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Altman 1963 problem p erdos

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theorem_p149: Altman's theorem that every plane convex n-gon determines at least [n/2] distinct distances between its vertices, the conjecture of Erdős that Problem 93 states, proved through two lemmas on a longest side or diagonal.


E. Altman, On a problem of P. Erdős, Amer. Math. Monthly 70 (1963), no. 2, 148--157, JSTOR stable id 2312883, DOI 10.2307/2312883; the author at the Technion, Israel Institute of Technology, Haifa (p. 148). Cited as [Al63] on the problem pages of #93, #95 and #660; #982 is linked from this card only. Its four references (p. 157) are Erdős, On sets of distances of nn points, Amer. Math. Monthly 53 (1946), 248--250, filed as erdos_1946_sets_distances_points; Erdős, Some unsolved problems, Michigan Math. J. (1957), p. 296, filed as erdos_1957_unsolved_problems; Erdős, Publ. Math. Inst. Hung. Acad. Sci. 6 (1961), p. 243, filed as erdos_1961_unsolved_problems; and Moser, On the different distances determined by points, Amer. Math. Monthly 59 (1952), 85--91, not held.

The copy read for this card is JSTOR's scan of the printed article: 11 pages, a JSTOR cover page as PDF p. 1 (citation, stable URL and the access date, 2026-09-22) and printed pp. 148--157 = PDF pp. 2--11 (printed p. nn is PDF p. n−146n-146). Every page, the cover included, ends in JSTOR's download footer, which carries the download timestamp and the downloading machine's address (text layer, all 11 PDF pages). Printed p. 148 opens with the last half page of the preceding article, and Altman's paper begins below a rule in the middle of that page. The text layer is OCR that locates passages and garbles subscripts, brackets, inequality signs and the displayed angle relations of the proofs, so the statements were read on the page images. Provenance: the copy was obtained on 2026-09-22 from JSTOR through the library's acquisition, under the library's subscription access, from the stable URL https://www.jstor.org/stable/2312883; 567,413 bytes. The article pages carry no copyright line; the JSTOR cover sheet prints "All use subject to https://about.jstor.org/terms", whose terms state that the content is proprietary to its owners and permit only noncommercial, scholarly use (read 2026-10-02); the JSTOR item page served only a bot-challenge stub and the publisher's host returned HTTP 403 on 2026-10-02, so the publisher's page was not read, every other right reserved.

Read status: the whole article, printed pp. 148--157 (PDF pp. 2--11), was read on the page images. Claims checked clause by clause: the introduction (pp. 148--149), the Theorem (p. 149), Lemma 1 (p. 149), Lemma 2 (p. 151), the second Theorem, the nomenclature and Lemma 3 (p. 153), and the Remark and the reference list (p. 157). The proofs of Lemma 2 (pp. 151--152) and of the Theorem (pp. 152--153) were read in full and followed; the proof of Lemma 1 (pp. 149--151) was read in full and its angle argument followed in outline, not checked; the proof of Lemma 3 (pp. 154--156) and the proof of the second Theorem (pp. 156--157) were read for structure only. Nothing here is independently reviewed.

