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Problem 537

../

claims/: The 1 claim page of Problem 537, one per claimant's result; the problem's standing derives from them.


Statement. Let ϵ>0\epsilon>0 and NN be sufficiently large. If $A\subseteq {1,\ldots,N}$ has ∣A∣≥ϵN\lvert A\rvert \geq \epsilon N then must there exist a1,a2,a3∈Aa_1,a_2,a_3\in A and distinct primes p1,p2,p3p_1,p_2,p_3 such that

a1p1=a2p2=a3p3?a_1p_1=a_2p_2=a_3p_3?

Formulation. The site's wording of 2026-09-18 (the page shows no last-edited date). The three primes are distinct, which forces the three aia_i to be distinct (if a1=a2a_1=a_2 then p1=p2p_1=p_2). The question asks whether, for every ϵ>0\epsilon>0, every set of at least ϵN\epsilon N integers up to NN, N≥N0(ϵ)N\ge N_0(\epsilon), contains such a triple; a single ϵ\epsilon and a family of sets of density at least ϵ\epsilon without a triple, for infinitely many NN, answers it in the negative. In Erdős's 1973 wording the question is whether for k>cnk>cn there is always an mm with at least three solutions of pai=mpa_i=m, pp prime, ai∈Aa_i\in A; he notes that a positive answer would give three aa's with pairwise the same least common multiple, the question of Problem 536. The site cites [Er73] as its only source.

Status. The site's label is DISPROVED (LEAN). The status-defining source is Erdős's 1973 survey, printed p. 124, which reports a construction of I. Ruzsa: the squarefree integers q1⋯qrq_1\cdots q_r whose prime factors satisfy qi+1>2qiq_{i+1}>2q_i have positive density, and for their intersection with (n/2,n)(n/2,n) the equation pai=mpa_i=m has at most two solutions for every mm. The site's commentary reproduces the two-line argument, checked here. The standing derives from the claim page Ruzsa's construction, accepted on the site's acceptance of the construction (the 1973 chapter is a contribution to an edited proceedings volume whose refereeing no record found documents, so it is the source and not acceptance evidence), so the problem is solved, disproved; the external Lean formalization inspected statically at a pinned revision (below) is recorded on the claim page and is not acceptance evidence. No dispute was found. The (LEAN) suffix is a catalog label; nothing was built or kernel-checked here.

Source. erdosproblems.com/537, accessed 2026-09-18: the problem page (DISPROVED (LEAN), the site's label for a negative answer whose proof has been verified in Lean; no last-edited date shown; source key [Er73]; commentary citing Problem 536; a thanks line naming one contributor), its three-comment discussion thread (7 February 2026) and its empty proof-claim tab. Cite as: T. F. Bloom, Erdős Problem #537, https://www.erdosproblems.com/537, accessed 2026-09-18.

References.

Formalization. The site's (LEAN) suffix is a catalog label; see "Formalization and the Lean label" below for what was inspected. The file ErdosProblems/537.lean of formal-conjectures (main on 2026-09-18) declares erdos_537 : answer(False) ↔ ∀ ε : ℝ, 0 < ε → ∀ᶠ N : ℕ in atTop, ∀ A ⊆ Finset.Icc 1 N, (A.card : ℝ) ≥ ε * N → ∃ a₁ ∈ A, ∃ a₂ ∈ A, ∃ a₃ ∈ A, ∃ p₁ p₂ p₃ : ℕ, p₁.Prime ∧ p₂.Prime ∧ p₃.Prime ∧ p₁ ≠ p₂ ∧ p₁ ≠ p₃ ∧ p₂ ≠ p₃ ∧ a₁ * p₁ = a₂ * p₂ ∧ a₂ * p₂ = a₃ * p₃ under category research solved, with proof sorry and a formal_proof attribute naming the external file above; its docstring reproduces the site's commentary. The community database records the problem disproved with Lean since 6 February 2026, formal_status Lean since the same date, the statement formalized since 3 August 2026 and no formal-proof URL. The site's page marks the statement as formalized. Nothing was built or kernel-checked here.

Current assessment

The question (site formulation of 2026-09-18). The statement above; DISPROVED (LEAN), the site's label for a negative answer whose proof has been verified in Lean; no last-edited date. The commentary, paraphrased here: it notes that a yes answer would settle Problem 536, and it presents Ruzsa's construction, as Erdős reports it, as the disproof, writing out the two-line argument; the construction and the argument follow in the next paragraph. The thread: a question of 7 February 2026 whether the elements need to be squarefree; the answer the same day that the argument works with prime powers in the factorization; and a comment of 7 February 2026 by Boris Alexeev reporting that the prover Aristotle had formalized a proof of the result, linking the Lean file below and noting that the proof takes Chebyshev's upper bound for the number of primes, already in Mathlib, in place of the prime number theorem. The proof-claim tab is empty. The community database records the problem disproved with Lean since 6 February 2026.

