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Source. Theorem 12, p. 20, with its proof on pp. 20–21, of David Ellis, Irredundant families of subcubes, arXiv:1003.2960v1 (2010), published in Mathematical Proceedings of the Cambridge Philosophical Society 150(2) (2011), 257–272, as identified on the source card. Labels and pages are those of arXiv:1003.2960v1.
Statement
Subcubes and irredundance are as on the Theorem 4 page.
Theorem 12 (p. 20). For any , there is an irredundant family of -subcubes of of size at least
With Theorem 4, whose bound equals , this gives (9), p. 21:
where is the largest size of an irredundant family of -subcubes of . The paper shows that the ratio increases on from to , so the two bounds differ by a factor of at most for all and (pp. 21–22; stated also on p. 4).
Proof pointer
Pages 20–21. Put each vertex in a random set independently with probability . For each vertex at Hamming distance exactly from , take the -subcube between and a nearest point of ; these subcubes are distinct, and is a private vertex of its own. The expected number of such is with , and choosing so that maximizes it at the stated value.
Dependencies
None for the construction. The two-sided estimate (9) uses Theorem 4.
Read depth. Claims checked: the statement on p. 20 and the estimate (9) with the ratio remark on p. 21 were read clause by clause. The proof was read but not checked step by step.
Bears on
No Erdős problem.