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Problem 930
claims/: The 1 claim page of Problem 930, one per claimant's result; the problem's standing derives from them.
Statement. Is it true that, for every , there is a such that if are disjoint intervals of consecutive integers, all of length at least , then
is not a perfect power?
Formulation. The intervals consist of positive integers. Erdős's display (9) on p. 28 of [Er76d] asks for no solution in positive integers, and the formal-conjectures statement requires every interval to start above . An interval containing would make the product .
Status. Open.
Source. erdosproblems.com/930, accessed 2026-09-04. Cite as: T. F. Bloom, Erdős Problem #930, https://www.erdosproblems.com/930.
References.
- [Er76d] Erdős, P., Problems and results on number theoretic properties of consecutive integers and related questions. Proceedings of the Fifth Manitoba Conference on Numerical Mathematics (Univ. Manitoba, Winnipeg, Man., 1975) (1976), 25-44.
- [ErSe75] Erdős, P. and Selfridge, J. L., The product of consecutive integers is never a power. Illinois J. Math. (1975), 292-301.
Formalization. Statement in formal-conjectures.
Current assessment
Erdős poses the question in [Er76d] as display (9), a common generalization of the theorem that a product of consecutive integers is never a power, and says that he cannot prove it even in a special case with . The case is that theorem of Erdős and Selfridge [ErSe75], with , recorded as the accepted partial claim Erdős and Selfridge 1975. The site notes that the lengths must be allowed to grow with : the constructions of Problem 363 show that for short intervals can have a perfect power as product, and that problem treats the case of squares. The question is open for every .
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