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Problem 189

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claims/: The 1 claim page of Problem 189, one per claimant's result; the problem's standing derives from them.


Statement. If R2\mathbb{R}^2 is finitely coloured then must there exist some colour class which contains the vertices of a rectangle of every area?

Status. DISPROVED (LEAN): the site credits Kovač's coloring of the plane in 2525 colors with no monochromatic rectangle of area 11 [Ko23]; see the claim page.

Source. erdosproblems.com/189, accessed 2026-09-04. Cite as: T. F. Bloom, Erdős Problem #189, https://www.erdosproblems.com/189.

References.

  • [Gr80] Graham, R. L., On partitions of En{\bf E}^{n}. J. Combin. Theory Ser. A (1980), 89-97.
  • [Ko23] Kovač, V., Coloring and density theorems for configurations of a given volume. arXiv:2309.09973 (2023).

Formalization. Statement in formal-conjectures.

Current assessment

The answer is no. Theorem 3 of Kovač gives an explicit Jordan-measurable coloring of the plane in 2525 colors in which no color class contains the four vertices of a rectangle of area 11, so no color class contains a rectangle of every area. The paper is refereed in Proc. Lond. Math. Soc., and the site's curator credits it; the two Lean developments of the coloring are linked at pinned commits from the claim page and have not been built or audited by this corpus. Graham [Gr80] proved the positive statement for right-angled triangles in place of rectangles. The question for parallelograms was open as the parallelogram variant of the formal-conjectures file records; Kovač's Theorem 6 settles it only for parallelograms with a side in one of finitely many fixed directions or with all angles bounded away from zero.

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