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Problem 136

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claims/: The 3 claim pages of Problem 136, one per claimant's result; the problem's standing derives from them.


Statement. Let f(n)f(n) be the smallest number of colours required to colour the edges of KnK_n such that every K4K_4 contains at least 5 colours. Determine the size of f(n)f(n).

Formulation. The wording does not say how precisely the size is to be determined. The linear order was already known in the source the site cites: [Er97b] (item 12) prints 23n<f(n)<n\frac23n<f(n)<n, and Erdős and Gyárfás [EG97] proved f(n)≥56(n−1)f(n)\ge\frac56(n-1) for all n≥4n\ge4 and f(n)≤nf(n)\le n for odd nn. The question, as [Er97b] frames it (Erdős expected the upper bound to be nearer the truth, Gyárfás the lower), is the constant cc in f(n)∼cnf(n)\sim cn, and the site reads it so, labeling the problem solved on f(n)∼56nf(n)\sim\frac56n. The exact value of f(n)f(n) is not known.

Status. Solved. Erdős and Gyárfás [EG97] proved f(n)≥56(n−1)f(n)\ge\frac56(n-1) for all n≥4n\ge4 and f(n)≤nf(n)\le n for odd nn, and reported f(9)=8f(9)=8 ([[problems/extremal_graph_theory/E0136/claims/1997_12_01_erdos_gyarfas|claim page]]); Erdős's own report [Er97b] (item 12) prints the weaker bounds 23n<f(n)<n\frac23n<f(n)<n and says that he believed the upper bound closer to the truth while Gyárfás believed in the lower bound. Bennett, Cushman, Dudek and Prałat [BCDP22] proved f(n)=56n+o(n)f(n)=\frac56n+o(n) ([[problems/extremal_graph_theory/E0136/claims/2022_07_06_bennett_cushman_dudek_pralat|claim page]]), and Joos and Mubayi [JoMu22] gave a much shorter second proof of the same asymptotic ([[problems/extremal_graph_theory/E0136/claims/2022_08_26_joos_mubayi|claim page]]); both are refereed (J. Combin. Theory Ser. B 169 (2024) and Proc. Amer. Math. Soc. 152 (2024)). The site reads the instruction to determine the size of f(n)f(n) as asking for the constant in f(n)∼cnf(n)\sim cn and labels the problem solved; the exact value of f(n)f(n) is not known. The site's thread holds one comment, a typographical remark of 23 July 2026.

Source. erdosproblems.com/136, accessed 2026-09-04. Cite as: T. F. Bloom, Erdős Problem #136, https://www.erdosproblems.com/136.

References.

  • [BCDP22] Bennett, P. and Cushman, R. and Dudek, A. and Pralat, P., The Erdős-Gyárfás function f(n,4,5)=56n+o(n)f(n,4,5)=\frac{5}{6}n+o(n) - so Gyárfás was right. arXiv:2207.02920 (2022); J. Combin. Theory Ser. B 169 (2024), 253-297, DOI 10.1016/j.jctb.2024.07.001. Library home: bennett_2022_erdos_gyarfas_function_so_gyarfas_was.
  • [EG97] Erdős, P. and Gyárfás, A., A variant of the classical Ramsey problem. Combinatorica 17 (1997), no. 4, 459-467, DOI 10.1007/BF01195000.
  • [Er97b] Erdős, Paul, Some old and new problems in various branches of combinatorics. Discrete Math. 165/166 (1997), 227--231, DOI 10.1016/S0012-365X(96)00173-2; item 12, p. 231: the definition of f(n)f(n), the bounds 23n<f(n)<n\frac23n<f(n)<n, f(9)=8f(9)=8 and the two authors' expectations. Library home: erdos_1997_some_old_new_problems_various_branches_combinatorics.
  • [JoMu22] Joos, F. and Mubayi, D., Ramsey theory constructions from hypergraph matchings. arXiv:2208.12563 (2022); Proc. Amer. Math. Soc. 152 (2024), no. 11, 4537-4550, DOI 10.1090/proc/16413. Library home: joos_2022_ramsey_theory_constructions_hypergraph_matchings.

Formalization. The formal-conjectures statement file ErdosProblems/136.lean, added on 2026-09-19 and linked from the site's page as the formalized statement, marks erdos_136 (that f(n)/n→5/6f(n)/n\to5/6) research solved with a formal_proof pointer to the declaration erdos_136 of Erdos136.lean in Boris Alexeev's repository plby/lean-proofs, a Lean development that declares itself a formalization of Bennett, Cushman, Dudek and Prałat's result and is linked from their claim page. Nothing is built, kernel-checked or audited here; the standing rests on the two refereed papers.

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