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Problem 1023

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claims/: The 1 claim page of Problem 1023, one per claimant's result; the problem's standing derives from them.


Statement. Let F(n)F(n) be the maximal size of a family of subsets of {1,…,n}\{1,\ldots,n\} such that no set in this family is the union of other members of the family. Is it true that there is a constant c>0c>0 such that

F(n)∼c2nn1/2?F(n)\sim c \frac{2^n}{n^{1/2}}?

Formulation. The printed source [Er71, item 18] states the unpublished Erdős–Kleitman bounds and the conjectured asymptotic max⁡ln=(1+o(1)) c 2n/n3/2\max l_n=(1+o(1))\,c\,2^n/n^{3/2} both with the exponent 3/23/2 in place of 1/21/2; the site prints 1/21/2 and reads the printed exponent as a misprint, since the middle layer alone gives F(n)≥(n⌊n/2⌋)F(n)\ge\binom{n}{\lfloor n/2\rfloor}. With the exponent 3/23/2 the conjecture is false; the Statement carries the site's exponent 1/21/2.

Status. The site labels the problem SOLVED (LEAN) and credits Hunter's observation in its thread that the solution of Problem 447 settles it: the answer is yes, F(n)∼(n⌊n/2⌋)F(n)\sim\binom{n}{\lfloor n/2\rfloor}, so c=2/πc=\sqrt{2/\pi}.

Source. erdosproblems.com/1023, accessed 2026-09-04. Cite as: T. F. Bloom, Erdős Problem #1023, https://www.erdosproblems.com/1023.

References.

  • [Er71] Erdős, P., Some unsolved problems in graph theory and combinatorial analysis. Combinatorial Mathematics and its Applications (Proc. Conf., Oxford, 1969) (1971), 97-109.
  • [Kl71] Kleitman, Daniel, Collections of subsets containing no two sets and their union. Proceedings of the LA Meeting AMS (1971), 153-155.

Formalization. Statement in formal-conjectures, marked solved there as of its commit of 18 September 2026 and pointing at a third-party Lean proof, linked from the claim page, which this corpus has not built.

Current assessment

The question is whether F(n)F(n), the largest size of a family of subsets of {1,…,n}\{1,\ldots,n\} with no member the union of other members, is asymptotic to a constant times 2n/n1/22^n/n^{1/2}. It is answered yes. The middle layer gives F(n)≥(n⌊n/2⌋)F(n)\ge\binom{n}{\lfloor n/2\rfloor}, and such a family is union-free in the sense of Problem 447, so Kleitman's theorem [Kl71] gives F(n)≤(1+o(1))(n⌊n/2⌋)F(n)\le(1+o(1))\binom{n}{\lfloor n/2\rfloor}; hence F(n)∼(n⌊n/2⌋)∼2/π 2n/n1/2F(n)\sim\binom{n}{\lfloor n/2\rfloor}\sim\sqrt{2/\pi}\,2^n/n^{1/2}. The accepted claim is Hunter's deduction from Kleitman's theorem, whose page records the argument, the curator's acceptance and the third-party Lean file that formalizes Kleitman's proof and the deduction; the site's Lean qualification is that file, which the corpus has not built. Erdős and Kleitman's unpublished bounds F(n)≍2n/n1/2F(n)\asymp2^n/n^{1/2}, which the site records from [Er71], are the historical state of the problem and have no page: they were never published, and the corrected form of their conjecture is the claim above. The printed statement is on the card Erdős 1971. As of 2026-10-06 the site's thread held five comments and the site listed no proof claim; the community database has recorded the problem as solved (Lean) since 2026-02-10.

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