Status-defining source (Er73, printed p. 124). Erdős poses the question: "Let a1<⋯<ak<na_1<\cdots<a_k<n, k>cnk>cn. Is it true that there always is an mm so that pai=mpa_i=m (pp prime) has at least three solutions?", adding that in a positive answer, since one may assume (p,ai)=1(p,a_i)=1, this mm would be the least common multiple of the three terms. He then reports that I. Ruzsa, whom he describes as a sixteen-year-old Hungarian mathematician, gave an easy example of a sequence a1<⋯<ak≤na_1<\cdots<a_k\le n with k>cnk>cn in which every mm has at most two representations pai=mpa_i=m, built from the squarefree integers

q1q2⋯qr,qi+1>2qi, i=1,…,r−1;r=1,2,…(4.4)q_1q_2\cdots q_r,\qquad q_{i+1}>2q_i,\ i=1,\ldots,r-1;\qquad r=1,2,\ldots \qquad(4.4)

Erdős asserts, each time as easy to see, that the integers (4.4) have positive density, so that cncn of them lie in (12n,n)(\tfrac12n,n), and that for this set pai=mpa_i=m has at most two solutions. The passage is paged, with its quotation, on the library's construction page. Written out here: let AA be the set of integers of the form (4.4) in (N/2,N)(N/2,N), of size ≫N\gg N by the positive density. Suppose p1a1=p2a2=p3a3=mp_1a_1=p_2a_2=p_3a_3=m with ai∈Aa_i\in A and distinct primes pip_i. Since p2p_2 and p3p_3 divide mm and differ from p1p_1, both divide a1a_1; being distinct prime factors of a number of the form (4.4), with p2<p3p_2<p_3 say, they satisfy p3>2p2p_3>2p_2 (the chain condition composes along the sorted prime factors). But p2a2=p3a3p_2a_2=p_3a_3 gives p3/p2=a2/a3∈(1,2)p_3/p_2=a_2/a_3\in(1,2) because N/2<a3<a2<NN/2<a_3<a_2<N; a contradiction. This is the site's argument and the contradiction step was checked here; it is elementary. The positive density of the set (4.4) is asserted by Erdős ("it is easy to see") and is proved in the Lean development below from Chebyshev's bound. Read depth: claims checked for the passage; the argument is a two-step deduction recorded above, not a proof reconstruction of a paper. The site's answer to Problem 536 remains open: Ruzsa's set has at most two solutions of pa=mpa=m, so it excludes triples with equal pairwise least common multiples of that special shape only.

Formalization and the Lean label. The site's (LEAN) suffix is a catalog label. The formal-conjectures file at the pinned commit is a statement with a sorry body whose formal_proof attribute names src/v4.29.1/ErdosProblems/Erdos537.lean in plby/lean-proofs at its revision of 30 June 2026. That file (108,554 bytes, 1,852 lines) declares itself "a Lean formalization of a solution to Erdős Problem 537", names the informal author as Imre Z. Ruzsa and the formal authors as the prover Aristotle and Boris Alexeev, imports Mathlib, defines SpecialSet as the squarefree naturals whose sorted prime factors form a chain with 2 * p < q, proves that the set has positive natural density (through a Chebyshev-type upper bound for primes, per its declaration names and the thread) and that SpecialFinset N, its part in (N/2,N](N/2,N], admits no triple with distinct primes, and proves erdos_537 : ¬(∀ ε > 0, ∃ N₀, ∀ N ≥ N₀, ∀ A, A ⊆ Finset.range (N + 1) → (A.card : ℝ) ≥ ε * N → ∃ a₁ ∈ A, ∃ a₂ ∈ A, ∃ a₃ ∈ A, ∃ p₁ p₂ p₃, p₁.Prime ∧ p₂.Prime ∧ p₃.Prime ∧ p₁ ≠ p₂ ∧ p₁ ≠ p₃ ∧ p₂ ≠ p₃ ∧ a₁ * p₁ = a₂ * p₂ ∧ a₂ * p₂ = a₃ * p₃); it contains no sorry, no axiom declaration and no native_decide, and its closing comment records #print axioms as propext, Classical.choice and Quot.sound. Its sets range over Finset.range (N + 1), that is {0,…,N}\{0,\ldots,N\}, where the collection's statement uses {1,…,N}\{1,\ldots,N\}; the difference is immaterial for a negation, since a set containing 00 has the triple a1=a2=a3=0a_1=a_2=a_3=0 with any three primes, so the counterexample sets lie in {1,…,N}\{1,\ldots,N\} in both readings (an observation made here). The file was not built or independently audited here, no bridging statement exists, and no local kernel credit is claimed. The community database records formal_status Lean and no formal-proof URL.

Search scope. None of the routes below found a dispute of the construction, a published account by Ruzsa, or a second source.

  • The site: problem page, discussion thread and proof-claim tab; the formal-conjectures file at the pinned commit; the community database record.
  • GitHub API: the pinned revision of plby/lean-proofs (its date) and the file Erdos537.lean at that revision, searched for sorry, axiom and native_decide.
  • arXiv: the API queries abs:"Erdős problem" AND (abs:535 OR abs:536 OR abs:538 OR abs:539) and abs:"pairwise" AND abs:"greatest common divisor" AND abs:Erdos (no records; titles and abstracts only).
  • The primary source at the page cited: [Er73] printed p. 124.

Not searched: MathSciNet, zbMATH, Google Scholar, X. Not held: no paper by Ruzsa on the construction is cited by the site or by [Er73]; the construction is known here only through Erdős's report.

Remaining gaps. (1) The status rests on Erdős's published report of an unpublished construction; the argument is elementary and was checked here at the level recorded above, but no independent whole-argument review exists, and the positive-density step is Erdős's assertion (proved in the external Lean file, not here). (2) The [Er73] card carries the result page and its Bears-on row for this problem; the passage is quoted above with its printed locator. (3) The Lean development is inspected statically only.

Linked library material

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