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Problem 1101

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claims/: The 1 claim page of Problem 1101, one per claimant's result; the problem's standing derives from them.


Statement. If u={u1<u2<⋯ }u=\{u_1<u_2<\cdots\} is a sequence of integers such that (ui,uj)=1(u_i,u_j)=1 for all i≠ji\neq j and ∑1ui<∞\sum \frac{1}{u_i}<\infty then let {a1<a2<⋯ }\{a_1<a_2<\cdots\} be the sequence of integers which are not divisible by any of the uiu_i. For any xx define txt_x by

u1⋯utx≤x<u1⋯utxutx+1.u_1\cdots u_{t_x}\leq x< u_1\cdots u_{t_x}u_{t_x+1}.

We call such a sequence uiu_i good if, for all ϵ>0\epsilon>0, if xx is sufficiently large then

max⁡ak<x(ak+1−ak)<(1+ϵ)tx∏i(1−1ui)−1.\max_{a_k<x} (a_{k+1}-a_k) < (1+\epsilon)t_x \prod_{i}\left(1-\frac{1}{u_i}\right)^{-1}.

Is there a good sequence such that un<nO(1)u_n< n^{O(1)}? Is there a good sequence such that un≤eo(n)u_n\leq e^{o(n)}?

Status. Open. The site labels the problem OPEN (page last edited 19 October 2025). Its two questions are the problem's two parts; Erdős expected the first to have a negative answer and the second a positive one. The second, whether some good sequence has un≤eo(n)u_n\leq e^{o(n)}, has one pending partial claim, Li's subexponential good sequence of 2026, which constructs a good sequence of primes with un=exp⁡((1+o(1))n)u_n=\exp((1+o(1))\sqrt n). The first, whether some good sequence has un<nO(1)u_n<n^{O(1)}, has no claim.

Source. erdosproblems.com/1101, accessed 2026-09-04. Cite as: T. F. Bloom, Erdős Problem #1101, https://www.erdosproblems.com/1101.

References.

  • [Er81h] Erdős, P., Some problems and results on additive and multiplicative number theory. Analytic number theory (Philadelphia, Pa., 1980) (1981), 171-182.

Formalization. Statement in formal-conjectures.

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