Contents

  • Introduction (pp. 148--149, page images). P\mathcal P is the family of all planar sets PnP_n of nn points and f(n)f(n) the minimum over them of the number of distinct distances; the paper then writes f(n)f(n) again for the same minimum over the vertex sets of convex nn-gons. The bounds it recalls for the general minimum are n2/3/(293)−1<f(n)<Cn/(log⁡n)1/2n^{2/3}/(2\sqrt[3]9)-1<f(n)<Cn/(\log n)^{1/2}, stated without attribution in the text (Moser's lower bound and Erdős's upper bound, by the reference list). The stated main purpose is to prove that the vertices of a convex nn-gon give f(n)=[n/2]f(n)=[n/2], which Erdős conjectured in the paper's references [1, 2, 3]. Two further conjectures of Erdős are recorded: that every convex polygon has a vertex with no three other vertices equidistant from it, said to have been disproved recently by Danzer for n=9n=9; and that every convex nn-gon has a vertex with at least [n/2][n/2] different distances to the other vertices, said to be still open, with the weaker bound [(n+2)/3][(n+2)/3] established by Moser [4]. The introduction also announces the regularity theorem of p. 153.
  • The Theorem (p. 149, page image), attributed in its heading to Erdős as the proposer and quoted here because the page's statement rests on its wording: "Every plane convex nn-sided polygon [...] comprises at least [n/2][n/2] different distances between corresponding pairs of vertices." The bracket is the integer part. It is paged on theorem_p149.
  • Lemma 1 (p. 149; proof pp. 149--151, page images). In a convex polygon A1A2⋯AnA_1A_2\cdots A_n whose side A1AnA_1A_n is of maximum length (no side or diagonal is longer), for indices 1≤p<y≤x<q<n1\le p<y\le x<q<n at least one of the segments ApAxA_pA_x, AqAyA_qA_y is shorter than the diagonal ApAqA_pA_q. The proof supposes both are at least as long, compares the base angles of the triangles ApAyAqA_pA_yA_q and ApAxAqA_pA_xA_q with the angles the segments A1AyA_1A_y and AnAxA_nA_x make where they cross ApAqA_pA_q, and reaches opposite inequalities between the same angle sums; the case x=yx=y is handled separately by an angle at AyA_y exceeding π/3\pi/3.
  • Lemma 2 (p. 151; proof pp. 151--152, page images). If a side of a convex nn-gon is of maximum length, the polygon determines at least n−2n-2 distinct distances; if the side is "a maximum in the narrower sense" (the paper's phrase, read here as strictly longer than every other side and diagonal), at least n−1n-1. The proof takes the side A1AnA_1A_n of length d1d_1, gets A2An−1<d1A_2A_{n-1}<d_1 from the obtuse angle of the quadrilateral A1A2An−1AnA_1A_2A_{n-1}A_n, and then applies Lemma 1 repeatedly: each diagonal in the chain shares a vertex with the next, whose other end moves one step along A2,A3,…A_2,A_3,\ldots or along $A_{n-1},A_{n-2}, \ldots$, so n−3n-3 steps produce n−3n-3 strictly decreasing lengths below d1d_1. In the strict case one diagonal of the quadrilateral lies strictly between d1d_1 and A2An−1A_2A_{n-1} and supplies one more length.
  • Proof of the Theorem (pp. 152--153, page images). If a side is of maximum length, Lemma 2 alone gives at least n−2≥[n/2]n-2\ge[n/2] distinct distances for n≥3n\ge3 (the paper does not state this case); otherwise the proof takes, among the diagonals of maximum length, one, ApAqA_pA_q, that cuts off the fewest consecutive sides, xx of them. It splits the polygon into two convex polygons: PP, with x+1x+1 sides, in which ApAqA_pA_q is the strictly longest segment (no side is of maximum length, and the minimality of xx excludes an equally long diagonal inside PP; the paper states the strictness without this remark), and QQ, with n−x+1n-x+1 sides, in which ApAqA_pA_q is of maximum length. Lemma 2 gives at least xx distinct distances in PP and at least n−x−1n-x-1 in QQ, all of them distances of the original polygon. Fewer than [n/2][n/2] distances in the whole polygon would force x<[n/2]x<[n/2] and n−x−1<[n/2]n-x-1<[n/2] together, which for n=2Nn=2N reads N−1<x<NN-1<x<N and for n=2N+1n=2N+1 reads N<x<NN<x<N, impossible for an integer xx.
  • The second Theorem (p. 153, page image), quoted: "If a plane convex (2N+1)(2N+1)-sided polygon comprises exactly NN different distances, it is regular." The nomenclature (p. 153): the segments AkAn−k+1A_kA_{n-k+1} form the parallel grid (1,n)(1,n) of the side A1AnA_1A_n; the diagonals joining the ends of one parallel to the ends of the next are its transversals; the angles a parallel makes with the sides above and below it are its ϵ\epsilon- and δ\delta-angles. Lemma 3 (p. 153): under the hypotheses of Lemma 2 with exactly n−1n-1 distances d1>d2>⋯>dn−1d_1>d_2>\cdots>d_{n-1} (part (a)), or exactly n−2n-2 distances with the side merely of maximum length (part (b)), the parallels and transversals of the grid carry prescribed lengths from the list, d2k−1d_{2k-1} and d2k−2d_{2k-2} in part (a), d2k−2d_{2k-2} and d2k−3d_{2k-3} in part (b). Its proof (pp. 154--156, three numbered paragraphs) uses the inequality between the diagonals and two opposite sides of a convex quadrilateral to force the two transversals of each quadrilateral to be equal, shows that the next parallel is the strictly longest segment of the polygon it cuts off, and descends into that polygon. The proof of the second Theorem (pp. 156--157, paragraph 4) shows that a longest diagonal of the (2N+1)(2N+1)-gon cuts off exactly NN sides, that every major diagonal (one cutting off NN sides) is of maximum length, and that Lemma 3 applied over each of them makes the polygon regular.
  • Remark (p. 157, page image). A convex 2N2N-gon with exactly NN distinct distances need not be regular: deleting one vertex of a regular (2N+1)(2N+1)-gon leaves an irregular 2N2N-gon with exactly NN distances. The same example shows the bound [n/2][n/2] of the Theorem is attained for even nn; the regular (2N+1)(2N+1)-gon attains it for odd nn.
  • Scope. The paper concerns the plane throughout. It prints no statement about polyhedra, about three or more dimensions, or about the number of pairs realizing a given distance.

