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Problem 960

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claims/: The 1 claim page of Problem 960, one per claimant's result; the problem's standing derives from them.


Statement. Let r,k≥2r,k\geq 2 be fixed. Let A⊂R2A\subset \mathbb{R}^2 be a set of nn points with no kk points on a line. Determine the threshold fr,k(n)f_{r,k}(n) such that if there are at least fr,k(n)f_{r,k}(n) many ordinary lines (lines containing exactly two points) then there is a set A′⊆AA'\subseteq A of rr points such that all (r2)\binom{r}{2} many lines determined by A′A' are ordinary.

Is it true that fr,k(n)=o(n2)f_{r,k}(n)=o(n^2), or perhaps even ≪n\ll n?

Status. Disproved: the site credits a construction of Alexeev, Putterman, Sawhney, Sellke and Valiant (April 2026), whose proof the authors attribute to an internal model at OpenAI, giving fr,k(n)≥n2/12−O(n)f_{r,k}(n)\geq n^2/12-O(n) for every r≥3r\geq3 and k≥4k\geq4; see the claim page.

Source. erdosproblems.com/960, accessed 2026-09-04. Cite as: T. F. Bloom, Erdős Problem #960, https://www.erdosproblems.com/960.

References.

Formalization. None recorded.

Current assessment

Disproved. The site formulation above asks for the threshold fr,k(n)f_{r,k}(n) of ordinary lines that forces, among nn points with no kk on a line, rr points all of whose connecting lines are ordinary, and whether fr,k(n)=o(n2)f_{r,k}(n)=o(n^2) or even ≪n\ll n, as Erdős hoped in [Er84] (p. 102). The answer is no for every r≥3r\geq3 and k≥4k\geq4: Theorem 2.1 of [APSSV26b], on the accepted claim page, gives for every n≥72n\geq72 an nn-point set with no four collinear, at least n2/12−10n/3n^2/12-10n/3 ordinary lines and a bipartite ordinary-line graph, so no three points span only ordinary lines, which rules out every r≥3r\geq3. The site's curator credits the bound, which the paper attributes to an internal model at OpenAI, and that credit is the reviewed evidence; the paper is a preprint with no refereed version found on 2026-10-06, and no Lean proof is recorded. The standing derives from that claim page. Known bounds: Turán's theorem gives fr,k(n)≤(1−1r−1)n22+1f_{r,k}(n)\leq(1-\tfrac1{r-1})\tfrac{n^2}2+1, so the order of fr,k(n)f_{r,k}(n) is n2n^2 for every fixed r≥3r\geq3 and k≥4k\geq4 and only the constant is open; the parameters k≤3k\leq3 and r=2r=2 are degenerate, as Section 2.1 of [APSSV26b] states. The site points to Problem 209 as related. A search on 2026-10-06 of the site's problem page and discussion thread, the arXiv record of [APSSV26b] and [Er84] (Period. Math. Hungar. 15 (1984), p. 102, through its library card) found no other claimed result on the problem.

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