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Research notes on every problem, and a library of the papers behind them. Built from the open erdos repository.

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Problem 31

../

claims/: The 1 claim page of Problem 31, one per claimant's result; the problem's standing derives from them.


Statement. Given any infinite set A⊂NA\subset \mathbb{N} there is a set BB of density 00 such that A+BA+B contains all except finitely many integers.

Status. Proved; the site's label is PROVED (LEAN). Lorentz's Theorem 1 [Lo54] gives every infinite AA a density-zero complement with A+BA+B cofinite; the Lean qualification of the site's label corresponds to the proof the formal-conjectures catalog links, a third party's Lean proof. The claim page [[problems/additive_bases/E0031/claims/1954_03_02_lorentz|Lorentz's sparse additive complement]] records the acceptance evidence, the refereed publication and the catalog's curator, Thomas Bloom; the Lean proof carries no formal-verification credit in this corpus.

Source. erdosproblems.com/31, accessed 2026-09-04. Cite as: T. F. Bloom, Erdős Problem #31, https://www.erdosproblems.com/31.

References.

Formalization. Statement in formal-conjectures (accessed 2026-10-07), tagged research solved and linking the Lean proof erdos_31 in Boris Alexeev's repository https://github.com/plby/lean-proofs (announced on the site's thread 2025-11-24). The Lean proof carries no formal-verification credit in this corpus; the claim page gives the pinned link.

Current assessment

Lorentz's published Theorem 1 gives the density-zero complement conclusion with the convention transfer below; the claim page [[problems/additive_bases/E0031/claims/1954_03_02_lorentz|Lorentz's sparse additive complement]] carries the standing and its acceptance evidence, the refereed publication and the catalog's agreement. The complete natural-language chain is retained as author-recorded proof coverage. No independent review of the proof chain is filed; the acceptance evidence is the refereed publication and the catalog's credit. The Lean proof carries no formal-verification credit in this corpus. Status search of 2026-10-07: the site's page and remarks, its thread (two comments, an exposition of Lorentz's proof of 2025-11-22 and the announcement of the Lean proof of 2025-11-24, and no proof claim) and the formal-conjectures file; no other claim was found.

Progress

Lorentz's published Theorem 1 gives a direct quantitative solution. The library card's Theorem 1 page reconstructs its complete elementary proof, author-recorded.

Problem 32 asks for a much sharper prime-specific complement. Lorentz's general theorem is relevant historical context there, but it does not settle that problem's quantitative target.

Known Results

For A⊆{1,2,…}A\subseteq\{1,2,\ldots\}, write A(n)=∣A∩[1,n]∣A(n)=|A\cap[1,n]|. [[../library/additive_bases/lorentz_1954_problem_additive_number_theory/theorem_1|Lorentz's Theorem 1]], stated on printed p.838 and proved through printed p.840, constructs a set BB such that A+BA+B contains every sufficiently large natural number and

B(n)≤C∑k=1nlog⁡A(k)A(k),B(n)\leq C\sum_{k=1}^{n}\frac{\log A(k)}{A(k)},

where a term with A(k)=0A(k)=0 is replaced by 11. Because AA is infinite, A(k)→∞A(k)\to\infty, so the summands tend to zero. Their Cesàro averages tend to zero, and hence B(n)=o(n)B(n)=o(n).

If N\mathbb N includes 00, first replace AA by the still-infinite positive part A∩{1,2,…}A\cap\{1,2,\ldots\}. A complement for that subset is also a complement for AA. This gives exactly the cofinite sumset and density-zero conclusion in the statement.

The source home expands the greedy cover, the Ks/ksK_s/k_s double count, the s0s_0 floor and early-count endpoint, the dyadic construction, the block reindexing, and the final Cesàro argument. This complete natural-language chain remains author-recorded. No formal-verification claim is made.

Linked library material

These entries are derived from explicit links on library pages. They are navigation only and do not by themselves record mathematical progress.