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Erdos 1952 sum

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theorem: Erdős's theorem that for an irreducible integer polynomial f, positive on the positive integers, there are constants c_1, c_2 > 0 depending on f with c_1 x log x < sum_{k <= x} d(f(k)) < c_2 x log x for all x >= 2.


Erdős, P., On the sum {∑k=1xd(f(k))\sum^x_{k=1} d(f(k))}. J. London Math. Soc. 27 (1952), 7--15. No copyright or license line is printed in the file (pp. 7--8 and 14--15 read); the Wiley article page could not be read, and the article's Crossref record (DOI 10.1112/jlms/s1-27.1.7, read 2026-10-02) names Wiley as the journal's publisher and lists only Wiley's text-and-data-mining terms and its version-of-record terms and conditions (onlinelibrary.wiley.com/termsAndConditions#vor), no open license; every other right reserved.

For d(n)d(n) the divisor function and ff an irreducible polynomial of degree ll with integer coefficients, assumed positive on the positive integers, the paper's single Theorem (p. 7) proves that there are positive constants c1,c2c_1,c_2, depending on ff, with c1xlog⁡x<∑k≤xd(f(k))<c2xlog⁡xc_1x\log x<\sum_{k\le x}d(f(k))<c_2x\log x for x≥2x\ge2. The paper calls the lower bound not difficult and known, citing Bellman, Duke Math. J. 17 (1950), 159--168, and proves it in Sections 4 and 5 (pp. 14--15) by showing that the sum of dx(f(k))d_x(f(k)), the number of divisors of f(k)f(k) not exceeding xx, is already greater than c1xlog⁡xc_1x\log x; it says the asymptotic c3xlog⁡x+o(xlog⁡x)c_3x\log x+o(x\log x) for that restricted sum, its (2), would not be hard to show, without proving it. The upper bound is the harder part, since d(f(k))d(f(k)) is not easily bounded in terms of dx(f(k))d_x(f(k)). The paper says this can be done for l=2l=2, where Bellman and Shapiro proved, unpublished, the asymptotic c4xlog⁡x+o(xlog⁡x)c_4x\log x+o(x\log x), its (3); it says (3) very likely holds for l>2l>2 as well, but that it cannot prove this (p. 7).

The tools are Lemmas 1 to 9 of Section 2 (pp. 8--10) and Lemma 10 of Section 4 (p. 14). Lemma 1 is van der Corput's second-moment bound ∑k≤xd(f(k))2<x(log⁡x)c5\sum_{k\le x}d(f(k))^2<x(\log x)^{c_5}, and Lemma 2 derives from it, by Schwarz's inequality, that ∑i≤td(f(ki))<x\sum_{i\le t}d(f(k_i))<x for any tt distinct positive integers ki<xk_i<x with t<x(log⁡x)−c5t<x(\log x)^{-c_5}. With ρ(a)\rho(a) the number of solutions of f(k)≡0(moda)f(k)\equiv0\pmod a, 0≤k<a0\le k<a, and DD the discriminant of ff, Lemma 3 records that ρ\rho is multiplicative, that ρ(pα)≤l\rho(p^\alpha)\le l when p∤Dp\nmid D, Nagell's ρ(pα)=ρ(p2σ+1)\rho(p^\alpha)=\rho(p^{2\sigma+1}) when pσ ∥ Dp^\sigma\,\|\,D and α>2σ\alpha>2\sigma, and that ρ(pα)≤c6\rho(p^\alpha)\le c_6 always (Nagell: c6=lD2c_6=lD^2 suffices). Lemma 4 says that for 1≤u≤x1\le u\le x the number NN of kk with 1≤k≤x1\le k\le x and f(k)≡0(modu)f(k)\equiv0\pmod u satisfies x2uρ(u)≤N≤2xuρ(u)\frac{x}{2u}\rho(u)\le N\le\frac{2x}{u}\rho(u). Lemma 10 gives ∑k≤yρ(k)>c13y\sum_{k\le y}\rho(k)>c_{13}y for large yy. The paper also states, without proof, that its upper-bound method combined with Brun's method would give ∑p≤xd(f(p))=O(x)\sum_{p\le x}d(f(p))=O(x) over primes, answering a question in Bellman's paper (p. 7).

Problem 975 asks whether ∑n≤Xτ(f(n))∼cXlog⁡X\sum_{n\le X}\tau(f(n))\sim cX\log X. The paper gives the order of magnitude for every ff in its setting and the asymptotic for none; it reports the degree-two case only as Bellman and Shapiro's unpublished result.

Source: https://users.renyi.hu/~p_erdos/Erdos.html.

Read status: claims checked for the Theorem, (2), (3), the remark on primes and Lemmas 1 to 4 and 10, read clause by clause on the page images of the print; the proofs read for structure only. Nothing here is independently reviewed. Result page: theorem.

Bears on. #975: the Theorem (p. 7) proves c1xlog⁡x<∑k≤xd(f(k))<c2xlog⁡xc_1x\log x<\sum_{k\le x}d(f(k))<c_2x\log x for irreducible ff positive on the positive integers, the order of magnitude of the sum whose asymptotic the problem asks for; it proves no asymptotic for any ff.

Results.

  • Theorem (p. 7): for irreducible ff of degree ll with f(k)>0f(k)>0 for k≥1k\ge1, there are c1,c2>0c_1,c_2>0 with c1xlog⁡x<∑k≤xd(f(k))<c2xlog⁡xc_1x\log x<\sum_{k\le x}d(f(k))<c_2x\log x for x≥2x\ge2.

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