Research notes on every problem, and a library of the papers behind them. Built from the open erdos repository.
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Statement
Notation as on the Theorem 1 page: prime, , subintervals of lengths and , the pairwise disjoint.
Corollary (p. 2, unnumbered). Suppose . Then some has integers , with , provided and .
The paper presents it (p. 2) as what a larger buys: it comes closer to what Hooley's conjectured bound for incomplete Kloosterman sums (p. 1; the print writes there for the modulus) would give for a single pair, namely both lengths .
A remark on the constants, of this page, not of the paper. The print gives no proof beyond placing the corollary after Theorem 1, and names no constants. Disjoint subintervals of of length number fewer than , so the hypothesis can hold only with an implied constant below . Substituting the thresholds in Theorem 1 needs with Theorem 1's constant . The corollary therefore follows from Theorem 1 when the thresholds on and carry suitable constant factors (for instance , and ), not with the literal thresholds for every implied constant.
Source. T. D. Browning and A. Haynes, Incomplete Kloosterman sums and multiplicative inverses in short intervals, Int. J. Number Theory 9 (2013), 481–486; read in the arXiv version 1204.6374v1, the Corollary on p. 2, Hooley's conjecture on p. 1. The edition is identified on the source card.
Read depth. Claims checked: the statement was read clause by clause against the print, and its deduction from Theorem 1 was checked here as recorded above.
Proof pointer
No proof is printed. Put and at their thresholds in the condition of Theorem 1: $p^3\log^4p/(H^2K^2)<p^3\log^4p/(p^{4/3}\cdot p^{4/3}\log^4p)=p^{1/3}$.
Dependencies
Theorem 1 of the same paper.
Bears on
No Erdős problem directly: it concerns many pairs of intervals, while Problem 445 asks about a single interval, for which the problem page uses the case of Theorem 1.