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Problem 382

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Statement. Let u≤vu\leq v be such that the largest prime dividing ∏u≤m≤vm\prod_{u\leq m\leq v}m appears with exponent at least 22. Is it true that v−u=vo(1)v-u=v^{o(1)}? Can v−uv-u be arbitrarily large?

Status. Open, the site's label (OPEN).

Source. erdosproblems.com/382, accessed 2026-09-04. Cite as: T. F. Bloom, Erdős Problem #382, https://www.erdosproblems.com/382.

Formalization. None recorded.

Current assessment

Open; the first question is answered only under a hypothesis. The site's formulation (its revision of 20 October 2025) asks, for intervals [u,v][u,v] whose product has its largest prime factor to an exponent at least 22, whether v−u=vo(1)v-u=v^{o(1)} and whether v−uv-u can be arbitrarily large; the site labels the problem OPEN. Erdős and Graham report that results of Ramachandra give v−u≤v1/2+o(1)v-u\le v^{1/2+o(1)}, and Remark 6.2 of Tao's preprint Tao 2026 says that Ramachandra's Selberg-sieve argument gives v−u≪v1/2−cv-u\ll v^{1/2-c} for an absolute c>0c>0, records both questions as conjectures of Erdős and Graham and makes no progress on them. The site's commentary credits Stijn Cambie with the observation that a consequence of Cramér's conjecture, that every interval [u,u+uϵ][u,u+u^{\epsilon}] with uu large contains a prime, answers the first question yes, since an interval that contains a prime has its largest prime factor to the first power only. That answer rests on an unproved hypothesis and is a remark in the site's commentary, not a dated manuscript, so it gets no claim page. Cambie's heuristic for the second question is not a proof; a positive answer to Problem 383 would answer that question yes. A comment of 11 August 2025 in the problem's forum thread gives an interval with v−u=13v-u=13 whose largest prime factor 42370334237033 appears squared and one with v−u=5v-u=5 whose largest prime factor 211193211193 appears cubed.

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