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Problem 81

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claims/: The 5 claim pages of Problem 81, one per claimant's result; the problem's standing derives from them.


Statement. Let GG be a chordal graph on nn vertices - that is, GG has no induced cycles of length greater than 33. Can the edges of GG be partitioned into n2/6+O(n)n^2/6+O(n) many cliques?

Status. The site labels the problem OPEN (page last edited 28 December 2025; proof-claims tab and thread as of 2026-10-07), and the frontmatter standing is derived from the five claim pages under claims/: three pending full claims assert the answer yes, so the standing is claimed, and none is refereed, independently reviewed or adopted by the site. In order of posting: Agbanwa's Zenodo note, n2/6+O(n)n^2/6+O(n) for the chordal graphs with a maximum clique whose edge deletion lowers the clique number by at most one, a class that excludes the extremal split graphs (claim page, partial, posted on the thread and not registered on the tab); Traverso's Paper III, n2/6+O(n)n^2/6+O(n) for split graphs with a Lean freeze (claim page, partial); the manuscript registered by Morluto, Luo, Huang and Lee, whose author line reads "Anonymous", generated with GPT-5.6 and GPT-6 Astra, giving the eventual maximum ⌊n(n+1)/6⌋\lfloor n(n+1)/6\rfloor and hence n2/6+O(n)n^2/6+O(n) for all chordal graphs, with a Lean proof conditional on three literature theorems (claim page, full); Okechukwu's arXiv preprint on graphs of bounded simplicial defect, whose chordal case gives n2/6+n/6+O(1)n^2/6+n/6+O(1), announced on the thread with a priority dispute (claim page, full); and Traverso's Paper IV, ⌊n(n+1)/6⌋+b\lfloor n(n+1)/6\rfloor+b at every order with pieces of order at most four and a Lean proof the author reports as unconditional (claim page, full). Two results get no claim page because they settle no instance of the question. The proof-claims tab's entry of 10 August 2026 by Cipollini (claim 201), an Overleaf manuscript partitioning the edges of every chordal graph into n2/6+o(n2)n^2/6+o(n^2) cliques, written by him with LaTeX assistance and minor polishing by GPT-5.6 Sol as the tab says, gives the sharp quadratic coefficient and names the gap between o(n2)o(n^2) and O(n)O(n) as the remaining difficulty; it proves the O(n)O(n) error for no class of chordal graphs, and the later full claims credit it as an independent first-order bound. The thread's comment of 19 June 2026, not registered on the tab, reports an explicit form (1/4−c)n2(1/4-c)n^2 with c≥1/133c\ge1/133 of the bound of Erdős, Ordman and Zalcstein, obtained with ChatGPT 5.5 Pro and formalized by Aristotle, as the comment says, which sharpens a known weaker bound. The site states that a listing on the proof-claims tab is no guarantee of correctness.

Source. erdosproblems.com/81, accessed 2026-09-04. Cite as: T. F. Bloom, Erdős Problem #81, https://www.erdosproblems.com/81.

References.

  • [CEO94] Chen, Guan-Tao and Erdős, Paul and Ordman, Edward T., Clique partitions of split graphs. Combinatorics, graph theory, algorithms and applications (Beijing, 1993) (1994), 21-30. library card.
  • [EOZ93] Erdős, Paul and Ordman, Edward T. and Zalcstein, Yechezkel, Clique partitions of chordal graphs. Combin. Probab. Comput. (1993), 409-415.

Formalization. None recorded.

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