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Research notes on every problem, and a library of the papers behind them. Built from the open erdos repository.

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Claim. The question of Problem 880 has the answer yes for k=2k=2 and no for every k≥3k\ge3. Write h×Ah\times A for the set of sums of hh pairwise distinct elements of AA and Δ(X)\Delta(X) for the largest asymptotic gap lim sup⁡(xi+1−xi)\limsup(x_{i+1}-x_i) of a set X={x1<x2<⋯ }X=\{x_1<x_2<\cdots\}. Theorem 1 of N. Hegyvári, F. Hennecart and A. Plagne, Answer to a question by Burr and Erdős on restricted addition, and related results, Combin. Probab. Comput. 16 (2007), no. 5, 747--756, states: (i) if A∪2AA\cup 2A contains all sufficiently large integers, then Δ(A∪2×A)≤2\Delta(A\cup 2\times A)\le2, and if 2A2A does, then Δ(2×A)≤2\Delta(2\times A)\le2; (ii) for every h≥3h\ge3 there is a set AA such that h({0}∪A)h(\{0\}\cup A) contains all sufficiently large integers and Δ(A∪2×A∪⋯∪h×A)=∞\Delta(A\cup 2\times A\cup\cdots\cup h\times A)=\infty, and a set AA with hAhA containing all sufficiently large integers and Δ(h×A)=∞\Delta(h\times A)=\infty. A set AA is a basis of order kk in the problem's sense, every large integer a sum of kk or fewer elements, exactly when k({0}∪A)k(\{0\}\cup A) contains all large integers, and the problem's BB is $A\cup 2\times A\cup\cdots\cup k\times A$, so part (i) gives bn+1−bn≤2b_{n+1}-b_n\le2 for all large nn when k=2k=2, and part (ii) gives a basis of each order k≥3k\ge3 with bn+1−bnb_{n+1}-b_n unbounded. The claim value is disproved: the question asks whether the gaps are bounded for every basis AA of every order kk, and part (ii) refutes that for each k≥3k\ge3; the case k=2k=2, where the assertion holds, is the part of the question that survives. The site labels the problem PROVED, although its remarks report the answer no for every k≥3k\ge3; the claim value follows the question as stated, which asks about every order kk.

Argument. The case k=2k=2 is the parity observation the site's remarks also make: an odd element of A+AA+A is a sum of two distinct elements, so when every large integer lies in A∪(A+A)A\cup(A+A), every large odd integer lies in A∪2×AA\cup 2\times A, the problem's BB, whose gaps are therefore at most 22 (when A+AA+A alone contains every large integer, 2×A2\times A itself contains every large odd integer). For h≥3h\ge3 the paper gives an explicit set: with x0=hx_0=h and xn+1=(3⋅2h−2−1)xn2+hxnx_{n+1}=(3\cdot2^{h-2}-1)x_n^2+hx_n, let An=[0,xn2)∪{2jxn2:0≤j≤h−2}A_n=[0,x_n^2)\cup\{2^jx_n^2:0\le j\le h-2\} and A={0}∪⋃n≥0(xn+An)A=\{0\}\cup\bigcup_{n\ge0}(x_n+A_n); sums of hh elements of AnA_n cover a long initial interval, which makes AA a basis of order hh, while sums of distinct elements miss arbitrarily long stretches. The same example gives the paper's Theorem 3: its k(h)k(h), the largest over all AA with hAhA cofinite of the least kk with Δ(k×A)<∞\Delta(k\times A)<\infty, satisfies k(h)≥2h−2+h−1k(h)\ge 2^{h-2}+h-1, realized by this example, which is why the answer fails for every h≥3h\ge3. The source card is hegyvari_2007_answer_question_burr_erdos_restricted_addition; the theorem numbering used here is that of the authors' preprint. This outline is a reading aid, not proof coverage.

Acceptance. The refereed evidence is the journal publication cited above (Combinatorics, Probability and Computing; Crossref gives the issue date 2007-09-01, which is the page's date). The reviewed evidence is the documented acceptance by the catalog erdosproblems.com: its curator, Thomas Bloom, credits both answers to this paper in the problem's remarks, and the page carries the label PROVED (accessed 2026-10-07). The proof is not compiled or reviewed here.

Formalization. A third party formalized both answers: not_erdos_880 in src/latest/ErdosProblems/Erdos880.lean of Boris Alexeev's repository https://github.com/plby/lean-proofs, pinned above at the commit of 2026-08-31 that last touched the file (the file was added on 2026-08-17). Its header names Hegyvári, Hennecart and Plagne as informal authors and Codex and GPT-5.6 Sol as formal authors, and its module comment states their theorem, so it is a formalization of this result and a link on this page, not an independent claim. Its theorem is a conjunction: every infinite set whose least order as an asymptotic basis is 22 has sums of at most two distinct elements with bounded gaps, and for every h≥3h\ge3 there is an infinite set of least order hh whose sums of at most hh distinct elements have unbounded gaps; the file imports Mathlib, contains no sorry and prints the theorem's axioms. This corpus has not built the file or audited its definitions against the problem, so the claim carries no formalized evidence.

Depends on. No page of this wiki.