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Green 2004 cameron erdos conjecture
corollary_13: States that, with o(2^{N/2}) exceptions, every sum-free subset of {1,...,N} consists entirely of odd numbers or is contained in {ceil((N+1)/3),...,N}.
proposition_6: States that an explicit family F of subsets of {1,...,N}, built from granularizations modulo a prime p in [2N,4N], has at most 2^{o(N)} members, each with o(N^2) additive triples, and contains a superset of every sum-free subset of {1,...,N}.
theorem_2: States that the number of sum-free subsets of {1,...,N} is asymptotically c(N)2^{N/2}, where c(N) takes two different constant values according to the parity of N, which proves the Cameron-Erdős conjecture.
Green, Ben, The Cameron-Erdős conjecture. Bull. London Math. Soc. 36 (2004), no. 6, 769-778, doi:10.1112/S0024609304003650. The copy read for this card is the arXiv v1 manuscript (stamp "arXiv:math/0304058v1 [math.NT] 4 Apr 2003"), 12 pages; the labels and pages below are its own. The arXiv record carries no license field, so arXiv's assumed license applies (arXiv:math/0304058), every other right reserved.
Theorem 2 (p. 2) proves that the number of sum-free subsets of [N] = {1,...,N} is asymptotically c(N)2^{N/2}, where c(N) takes two different constant values according as N is odd or even; the paper does not give the constants. This confirms Conjecture 1 of Cameron and Erdős (p. 1), that the count is O(2^{N/2}), previously known only in the form 2^{N/2+o(N)} (Alon, Calkin, and Erdős and Granville unpublished; display (1), p. 1, rederived as Proposition 12, p. 10). The proof has two parts: a container-style construction of a family F of 2^{o(N)} subsets of [N], each with o(N^2) additive triples, covering every sum-free subset, built from the Fourier-analytic granularization of Green and Ruzsa on Z/pZ (Proposition 6, p. 7); and a structural step (Corollary 13, p. 10), resting on a structure theorem for large sets with few additive triples (Proposition 7, p. 8), showing that all but o(2^{N/2}) sum-free subsets of [N] consist entirely of odd numbers or lie inside {ceil((N+1)/3),...,N}. The last step is not proved in the paper: it cites the count, due to Cameron and Erdős (1990), of the sum-free subsets of {ceil((N+1)/3),...,N} as asymptotically c(N)2^{N/2} (p. 11). The introduction also recalls counting bounds for sum-free subsets of Z/pZ and of general abelian groups.
Source: https://arxiv.org/abs/math/0304058.
Results
- Theorem 2 (p. 2): the number of sum-free subsets of [N] is asymptotically c(N)2^{N/2}, with c(N) taking two different constant values according to the parity of N; this proves the Cameron-Erdős conjecture.
- Corollary 13 (p. 10): with o(2^{N/2}) exceptions, all sum-free subsets of [N] consist entirely of odd numbers or are contained in {ceil((N+1)/3),...,N}.
- Proposition 6 (p. 7): an explicit family F of at most 2^{o(N)} subsets of [N], each with at most o(N^2) additive triples, such that every sum-free subset of [N] lies inside a member of F.
Read status. Claims checked for the three results above, read clause by clause on the arXiv manuscript; the proofs were read for their structure only.
Bears on
- Problem 748: Theorem 2 gives the asymptotic f(n) ~ c(n)2^{n/2} for the problem's count of sum-free subsets of {1,...,n}, hence the bound O(2^{n/2}) of the Cameron-Erdős conjecture and, with the trivial lower bound 2^{ceil(n/2)}, the asked exponent form; Proposition 12 rederives the exponent form, which the paper attributes to earlier work.
- Problem 877: background only. The paper counts all sum-free subsets, not the maximal ones; Theorem 2 identifies the problem's question f_m(n) = o(2^{n/2}) with maximal sum-free subsets being a vanishing proportion of all sum-free subsets, and gives no bound on f_m(n) beyond f_m(n) <= f(n).
No file of this source is held: no license on record permits its redistribution, and the card cites the edition it names above.