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Research notes on every problem, and a library of the papers behind them. Built from the open erdos repository.

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Statement

For a set AA of natural numbers, F(x,A)F(x,A) is the number of natural numbers n≤xn\le x divisible by no element of AA (p. 385). Put

H(x,K)=min⁡F(x,A),H(x,K)=\min F(x,A),

the minimum over sets AA with

∑a∈A1/a≤K,1∉A\sum_{a\in A}1/a\le K,\qquad 1\notin A

(display (1.5), p. 386).

The claim (printed p. 386, unnumbered). The paper says that the condition that the elements of PP be primes cannot be omitted, and continues: "In the second part of the paper we shall show that"

H(x,K)<xε,K>K0(ε),H(x,K)<x^{\varepsilon},\qquad K>K_0(\varepsilon),

and, more exactly, that

lim⁡x→∞log⁡H(x,K)log⁡x=e1−K(K≥1).\lim_{x\to\infty}\frac{\log H(x,K)}{\log x}=e^{1-K}\qquad(K\ge1).

It adds that H(x,1)=o(x)H(x,1)=o(x) follows from Schinzel and Szekeres (1959), who did not state it explicitly.

This paper contains no proof of either display. The second part is I. Z. Ruzsa, On the small sieve. II. Sifting by composite numbers, J. Number Theory 14 (1982), 260–268, whose card records the limit as that paper's Theorem I.

Source. P. Erdős and I. Z. Ruzsa, On the small sieve. I. Sifting by primes, J. Number Theory 12 (1980), 385–394; the definition (1.5) and the claim on printed p. 386 (PDF p. 2). The edition is identified in the source digest.

Read depth. Claims checked: the definition and the claim were read on the page image. There is no proof in this paper to check.

Dependencies

None in this paper.

Bears on

  • Problem 784: the quantity of that problem's corrected statement is H(x,C)H(x,C), with 11 excluded as in (1.5). For fixed K>1K>1 the claimed limit makes H(x,K)H(x,K) at most xθx^{\theta} for some θ<1\theta<1 and all large xx, which is eventually below x/(log⁡x)cx/(\log x)^c for every cc, so the claim, if proved, answers the problem negatively for K>1K>1. At K=1K=1 the limit is 11 and decides nothing. This paper only announces the claim.