Research notes on every problem, and a library of the papers behind them. Built from the open erdos repository.
Updated
Problem 489
claims/: The 3 claim pages of Problem 489, one per claimant's result; the problem's standing derives from them.
Statement. Let be a set such that $\lvert A\cap [1,x]\rvert=o(x^{1/2})$. Let
If then is it true that
exists (and is finite)?
Status. OPEN, in the site's label. The site notes that for the set of
prime squares, when is the squarefree numbers, Erdős proved the limit exists
(Publ. Math. Debrecen 2 (1951), 103--109; claim page
Erdős's squarefree case,
accepted and partial). A full proof claim posted to the site's proof-claims tab
on 15 July 2026 by Colin Snyder, produced with GPT 5.6 (custom harness), as the
tab names the system, answers yes with a Lean 4 proof bundle; the site has not
accepted it, nothing was built or audited here, and the claim page
Snyder's Lean proof
records it, together with the formal-conjectures collection's marking of the
problem as solved on the strength of a hosted copy of that proof, which is not
acceptance. A note of 20 April 2026 by Przemyslaw Chojecki, produced with
GPT-5.4 Pro, as Chojecki's thread comment says, claims a proof that the limit
always exists in and is finite for a structured class of ; it
is the partial claim page
Chojecki's note.
The frontmatter standing derives from the pending full claim, and it departs
from the label for that reason: Snyder's claim answers the Statement yes and
would settle it, so the derived standing is claimed with claim proved, while
the site, which has not accepted the claim, labels the problem OPEN.
Source. erdosproblems.com/489, accessed 2026-09-04; proof-claims tab accessed 2026-10-06. Cite as: T. F. Bloom, Erdős Problem #489, https://www.erdosproblems.com/489.
Formalization. The file
ErdosProblems/489.lean
of formal-conjectures, pinned to its commit of 2026-09-17 (on main as of
2026-10-07 the file differs only by a module header), defines sievedSet A
as the positive integers divisible by no member of A and GapSumSq A x
as the sum of the squared gaps between consecutive members below x, and
declares erdos_489 : answer(True) ↔ ∀ A, (counting function of A on [1,x]) =o[atTop] √x → (sievedSet A).Infinite → ∃ L : ℝ, Tendsto (GapSumSq A x / x) atTop (𝓝 L),
with x running over the naturals, under category research solved with
proof sorry and a formal_proof attribute pointing at the copy of
Snyder's Lean proof in the williamjblair/lean-proofs repository, linked on
the claim page; a second declaration states the squarefree case. The
site's indicator records a formalized statement. The solved marking records
that claim and is not acceptance evidence; nothing was built or audited
here.
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