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2025_03_26_alexeev_conway_rosenfeld_sutherland_tao_uhr_ventullo: Alexeev, Conway, Rosenfeld, Sutherland, Tao, Uhr and Ventullo prove that t(n)/n equals 1/e minus c_0 over log n up to a smaller error, with an explicit c_0, answering both of the problem's questions in the affirmative.
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