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Croot 2004 sums reciprocal powers modulo prime
theorem_2: Croot's 2004 theorem that for every epsilon in (0, 1] and every integer k at least 1 there is N(epsilon, k) such that for every prime p and every residue a modulo p some integers x_1, ..., x_N in [1, p^epsilon] have a congruent to the sum of the inverses of the x_i^k modulo p (for the small primes, only with at most N summands); with k equal to 1 the affirmative answer to Problem 1180 for every prime.
Ernie Croot, Sums of the form modulo a prime, Integers 4 (2004), Paper A20; arXiv:math/0403360 (v1 22 March 2004, under the title "Reciprocal power sums modulo a prime"; v2 21 October 2004, with the comment "Light Corrections. The parameter h in the definition of T had to be a lot larger", the arXiv listing read). The site's Problem 1180 commentary names the author without a key.
The copy read for this card is a six-page manuscript (Ghostscript 7.07 output with a text layer) headed with the title above, the Georgia Institute of Technology affiliation and the abstract, without an arXiv stamp or journal header; the locators below are its own page numbers 1--6. Its text is neither arXiv version (both compared by text extraction on 2026-10-07): it has v2's title, layout and Comments paragraph, but keeps v1's closing sentence of the abstract ("This extends a result of I. Shparlinski [5]"), v1's five references, the slip in Theorem 2, and v1's , the smallest integer above (p. 4). v2 takes , counts the terms of the elements of as where the manuscript has , prints and adds an example to the Comments and a sixth reference (Granville); the locators below hold in v2 too, except that its proof of Lemma 1 starts on p. 5 and its acknowledgement is on p. 6. Provenance: 79,896 bytes; from the survey download set of 2026-09-05 (arXiv:math/0403360, https://arxiv.org/abs/math/0403360; the exact download URL is not recorded). The published version, Integers 4 (2004), Paper A20, is listed in the journal's volume 4 contents and deposited at Zenodo (DOI 10.5281/zenodo.7642509, deposit dated 15 February 2023; both records read); its PDF ("Received: 5/24/04, Revised: 10/11/04, Accepted: 10/21/04, Published: 11/1/04", p. 1) carries v2's text (compared by text extraction on 2026-10-07), so the manuscript predates the revision. No notice is printed in the manuscript. The arXiv abstract page of v2 (https://arxiv.org/abs/math/0403360v2, read 2026-10-02) links its "view license" to arXiv's assumed license (http://arxiv.org/licenses/assumed-1991-2003/), and the Zenodo record (read 2026-10-07) names CC-BY-4.0 for the published PDF; these govern the arXiv files and the published PDF, not this manuscript, so the term is unstated.
Read status: claims checked for Theorem 2 and for the introduction's account of the Erdős--Graham question and of Shparlinski's answer (pp. 1--2, read clause by clause in the text layer and on the page images of pp. 1--2); the proof (pp. 2--5) was read for structure and not checked.
Contents
- Abstract and introduction (pp. 1--2): the introduction (p. 1) takes its question from the Erdős--Graham monograph [2] and poses it as: "Is it true that for every there exists a number such that for every prime number , every residue class can be expressed as , where the 's are positive integers ?" It credits the affirmative answer to Shparlinski [5], whose proof rests on a result of Karatsuba [4] in the simplified form due to Friedlander and Iwaniec [3]. Shparlinski asked whether the result extends to reciprocal powers; the paper answers this with the sum-product estimate of Bourgain, Katz and Tao, quoted as Theorem 1: if for then with , .
- Theorem 2 (p. 2): for every and every integer there is such that for every prime and every integer there are integers with . The print writes "" for the integers of the display; the abstract writes . A Comment (p. 2) records a more general statement suggested by Shparlinski, for multiplicatively closed sets with at least elements up to , as something that "can perhpas [sic] be proved", not as a theorem.
- Proof of Theorem 2 (Section II, pp. 2--5): the reduction to sufficiently large and to small (the conclusion for a smaller implies it for every larger one); the set of sums of inverse th powers of distinct primes , with (1) because the sums are distinct modulo ; the iteration or , whichever is larger, which by Theorem 1 exceeds after at most steps; the set of sums of inverse th powers of integers ; Lemma 1 (p. 4), proved by exponential sums with Parseval's identity and the Cauchy--Schwarz inequality: if then every residue class is a sum of products with ; and the conclusion (p. 5) that every residue is a sum of at most terms with , where depends only on and .
- The closing thanks and the references (pp. 5--6): [1] Bourgain, Katz and Tao, "Preprint on the Arxives"; [2] Erdős and Graham, Old and New Problems and Results in Combinatorial Number Theory, Univ. Genève, 1980; [3] Friedlander and Iwaniec, Analytic Number Theory (Kyoto, 1996), Cambridge Univ. Press, 1997; [4] Karatsuba, Izv. Ross. Akad. Nauk Ser. Mat. 59 (1995), 61--80; [5] Shparlinski, Arch. Math. (Basel) 78 (2002), 445--448.
Compiled scope
Theorem 2 and the introduction's attributions are compiled as statements with a proof pointer; no step of the proof was checked and nothing here is independently reviewed. The theorem gives without an explicit value (the proof's depends on the constants of Theorem 1). The summands are not required to be distinct. The theorem is stated for every prime , the finitely many small primes being absorbed by enlarging (p. 2); that step needs read as a bound on the number of summands, since for , and for at every , the only admissible is , and exactly of them give the single residue . The paper does not state the bound that the site's Problem 1180 commentary attributes to Croot; Glibichuk's introduction attributes that bound to Croot's 1999 Mathematika paper, filed as crootiii_1999_questions_erdos_graham_about_egyptian_fractions.
Bears on. #1180 (Theorem 2 with , p. 2: at most summands suffice for every prime and every residue when , the small primes needing the at-most reading; the introduction's attribution of the first affirmative answer to Shparlinski [5]).
No file of this source is held: no license on record covers the manuscript read (the published version's CC-BY-4.0 deposit would allow holding that edition), and the card cites the edition it names above.