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Rotkiewicz 1964 nombres naturels n k pseudopremiers

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theorem_1: Rotkiewicz's theorem that the least integer k above 1 for which some pseudoprime n has kn also a pseudoprime is k = 23, attained by n = 89 * 683 = 60787 and kn = 1398101.

theorem_2: Rotkiewicz's theorem that for coprime natural numbers a and b and any natural number k there are a prime p congruent to b mod a and k pseudoprimes n_i congruent to 1 mod a such that each p n_i is a pseudoprime congruent to b mod a.


A. Rotkiewicz, Sur les nombres naturels n et k tels que les nombres n et nk sont à la fois pseudopremiers, Atti Accad. Naz. Lincei Rend. Cl. Sci. Fis. Mat. Nat. (8) 36 (1964), no. 6, 816--818 (note presented by W. Sierpiński at the session of 10 June 1964).

The copy read for this card is the bdim (Biblioteca Digitale Italiana di Matematica) digitization: a bdim cover sheet (PDF p. 1; it misspells "sont" as "soni") followed by the three printed pages 816--818 (PDF p. nn is printed p. 814+n814+n), a scan whose OCR text layer garbles the formulas; the statements below were read on the page images. Provenance: a survey download of September 2026; the cover sheet names the record http://www.bdim.eu/item?id=RLINA_1964_8_36_6_816_0; 354,579 bytes. Read status: claims checked for Théorèmes 1 and 2 and Lemmes 1 and 2 (statements read on the page images); the proofs were followed for structure only and nothing was verified. The file prints the digitizer's notice on its bdim cover sheet (PDF p. 1), "L'utilizzo e la stampa di questo documento digitale è consentito liberamente per motivi di ricerca e studio. Non è consentito l'utilizzo dello stesso per motivi commerciali. Tutte le copie di questo documento devono riportare questo avvertimento.", a research-and-study grant that forbids commercial use and names no license, every other right reserved.

Contents

A pseudoprime is a composite nn with n∣2n−2n\mid 2^n-2.

  • Théorème 1 (p. 816; proof pp. 816--817): the least integer k>1k>1 for which there is a pseudoprime nn with knkn also pseudoprime is k=23k=23; the corresponding numbers are n=89⋅683=60787n=89\cdot683=60787 and kn=23⋅89⋅683=1398101kn=23\cdot89\cdot683=1398101. The proof uses Lemme 1 to exclude 1<k≤101<k\le10 and k=13,14,18k=13,14,18, for which no pseudoprime divides 2k−22^k-2; it excludes k=12,16,20k=12,16,20 because then 4∣kn4\mid kn and no pseudoprime is divisible by 4; for k=11,15,17,19,21,22k=11,15,17,19,21,22 it lists the pseudoprime divisors nn of 2k−22^k-2 and checks that no knkn is a pseudoprime. For k=21k=21 the list gives only 11⋅3111\cdot31; a computation made for this card finds a second pseudoprime divisor of 221−22^{21}-2, namely 11⋅31⋅41=1398111\cdot31\cdot41=13981, but 21⋅1398121\cdot13981 is not a pseudoprime either, so the theorem stands.
  • Théorème 2 (p. 816; proof p. 818): for coprime natural numbers a,ba,b and any natural number kk there are a prime pp and natural numbers n1,…,nkn_1,\dots,n_k with p≡b(moda)p\equiv b\pmod a, each nin_i a pseudoprime with ni≡1(moda)n_i\equiv1\pmod a, and each pnipn_i a pseudoprime with pni≡b(moda)pn_i\equiv b\pmod a. The proof takes pp in a progression amq2x+ramq^2x+r and applies Lemme 2, whose proof uses Zsigmondy's theorem [3] and Lemme 1 of [2], a note of the author with A. Schinzel (see also [1]); infinitely many such primes pp satisfying condition (5) of Lemme 2 are obtained as in the proof of Lemme 2 of the author's note [1].
  • Lemme 1 (p. 816): if nn and knkn are pseudoprimes then n∣2k−2n\mid 2^k-2. Stated with Théorème 1 on its result page.
  • Lemme 2 (p. 817): let p,qp,q be primes and m1,…,mk+2m_1,\dots,m_{k+2} distinct natural numbers dividing mm, and suppose (3) m∣p−1m\mid p-1 and ((p−1)/m,m)=1((p-1)/m,m)=1; (4) q2∣p−1q^2\mid p-1 and ma φ(ma)∣q−1ma\,\varphi(ma)\mid q-1; (5) (p−1)/m=q1α1⋯qsαs(p-1)/m=q_1^{\alpha_1}\cdots q_s^{\alpha_s} with q1<⋯<qsq_1<\dots<q_s and q1α1⋯qs−1αs−1∤qs−1q_1^{\alpha_1}\cdots q_{s-1}^{\alpha_{s-1}}\nmid q_s-1. Then each ni=f(p−1)/mi(2) f(p−1)/mi+1(2)n_i=f_{(p-1)/m_i}(2)\,f_{(p-1)/m_{i+1}}(2) with 1≤i≤k+11\le i\le k+1 is a pseudoprime with ni≡1(moda)n_i\equiv1\pmod a, where fn(2)=∏i∣n(2i−1)μ(n/i)f_n(2)=\prod_{i\mid n}(2^i-1)^{\mu(n/i)}; the lemma does not introduce aa, which in its use is the modulus of Théorème 2. Stated with Théorème 2 on its result page.

The note contains no statement about the greatest prime factors of nn and n+1n+1. The discussion of problem 649 on erdosproblems.com attributes to its reference [Ro64b] the statement that for every prime p>13p>13 there is a prime q>pq>p dividing 2p−1−12^{p-1}-1; that statement is not among this note's theorems and lemmas, and the attribution was not traced further.

Compiled scope

All three printed pages were read on the page images; the statements above were checked there, and the proofs were followed for structure only. Nothing here is independently reviewed.

Bears on. #649: listed in the problem's references; the note's own results concern pseudoprimes nn and knkn and pseudoprimes in residue classes, not the pattern P(n)=pP(n)=p, P(n+1)=qP(n+1)=q, and the divisor property attributed to it in the problem's site discussion was not found in it. Neither Théorème 1 (p. 816) nor Théorème 2 (p. 816) bears on the problem.

No file of this source is held: no license on record permits its redistribution, and the card cites the edition it names above.