Research notes on every problem, and a library of the papers behind them. Built from the open erdos repository.
Updated
Statement
Lemma 1 (p. 39). Let be a positive integer, let be a non-empty subset of , and let be an integer with . Then there are a set of non-negative integers with and , and a set , such that
The authors call it a combinatorial result "which is fundamental for all the results in this paper" (p. 39).
Proof pointer
P. 40, by pigeonhole: each -element subset of is sent to the set of differences of its elements from its least element, an -element subset of . Some difference set receives at least the stated number of subsets; their least elements form , and is that difference set together with .
Read depth
Claims checked: the statement was read clause by clause on the page image of the print, and the short proof was read in full; it is not independently verified.
Dependencies
None.
Used by
Theorem 1, Theorem 2, Theorem 3 and Theorem 5, through Lemmas 3 and 6.
Source. P. Erdős, C. L. Stewart and R. Tijdeman, Some diophantine equations with many solutions, Compositio Mathematica 66 (1988), 37--56; the edition read is named on the source card.
Bears on
No problem page of this corpus.