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Statement

The paper's equation (1.1) (printed p. 373) is

Π=Π(n,d,k)=n(n+d)⋯(n+(k−1)d)=byl\Pi=\Pi(n,d,k)=n(n+d)\cdots(n+(k-1)d)=by^l

in positive integers n,d,y,bn,d,y,b and integers l≥2l\ge2, k≥2k\ge2, with gcd⁡(n,d)=1\gcd(n,d)=1 and P(b)≤kP(b)\le k, where P(u)P(u) is the greatest prime factor of an integer uu with ∣u∣>1|u|>1 and P(±1)=1P(\pm1)=1; bb is also taken to be free of llth powers.

Theorem 1 (p. 374), quoted: "Equation (1.1) with k=4,5k=4,5 and b=1b=1 does not hold."

So, for positive integers n,dn,d with gcd⁡(n,d)=1\gcd(n,d)=1 and every integer l≥2l\ge2, neither n(n+d)(n+2d)(n+3d)n(n+d)(n+2d)(n+3d) nor n(n+d)(n+2d)(n+3d)(n+4d)n(n+d)(n+2d)(n+3d)(n+4d) equals yly^l for a positive integer yy. Primitivity here is gcd⁡(n,d)=1\gcd(n,d)=1 only, not pairwise coprimality of the terms. The paper says (p. 374) that this answers a problem of Guy, D17 of Unsolved Problems in Number Theory.

Source. K. Győry, L. Hajdu and N. Saradha, On the Diophantine equation n(n+d)⋯(n+(k−1)d)=byln(n+d)\cdots(n+(k-1)d)=by^l, Canad. Math. Bull. 47 (2004), no. 3, 373--388, doi:10.4153/CMB-2004-037-1; equation (1.1) on p. 373, Theorem 1 on p. 374 and its proof on p. 384. The edition is recorded on the source card.

Read depth. Claims checked: the statement and the ambient hypotheses of (1.1) were read clause by clause against the published print, and the proof on p. 384 was read for its structure only. The proofs of Theorems 8 and 9, on which it rests, were not verified. A second reader checked the statement, hypotheses, label and page against the print.

Proof pointer

Section 5, p. 384. For l=2l=2 the paper cites Euler (k=4k=4) and Obláth (k=5k=5; its reference [11], Publ. Math. Debrecen 1 (1950), 222--226). For l≥3l\ge3 it reduces to a prime exponent ll; a prime l≥5l\ge5 is excluded by Theorem 8 (p. 376) and l=3l=3 by Theorem 9 (p. 376).

Bennett, Bruin, Győry and Hajdu, Powers from products of consecutive terms in arithmetic progression, Proc. London Math. Soc. (3) 92 (2006), 273--306, say on p. 273 that the arguments of this paper "are invalid if l=3l=3" and that they correct them in their Section 5; on p. 292 they say the proofs of Theorems 8 and 9 here depend on an incorrect result, Lemma 6 (p. 378), the lemma on cubic equations that the proof of Theorem 9 for l=3l=3 uses (p. 382). The statement stands with that later corrected proof for l=3l=3; see bennett_2006_powers_products_consecutive_terms_arithmetic_progression.

Dependencies

Theorems 8 and 9 (p. 376) of the same paper, through Lemmas 1--7 (pp. 377--379); Euler's theorem for k=4k=4, l=2l=2; Obláth's theorem for k=5k=5, l=2l=2; for l=3l=3, Section 5 of Bennett--Bruin--Győry--Hajdu (2006).

Bears on

  • Problem 672: the lengths k=4k=4 and k=5k=5, for every positive dd and every exponent l≥2l\ge2, answered in the negative; the case l=3l=3 holds with the 2006 corrected proof. Lengths k≥6k\ge6 are not covered. The claim is recorded on its claim page.