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Research notes on every problem, and a library of the papers behind them. Built from the open erdos repository.

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Statement

Setting (p. 1). A sunflower with pp petals is a family of pp sets whose pairwise intersections are all the same set, which may be empty. Sun(p,k)\mathrm{Sun}(p,k) is the least natural number ss such that every family of at least ss distinct kk-element sets contains a sunflower with pp petals.

Theorem 1 (p. 1, quoted). "There is a constant C≥4C\geq 4 such that Sun(p,k)≤(Cplog⁡k)k\mathrm{Sun}(p,k)\leq(Cp\log k)^k for all integers p,k≥2p,k\geq 2."

The paper places this against Rao's bound Sun(p,k)≤(Cplog⁡(pk))k\mathrm{Sun}(p,k)\leq(Cp\log(pk))^k (reproved by Tao), so the gain is the removal of the log⁡p\log p factor, and against the Erdős–Rado bounds (p−1)k<Sun(p,k)≤(p−1)kk!+1(p-1)^k<\mathrm{Sun}(p,k)\leq(p-1)^kk!+1 (p. 1).

Proof pointer

P. 1, the paragraph after Theorem 1. With r(p,k)=Cplog⁡k+1{k=1}pr(p,k)=Cp\log k+\mathbb 1_{\{k=1\}}p the paper shows Sun(p,k)≤r(p,k)k\mathrm{Sun}(p,k)\leq r(p,k)^k for all p≥2p\geq2 and k≥1k\geq1 by induction on kk. The case k=1k=1 is immediate since r(p,1)=pr(p,1)=p. For k≥2k\geq2, a family that is r(p,k)r(p,k)-spread has pp disjoint members by Lemma 2, and these form a sunflower; otherwise some non-empty TT lies in more than r(p,k)k−∣T∣≥r(p,k−∣T∣)k−∣T∣r(p,k)^{k-|T|}\geq r(p,k-|T|)^{k-|T|} members, and induction applied to those members with TT removed gives the sunflower.

Read depth

Claims checked: the definitions, Theorem 1 and the induction on p. 1 were read clause by clause on the page images of the print. Nothing here is independently reviewed.

Dependencies

Lemma 2, which rests on the external Theorem 3 of Rao and Tao.

Source. T. Bell, S. Chueluecha and L. Warnke, Note on sunflowers, Discrete Math. 344 (2021), no. 7, 112367, doi:10.1016/j.disc.2021.112367; the edition read, arXiv:2009.09327v2, is named on the source card, and the labels and pages here are its.

Bears on

  • Problem 20: with the problem's nn as the paper's kk and the problem's kk as the paper's pp, the theorem gives f(n,k)≤(Cklog⁡n)nf(n,k)\leq(Ck\log n)^n for all n,k≥2n,k\geq2. For fixed kk this is (log⁡n)n(1+o(1))(\log n)^{n(1+o(1))}, not the cknc_k^n bound the problem asks for; the paper states that the conjecture remains open (p. 1).