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Problem 784

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claims/: The 2 claim pages of Problem 784, one per claimant's result; the problem's standing derives from them.


Statement. Let C>0C>0. Does there exist a c>0c>0 (depending on CC) such that, for all sufficiently large xx, if A⊆[1,x]A\subseteq [1,x] has $\sum_{n\in A}\frac{1}{n}\leq C$ then

#{m≤x:a∤m for all a∈A}≫x(log⁡x)c?\#\{ m\leq x : a\nmid m\textrm{ for all }a\in A\}\gg\frac{x}{(\log x)^c}?

Statement (corrected). Let C>0C>0. Does there exist a c>0c>0 (depending on CC) such that, for all sufficiently large xx, if A⊆[1,x]A\subseteq [1,x] with 1∉A1\notin A has ∑n∈A1n≤C\sum_{n\in A}\frac{1}{n}\leq C then

#{m≤x:a∤m for all a∈A}≫x(log⁡x)c?\#\{ m\leq x : a\nmid m\textrm{ for all }a\in A\}\gg\frac{x}{(\log x)^c}?

Notes. The site's wording fails for every C≥1C\ge1 at the set A={1}A=\{1\}: its reciprocal sum is 1≤C1\le C, every mm is divisible by 11, and nothing up to xx is left unsifted, so the answer is no for a reason that has nothing to do with sieving. The failure was observed in a thread comment by jif of 18 December 2025 (thread), which also noted the union bound (1−C)x(1-C)x for 0<C<10<C<1, and the site's commentary records it. The change inserts "with 1∉A1\notin A" after "A⊆[1,x]A\subseteq[1,x]", in the form of the condition that defines the quantity in the problem's own sources. The evidence, strongest first: Erdős and Ruzsa [ErRu80], p. 386, define the least unsifted count H(x,K)H(x,K) for general sets over the AA subject to ∑a∈A1/a≤K\sum_{a\in A}1/a\le K and 1∉A1\notin A (display (1.5)) and announce for it the limit e1−Ke^{1-K} of log⁡H(x,K)/log⁡x\log H(x,K)/\log x that answers this question; in Erdős's own [Er73], p. 135, the question is stated for a1<⋯<ak≤na_1<\cdots<a_k\le n, and the coprime question printed next to it, display (14.3), takes 1<ai≤n1<a_i\le n; Ruzsa [Ru82] (display (1.3)) and Weingartner [We25] (the paper's condition (3)) define the quantity they estimate with 11 excluded; and the site's commentary defines HC(x)H_C(x) as the minimum over subsets of {2,…,⌊x⌋}\{2,\ldots,\lfloor x\rfloor\} and says that the question asks whether HC(x)≫x/(log⁡x)OC(1)H_C(x)\gg x/(\log x)^{O_C(1)}. The defect is already in [Er73], whose a1<⋯<ak≤na_1<\cdots<a_k\le n does not exclude 11, and the site's wording keeps it; no source states the question as one about sets containing 11. With 11 excluded the recorded failure is removed, and the answer is decided by Ruzsa's and Weingartner's theorems rather than by the degenerate set. The observation about A={1}A=\{1\} settles no instance of the corrected Statement and is credited here, not counted.

Formulation. The site's wording as of 2026-09-05 (page last edited 8 April 2026). Erdős's [Er73], p. 135, asks it for a1<⋯<ak≤na_1<\cdots<a_k\le n with ∑1/ai<c1\sum1/a_i<c_1 and notes that, by the example of Schinzel and Szekeres [ScSz59], the bound would be best possible apart from the value of the exponent. The site's commentary writes HC(x)H_C(x) for the least unsifted count over A⊆{2,…,⌊x⌋}A\subseteq\{2,\ldots,\lfloor x\rfloor\} with reciprocal sum at most CC, the notation used below. For 0<C<10<C<1 the element 11 cannot lie in AA anyway, and the union bound leaves at least (1−C)x(1-C)x integers unsifted.

Status. The site labels the problem SOLVED and credits Ruzsa and Weingartner (page last edited 8 April 2026, accessed 2026-09-05 and 2026-10-07; two thread comments, no proof claim). For the corrected Statement the answer is yes for 0<C≤10<C\le1 and no for C>1C>1, so the bound fails when it is asked for every C>0C>0, as Erdős expected it to hold. For 0<C<10<C<1 the union bound leaves at least (1−C)x(1-C)x integers unsifted. Ruzsa (J. Number Theory 14 (1982), a refereed journal) proves c1x/log⁡x<H1(x)<x/(log⁡x)c2c_1x/\log x<H_1(x)<x/(\log x)^{c_2}, the lower bound answering yes at C=1C=1, and log⁡HC(x)/log⁡x→e1−C\log H_C(x)/\log x\to e^{1-C} for C≥1C\ge1, so for fixed C>1C>1 the unsifted count can be xe1−C+o(1)x^{e^{1-C}+o(1)}, below every x/(log⁡x)cx/(\log x)^c; Erdős's 1980 survey acknowledges that Ruzsa's construction overturned his expectation. Weingartner (Res. Number Theory 11 (2025), refereed) sharpens this to HC(x)≍xe1−C/log⁡xH_C(x)\asymp x^{e^{1-C}}/\log x uniformly for 1≤C≤Z1\le C\le Z, and Saias (1998) gives the matching upper bound H1(x)≪x/log⁡xH_1(x)\ll x/\log x. Claim pages: Ruzsa 1982 and Weingartner 2025 (both accepted). When AA consists of primes, Erdős and Ruzsa (1980) show a positive proportion of the integers up to xx is always left unsifted, a restricted variant.

Source. erdosproblems.com/784, accessed 2026-09-04. Cite as: T. F. Bloom, Erdős Problem #784, https://www.erdosproblems.com/784.

References.

Formalization. None recorded.

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