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Problem 669

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claims/: The 2 claim pages of Problem 669, one per claimant's result; the problem's standing derives from them.


Statement. Let Fk(n)F_k(n) be minimal such that for any nn points in R2\mathbb{R}^2 there exist at most Fk(n)F_k(n) many distinct lines passing through at least kk of the points, and fk(n)f_k(n) similarly but with lines passing through exactly kk points.

Estimate fk(n)f_k(n) and Fk(n)F_k(n) - in particular, determine lim⁡Fk(n)/n2\lim F_k(n)/n^2 and lim⁡fk(n)/n2\lim f_k(n)/n^2.

Status. Open. The site labels the problem OPEN (page last edited 27 December 2025). The instance k=3k=3 is settled by the accepted partial claims on Burr, Grünbaum and Sloane's construction and Green and Tao's exact bound.

Source. erdosproblems.com/669, accessed 2026-09-04. Cite as: T. F. Bloom, Erdős Problem #669, https://www.erdosproblems.com/669.

References.

Formalization. None recorded.

Current assessment

Trivially fk(n)≤Fk(n)f_k(n)\le F_k(n) and f2(n)=F2(n)=(n2)f_2(n)=F_2(n)=\binom n2. A line through at least kk of the points contains at least (k2)\binom k2 of the (n2)\binom n2 pairs, and no pair lies on two lines, so Fk(n)≤(n2)/(k2)F_k(n)\le\binom n2/\binom k2 and lim sup⁡Fk(n)/n2≤1/(k(k−1))\limsup F_k(n)/n^2\le1/(k(k-1)). The case k=3k=3 is Sylvester's orchard problem. Burr, Grünbaum and Sloane's cubic-curve construction, with the pair count, gives f3(n)=n2/6−O(n)f_3(n)=n^2/6-O(n) and F3(n)=n2/6−O(n)F_3(n)=n^2/6-O(n), so both limits equal 1/61/6 for k=3k=3 (claim page). Green and Tao's upper bound, with that construction, gives f3(n)=⌊n(n−3)/6⌋+1f_3(n)=\lfloor n(n-3)/6\rfloor+1 for all large nn (claim page). For k≥4k\ge4 the cited sources give only the trivial upper bound, so the limits for k≥4k\ge4 are open as far as they show. The site also points to Problem 101. The literature search behind this account covered the site's page, the two papers above and the formal-conjectures repository.

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