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Source. Theorem (the paper's only theorem, unnumbered), printed pp. 1151--1152 (physical PDF pp. 1--2), read on the page images; restated as inequality (3) on p. 1152. The proof occupies sections 2--6 (pp. 1154--1169) and was not read here.

Statement

Let q=1/pq=1/p, where p∈Z∖{0,±1}p\in\mathbb Z\setminus\{0,\pm1\}, and let

ζq(2)=∑n=1∞qn(1−qn)2=∑n=1∞pn(pn−1)2.(2)\zeta_q(2)=\sum_{n=1}^{\infty}\frac{q^n}{(1-q^n)^2} =\sum_{n=1}^{\infty}\frac{p^n}{(p^n-1)^2}. \qquad (2)

Then ζq(2)\zeta_q(2) is irrational, and only finitely many pairs of integers a,ba,b satisfy

∣ζq(2)−ab∣≤∣b∣−4.07869375.\Big|\zeta_q(2)-\frac ab\Big|\le|b|^{-4.07869375}.

In terms of the irrationality exponent $\mu(\alpha)=\inf{c\in\mathbb R:\ |\alpha-a/b|\le |b|^{-c}$ has finitely many solutions a,b∈Z}a,b\in\mathbb Z\}, the paper restates this as (3), μ(ζq(2))≤4.07869374…\mu(\zeta_q(2))\le4.07869374\ldots. The two printed constants differ in the last digit; both are recorded as printed.

Specialization. For p=2p=2, by the paper's (1),

ζ1/2(2)=∑n=1∞2n(2n−1)2=∑n=1∞σ(n)2n,\zeta_{1/2}(2)=\sum_{n=1}^{\infty}\frac{2^n}{(2^n-1)^2} =\sum_{n=1}^{\infty}\frac{\sigma(n)}{2^n},

the number of Problem 250; so that number is irrational with irrationality measure at most 4.07869374…4.07869374\ldots.

Proof pointer

A qq-analog of the Rhin--Viola group-structure method: rational linear forms in 11 and ζq(2)\zeta_q(2) from a qq-hypergeometric construction (section 2), their arithmetic through cyclotomic denominators (sections 1 and 3), a transformation group acting on the parameters (section 4), asymptotics (section 5) and the measure (section 6, pp. 1168--1169). Section 7 (pp. 1170--1171) gives a second route, a qq-analog of Apéry's sequence, which also yields the irrationality. Nothing of this was checked here.

Coverage

Statement read on the page images; proof not read. Relied on as a refereed publication (Zbl 1044.11067). The paper itself records (p. 1151) that the irrationality was established by Duverney and the transcendence by Nesterenko before it.

Bears on. #250: at p=2p=2 the theorem proves the problem's number irrational, with irrationality measure at most 4.07869374…4.07869374\ldots; the paper (p. 1151) credits the irrationality to Duverney before it.