library material

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