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Problem 872

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claims/: The 2 claim pages of Problem 872, one per claimant's result; the problem's standing derives from them.


Statement. Consider the two-player game in which players alternately choose integers from {2,3,…,n}\{2,3,\ldots,n\} to be included in some set AA (the same set for both players) such that no a∣ba\mid b for a≠b∈Aa\neq b\in A.

The game ends when no legal move is possible. One player wants the game to last as long as possible, the other wants the game to end quickly. How long can the game be guaranteed to last for?

At least ϵn\epsilon n moves? (For ϵ>0\epsilon>0 and nn sufficiently large.) At least (1−ϵ)n2(1-\epsilon)\frac{n}{2} moves?

Status. Open on the site (OPEN; page last edited 24 April 2026; one proof claim is listed as full on the proof-claims thread). The frontmatter standing derives from the claim pages: the pending partial claim [[problems/divisors/E0872/claims/2026_02_14_price|Price's Shortener strategy]] would answer the second displayed question in the negative with Prolonger moving first, and the pending partial claim [[problems/divisors/E0872/claims/2026_07_24_buddhdev|Buddhdev's sublinear bound]] would answer both displayed questions in the negative while leaving the order of the game's length open; no full claim is recorded.

Source. erdosproblems.com/872, accessed 2026-09-04 and 2026-10-07. Cite as: T. F. Bloom, Erdős Problem #872, https://www.erdosproblems.com/872.

References.

  • [BPW16] Biró, Csaba and Horn, Paul and Wildstrom, D. Jacob, An upper bound on the extremal version of Hajnal's triangle-free game. Discrete Appl. Math. (2016), 20-28.
  • [Er92c] Erdős, P., Some of my forgotten problems in number theory. Hardy-Ramanujan J. 15 (1992), 34-50; the game is on p. 47. Library home: erdos_1992_my_forgotten_problems_number_theory.
  • [FuSe91] Füredi, Zoltán and Reimer, Dave and Seress, Ákos, Hajnal's triangle-free game and extremal graph problems. Congr. Numer. (1991), 123-128.

Formalization. Statement in formal-conjectures, which, at the commit of 18 September 2026 linked here, defines the value by a finite minimax recursion with Prolonger moving first, states the two displayed questions as separate theorems and adds a statement on the π(n)\pi(n) lower bound; it carries no formal_proof. The Lean project of the pending claim and the Lean proof of the 23/4823/48 bound posted on the thread are described on the claim pages; this corpus has built neither.

Current assessment

The question. The site formulation quoted above (page last edited 24 April 2026) asks for the guaranteed length of the game in which two players alternately add integers from {2,…,n}\{2,\ldots,n\} to a common set that must stay free of divisibility between its members, one player prolonging and the other shortening, and poses two thresholds, ϵn\epsilon n and (1−ϵ)n/2(1-\epsilon)n/2. Erdős does not say who moves first, and the site's remarks note that the answer may depend on it; the forum, the formal-conjectures file and the pending claim all take Prolonger to move first, and computations reported on the discussion thread (exact values up to n=120n=120) suggest that the Shortener-first value stays close to π(n)\pi(n) while the Prolonger-first value grows faster. The game is a number-theoretic form of Hajnal's triangle-free game; the site's remarks cite [FuSe91] for its ≫nlog⁡n\gg n\log n lower bound and [BPW16] for the upper bound (26121+o(1))n2(\tfrac{26}{121}+o(1))n^2 on the graph game, and call the type a saturation game. Erdős poses the game in [Er92c, p. 47] as a number-theoretic form of Hajnal's game and says he thinks the prolonging player can force (1−ϵ)n2(1-\epsilon)\frac n2 moves but cannot prove even ϵn\epsilon n.

What the site records. Every maximal set must contain the primes in (n/2,n](n/2,n], so L(n)≫n/log⁡nL(n)\gg n/\log n; a discussion-thread comment sharpens the argument to L(n)≥π(n)L(n)\ge\pi(n) by counting the largest prime powers up to nn. For the second threshold the site's remarks credit a Shortener strategy found by GPT-5.2 Pro at Liam Price's prompting (February 2026, Prolonger first) with the bound (2348+o(1))n(\tfrac{23}{48}+o(1))n; that result is the pending partial claim [[problems/divisors/E0872/claims/2026_02_14_price|Price's Shortener strategy]], and a thread comment of 17 February 2026 lowers its constant by changing the strategy's auxiliary set, as the claim page records. Buddhdev's manuscript of April 2026, announced on the thread on 23 April 2026, gives L(n)<0.19nL(n)<0.19n together with the lower bound L(n)≥(18−o(1))nlog⁡log⁡n/log⁡nL(n)\ge(\tfrac18-o(1))n\log\log n/\log n; it has no page of its own: its author's o(n)o(n) claim of 24 July 2026 supersedes its upper bound, which that claim page discloses, and its lower bound settles neither displayed question. On 12 July 2026 the author posted a note and a revised manuscript claiming L(n)≥cδn(log⁡log⁡n)2/log⁡nL(n)\ge c_\delta n(\log\log n)^2/\log n for every fixed 0<δ<1/40<\delta<1/4, after a K5K_5 computation refuted the hypothesis behind the April manuscript's conditional bound of that order; the claim is unreviewed and, being o(n)o(n), settles neither displayed question, so it has no page. A note posted on the thread on 29 April 2026 by Jonas Silva (user jonaslsa), signed with GPT 5.5 Pro, raises the constant to 12\tfrac12, L(n)≥(12−o(1))nlog⁡log⁡n/log⁡nL(n)\ge(\tfrac12-o(1))n\log\log n/\log n, and a thread post of the site's curator of the same day presents the argument as a game on the bipartite graph of primes p∼qp\sim q with pq∈(n/2,n]pq\in(n/2,n]; neither settles a displayed question, so neither has a claim page. A Lean proof of the 23/4823/48 bound posted on the thread in May 2026 is recorded on Price's page.

The pending claim. The partial claim [[problems/divisors/E0872/claims/2026_07_24_buddhdev|Buddhdev's sublinear bound]] (a Zenodo manuscript of 24 July 2026 produced with an AI research system, with a Lean project the author reports complete, posted as a forum proof claim on 2026-07-30 and reviewed by nobody) asserts L(n)=o(n)L(n)=o(n) with Prolonger first, which would answer both displayed questions in the negative and leaves the order of L(n)L(n) open, between nlog⁡log⁡n/log⁡nn\log\log n/\log n (or n(log⁡log⁡n)2/log⁡nn(\log\log n)^2/\log n if the lower-bound claim of 12 July holds) and o(n)o(n). The author agreed on the thread that the headline question is not closed, so the claim is recorded as partial and the standing stays open.

Scope of this assessment. This assessment rests on the problem page, its discussion thread and its proof-claims thread; on the pending claim's manuscript to its theorem, the outline of its argument and its verification notes, its Lean project unbuilt; and on Price's write-up as the thread and the site's remarks describe it. No independent review of any argument is recorded; the curator's remark on Price's result is commentary on a problem the site labels OPEN.

Linked library material

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