Compiled scope

The paper is compiled at statement depth for the result the citing pages consume, the Theorem of p. 149, read on the page image and paged on theorem_p149, with its proof through Lemmas 1 and 2 read in full and followed as described in the read status. The second Theorem, Lemma 3 and the Remark are recorded as statements read on the page images. Nothing here is independently reviewed.

Bears on. #93: the Theorem (printed p. 149, PDF p. 3) is the problem's statement, that the vertices of a convex nn-gon determine at least ⌊n/2⌋\lfloor n/2\rfloor distinct distances; the regular (2N+1)(2N+1)-gon and the Remark's 2N2N-gon (p. 157) show the bound is attained, which is the introduction's f(n)=[n/2]f(n)=[n/2] (p. 148). The problem page reads the Theorem on the page image and its proof as followed here; nothing is independently reviewed. #95: the site says the convex-polygon case of that problem was solved by this paper. The paper's printed statements concern only the number of distinct distances; it prints no statement about ∑if(ui)2\sum_i f(u_i)^2, the sum of the squared multiplicities. By Cauchy--Schwarz the number tt of distinct distances satisfies t≥(n2)2/∑if(ui)2t\ge\binom n2^2/\sum_if(u_i)^2, so what the problem's inequality yields for tt in convex position, t≫ϵn1−ϵt\gg_\epsilon n^{1-\epsilon}, is weaker than the Theorem's t≥⌊n/2⌋t\ge\lfloor n/2\rfloor; the converse direction is not in the paper. How the site's sentence is to be read is a filing observation left open here, not a review verdict. #660: the paper is the two-dimensional analog the page records, the Theorem of p. 149, and it is the only Altman reference the site gives for that problem. Read in full on the page images, it treats the plane only and prints no statement about the vertices of a convex polyhedron or about three dimensions, so the linear lower bound D3>cnD_3>cn that Erdős's 1975 survey attributes to Altman is not in this paper. #982: the introduction (printed p. 149, PDF p. 3) records that problem's conjecture, a vertex with at least [n/2][n/2] different distances to the other vertices, as still open in 1963, and attributes the weaker bound [(n+2)/3][(n+2)/3] to Moser [4]; the paper proves nothing further about it.

Results.

  • Theorem, p. 149: every plane convex nn-gon determines at least [n/2][n/2] distinct distances between its vertices; sharp, by the regular polygon and the Remark of p. 157.

No file of this source is held: no license on record permits its redistribution, and the card cites the edition it names above.