Research notes on every problem, and a library of the papers behind them. Built from the open erdos repository.
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Statement
Setting (p. 1). A sunflower with petals is a family of sets whose pairwise intersections are all the same set, which may be empty. is the least natural number such that every family of at least distinct -element sets contains a sunflower with petals.
Theorem 1 (p. 1, quoted). "There is a constant such that for all integers ."
The paper places this against Rao's bound (reproved by Tao), so the gain is the removal of the factor, and against the Erdős–Rado bounds (p. 1).
Proof pointer
P. 1, the paragraph after Theorem 1. With the paper shows for all and by induction on . The case is immediate since . For , a family that is -spread has disjoint members by Lemma 2, and these form a sunflower; otherwise some non-empty lies in more than members, and induction applied to those members with removed gives the sunflower.
Read depth
Claims checked: the definitions, Theorem 1 and the induction on p. 1 were read clause by clause on the page images of the print. Nothing here is independently reviewed.
Dependencies
Lemma 2, which rests on the external Theorem 3 of Rao and Tao.
Source. T. Bell, S. Chueluecha and L. Warnke, Note on sunflowers, Discrete Math. 344 (2021), no. 7, 112367, doi:10.1016/j.disc.2021.112367; the edition read, arXiv:2009.09327v2, is named on the source card, and the labels and pages here are its.
Bears on
- Problem 20: with the problem's as the paper's and the problem's as the paper's , the theorem gives for all . For fixed this is , not the bound the problem asks for; the paper states that the conjecture remains open (p. 1).