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Squares from blocks of consecutive integers: a problem of Erdős and Graham

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lemma_2_1: Bennett and Van Luijk's lemma that, for a positive squarefree integer D < 100, the equation 2(4t^2+t-4) = Ds^2 has infinitely many solutions in positive integers s and t exactly when D is one of 5, 7, 13, 37, 47, 58, 67, 73, 83 and 97.

theorem_1_1: Bennett and Van Luijk's theorem that for every r >= 5 there are infinitely many tuples (n_1, ..., n_r, x) of positive integers with f(n_1,5)...f(n_r,5) = x^2 and n_j + 5 <= n_{j+1}, where f(n,k) is the product of the k consecutive integers starting at n.


Bennett, Michael A. and Van Luijk, Ronald, Squares from blocks of consecutive integers: a problem of Erdős and Graham. Indag. Math. (N.S.) 23 (2012), 123--127. The copy read for this card is the authors' six-page manuscript, paged 1--6 rather than with the journal's page numbers; it prints no notice. The publisher's page for the journal version could not be read on 2026-10-02 (DOI 10.1016/j.indag.2011.11.002), and its Crossref record lists only Elsevier's text-and-data-mining and open-archive user licenses, which govern the version of record, not this file; the term is unstated. Labels and pages on this card and its result pages are the manuscript's.

With f(n,k)=n(n+1)⋯(n+k−1)f(n,k)=n(n+1)\cdots(n+k-1), Erdős and Graham asked whether equation (1), ∏j=1rf(nj,kj)=x2\prod_{j=1}^r f(n_j,k_j)=x^2, has, for fixed r≥1r\geq1 and fixed k1,…,krk_1,\ldots,k_r with every kj≥4k_j\geq4, at most finitely many solutions in positive integers (n1,…,nr,x)(n_1,\ldots,n_r,x) with nj+kj≤nj+1n_j+k_j\leq n_{j+1} for 1≤j≤r−11\leq j\leq r-1, condition (2) (p. 1). Theorem 1.1 (p. 2) answers this in the negative for blocks of length five: if r≥5r\geq5 and ki=5k_i=5 for all ii, there are infinitely many (r+1)(r+1)-tuples of positive integers (n1,…,nr,x)(n_1,\ldots,n_r,x) satisfying (1) and (2).

The authors say it is unclear whether the polynomial-identity and Pell-equation argument that Bauer and Bennett used for blocks of length four extends to blocks of length five or more (p. 2). They instead look for four polynomials pi(t)∈Z[t]p_i(t)\in\mathbb Z[t] with pi(t)≠pj(t)+kp_i(t)\neq p_j(t)+k for 1≤i,j,k≤41\leq i,j,k\leq4, i≠ji\neq j, whose product of five-term blocks is g(t)h(t)2g(t)h(t)^2 with deg⁡g≤2\deg g\leq2 (equation (4), p. 2), and find one family with g(t)=2(4t2+t−4)g(t)=2(4t^2+t-4) (p. 4). Since g(t)g(t) is never a square modulo 2525, they solve g(t)=Ds2g(t)=Ds^2 instead (Lemma 2.1, p. 4: for positive squarefree D<100D<100 there are infinitely many positive solutions exactly for ten values of DD), attach fixed blocks with product Dy2Dy^2 for r∈{5,6,7,9,10,11,12}r\in\{5,6,7,9,10,11,12\}, and induct from r−8r-8 (p. 5). The authors note that Ulas suggested infinitely many solutions whenever rr exceeds a constant depending only on max⁡iki\max_i k_i (pp. 1--2), that they know of no solution with all ki=5k_i=5 and r≤3r\leq3 while r=4r=4 has many, and that their techniques appear unlikely to work for blocks of length six or more (pp. 5--6).

Source: https://personal.math.ubc.ca/~bennett/publ.html.

Read status: claims checked for Theorem 1.1 and Lemma 2.1, read clause by clause on the page images of the manuscript; the proof of Theorem 1.1 was followed and rests on Lemma 2.1, whose proof the paper only sketches. A search made for this corpus found solutions of Lemma 2.1's equation for D=5,13,58,97D=5,13,58,97 only with tt negative, against the lemma's "positive integers ss and tt"; such tt still give positive tuples for Theorem 1.1 (see its page). Nothing here is independently reviewed.

Bears on. #363: Theorem 1.1 (p. 2) gives, for each fixed r≥5r\geq5, infinitely many collections of rr disjoint blocks of five consecutive positive integers with square product, which the paper presents as a negative answer to Erdős and Graham's finiteness question for blocks of five.

Results.

  • Theorem 1.1 (p. 2): for r≥5r\geq5 and all ki=5k_i=5, there are infinitely many (r+1)(r+1)-tuples of positive integers satisfying (1) and (2).
  • Lemma 2.1 (p. 4): for positive squarefree D<100D<100, the equation 2(4t2+t−4)=Ds22(4t^2+t-4)=Ds^2 has infinitely many solutions in positive integers exactly when D∈{5,7,13,37,47,58,67,73,83,97}D\in\{5,7,13,37,47,58,67,73,83,97\}.

No file of this source is held: no license on record permits its redistribution, and the card cites the edition it names above.