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Problem 411

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claims/: The 1 claim page of Problem 411, one per claimant's result; the problem's standing derives from them.


Statement. Let g1=g(n)=n+ϕ(n)g_1=g(n)=n+\phi(n) and gk(n)=g(gk−1(n))g_k(n)=g(g_{k-1}(n)). For which nn and rr is it true that gk+r(n)=2gk(n)g_{k+r}(n)=2g_k(n) for all large kk?

Status. Open, the site's label (OPEN, page last edited 28 October 2025). The one claim recorded, Steinerberger 2025, is partial: it reduces shift two to the equation ϕ(m)+ϕ(m+ϕ(m))=m\phi(m)+\phi(m+\phi(m))=m, puts every solution into two branches by its odd part, and claims to settle the first branch, whose solutions are six doubling families with odd part in {1,3,5,7,35,47}\{1,3,5,7,35,47\}; the second branch, the question of which nn reach a solution, and every other shift stay open.

Source. erdosproblems.com/411, accessed 2026-09-04. Cite as: T. F. Bloom, Erdős Problem #411, https://www.erdosproblems.com/411.

References.

Formalization. None recorded.

Current assessment

Open; shift two is reduced to one totient equation, with one of its two branches claimed settled by an arXiv preprint. The site formulation above (page last edited 28 October 2025) asks for which nn and rr the iterates of g(n)=n+ϕ(n)g(n)=n+\phi(n) satisfy gk+r(n)=2gk(n)g_{k+r}(n)=2g_k(n) for all large kk. The site records the solutions n=10n=10 and n=94n=94 for r=2r=2, Selfridge and Weintraub's solutions of the multiplier-99 relation gk+9(n)=9gk(n)g_{k+9}(n)=9g_k(n), and Weintraub's gk+25(3114)=729gk(3114)g_{k+25}(3114)=729g_k(3114) for k≥6k\ge6. The one claim recorded is Steinerberger's 2025 preprint (claim page; library card): the relation with r=2r=2 holds from step kk on exactly when m=gk(n)m=g_k(n) solves ϕ(m)+ϕ(m+ϕ(m))=m\phi(m)+\phi(m+\phi(m))=m; every solution has odd part in {1,3,5,7,35,47}\{1,3,5,7,35,47\} or is 2ℓ(8t+7)2^\ell(8t+7) or 2ℓ(6t+5)2^\ell(6t+5) with 8t+7≥10108t+7\ge10^{10} prime and ϕ(6t+5)=4t+4\phi(6t+5)=4t+4; and the first branch's solutions are exactly 2as2^a s with ss in that set and a≥asa\ge a_s (a1=2a_1=2, as=1a_s=1 otherwise). The site's commentary credits the reduction and the branches to the preprint and relates the second branch to whether ϕ(q)=23(q+1)\phi(q)=\tfrac23(q+1) has infinitely many solutions; it labels the problem OPEN, so the claim is pending, not accepted. The preprint is on arXiv only, with no journal reference on its record.

Proof claim on the site. The site's proof-claims tab carries one partial claim, posted 2026-09-08 by Alateng Pan (write-up on Zenodo, fourth version of 2026-08-18; three earlier versions claimed a complete proof of the r=2r=2 case and were retitled), which claims to settle the first branch of the reduction by the six base orbits n=4,6,10,14,70,94n=4,6,10,14,70,94 and a doubling step and leaves the second branch open; the submission states that the system DeepSeek was used for language polishing and formatting only, with the mathematics the author's own. Its result is the first-branch classification already in the 2025 preprint, so under the rule that the credited source names the page it is disclosed on the Steinerberger claim page and gets no page of its own.

Material reported by the site without a result on the problem. The site reports Cambie's conjecture that the only solutions have r=2r=2 and n=2lpn=2^lp with l≥1l\ge1 and p∈{2,3,5,7,35,47}p\in\{2,3,5,7,35,47\}. Read with the problem's "for all large kk" this cannot hold, since every nn whose orbit reaches such a value also qualifies (n=18n=18 and n=22n=22 satisfy the relation from k=1k=1). It is therefore read as concerning the nn for which the relation holds from k=0k=0, which are the solutions of Steinerberger's equation. Cambie has reduced the problem to the question of which integers r,t≥1r,t\ge1 and primes p≡7(mod8)p\equiv7\pmod8 satisfy gr(2pt)=4ptg_r(2p^t)=4p^t (the site prints gkg_k). The known cases are g2(14)=28g_2(14)=28 and g2(94)=188g_2(94)=188, and he conjectures no solutions beyond t=1t=1 and p∈{7,47}p\in\{7,47\}. The site also reports his observed shift-four relations gk+4(738)=3gk(738)g_{k+4}(738)=3g_k(738), gk+4(148646)=4gk(148646)g_{k+4}(148646)=4g_k(148646) and gk+4(4325798)=4gk(4325798)g_{k+4}(4325798)=4g_k(4325798) for all k≥1k\ge1. None of these settles an instance of the multiplier-22 question: the conjecture and the reduction decide no nn, and the three examples have multipliers 33 and 44. The forum thread (six comments, 2025-12-09 to 2026-09-13) adds, on the related equation ϕ(q)=23(q+1)\phi(q)=\tfrac23(q+1), a comment citing a paper of Hercher that proves every solution squarefree, with at least seven prime factors and at least 101410^{14} beyond the four known, and a comment of 2026-04-03 claiming that the squarefree solutions are exactly the partial products of a recurrence of primes, which a reply the same day refutes as stated (a solution need not come from a smaller solution by adjoining one prime); the remaining comments are Pan's announcements of the claim above. None of these decides an instance of the problem either.

Formalization and search scope. No formal-conjectures statement file exists (the site reports no formalised statement; the community database lists the problem as open and unformalized as of its last update on 2025-08-31, with the comment "partial r=2 result"). Search scope: the site's page, discussion thread and proof-claims tab, the arXiv record of [St25], the Zenodo record of the later claim and its version history, the community database, and the monograph page recorded below.

Known Results

Historical question and examples

Erdős and Graham's 1980 monograph, printed p. 81, defines g1(n)=g(n)=n+ϕ(n)g_1(n)=g(n)=n+\phi(n) and gk(n)=g(gk−1(n))g_k(n)=g(g_{k-1}(n)) for k≥2k\geq2, and asks about the eventual multiplier-2 relation in the displayed question.

Among the examples recorded on that page, only n=10,94n=10,94 with shift 2 are examples of the target relation:

gk+2(n)=2gk(n).g_{k+2}(n)=2g_k(n).

The page separately reports Selfridge and Weintraub's examples of

gk+9(n)=9gk(n),g_{k+9}(n)=9g_k(n),

with all reported nn even, and Weintraub's example

gk+25(3114)=729gk(3114),k≥6.g_{k+25}(3114)=729g_k(3114),\qquad k\geq6.

The latter two relations have multipliers 9 and 729, respectively; they are separate scaling relations, not examples of the target multiplier-2 equation. These are historical reports: the passage supplies no general classification in n,rn,r, and their computational certificates are not checked by this corpus.

Linked library material

These entries are derived from explicit links on library pages. They are navigation only and do not by themselves record mathematical progress.