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Problem 13

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claims/: The 1 claim page of Problem 13, one per claimant's result; the problem's standing derives from them.


Statement. Let A⊆{1,…,N}A\subseteq \{1,\ldots,N\} be such that there are no a,b,c∈Aa,b,c\in A such that a∣(b+c)a\mid(b+c) and a<min⁡(b,c)a<\min(b,c). Is it true that $\lvert A\rvert\leq N/3+O(1)$?

Formulation. The site's wording, accessed 2026-09-18 (page last edited 8 April 2026), is unambiguous. The condition quantifies over all a,b,c∈Aa,b,c\in A with a<min⁡(b,c)a<\min(b,c) and does not require b≠cb\ne c, so a pair a<ba<b with a∣2ba\mid2b is also forbidden; this is Bedert's Definition 1 ("no three numbers x,y,z∈Ax,y,z\in A with z<x,yz<x,y and z∣x+yz\mid x+y") and the formal-conjectures predicate IsForbiddenTripleFree. Erdős's own finite conjecture is a separate variant, not a reading of the site's wording: it forbids a term dividing the sum of two distinct larger terms. It is the 1970 paper's (1), max⁡A(x)=[13x]+1\max A(x)=[\tfrac13x]+1, attained by the [13x]+1[\tfrac13x]+1 largest integers up to xx, and the 1975, 1977 and 1980 restatements, each in substance k≤[x/3]+1k\le[x/3]+1, with equality for x=3nx=3n and the integers 2n,2n+1,…,3n2n,2n+1,\ldots,3n; the 1992 paper prints the strict "k<[x/3]+1k<[x/3]+1", and the 1997 paper [Er97b] prints "max⁡k≤m/3+0(1)\max k\le m/3+0(1)" [sic] with the example 2m/3<ai≤m2m/3<a_i\le m (p. 230), the site's O(1)O(1) form with a half-open example that excludes 2m/32m/3. The two questions differ when 3∣N3\mid N (whether they agree otherwise is not decided by the source): the set {2n,…,3n}\{2n,\ldots,3n\}, N=3nN=3n, has n+1n+1 elements and no term dividing the sum of two distinct larger terms, but 2n∣3n+3n2n\mid3n+3n (an observation made here; it is what Bedert's remark on p. 2 about a "typo" in Erdős's example amounts to). The standing judges the site's question, which asks only for N/3+O(1)N/3+O(1), and Bedert proves that bound. Whether the same bound holds for Erdős's distinct-terms variant does not follow from Bedert's theorem as stated, and no result on that variant is recorded. The site's commentary also records the rr-fold generalization from the 1992 paper, in which no a∈Aa\in A divides a sum b1+⋯+brb_1+\cdots+b_r of rr elements of AA larger than aa, asking whether ∣A∣≤N/(r+1)+O(1)|A|\le N/(r+1)+O(1), which the formal-conjectures file carries as the open variant erdos_13.variants.general; the 1992 page prints k≤x/r+O(1)k\le x/r+O(1) with the example x(1−1/r)≤ai≤xx(1-1/r)\le a_i\le x, a form that is inconsistent for r=2r=2 (see the 1992 card), so the site's N/(r+1)N/(r+1) is taken as the intended reading.

Status. PROVED (LEAN). Bedert's Theorem 1 (2023) gives an absolute constant CC with ∣A∣≤N/3+C|A|\le N/3+C for every NN and every A⊆{1,…,N}A\subseteq\{1,\ldots,N\} with property P, and his Theorem 2 gives ∣A∣≤⌈N/3⌉|A|\le\lceil N/3\rceil for all sufficiently large NN, sharp for the set {⌊2N/3⌋+1,…,N}\{\lfloor2N/3\rfloor+1,\ldots,N\}. The status-defining source is an arXiv preprint (v1, 17 January 2023); Thomas Bloom, the site's curator, accepted it as the resolution, naming Bedert's paper in the commentary as the proof that the answer is yes, the formal-conjectures collection marks the statement research solved, and an outside Lean proof of the N/3+CN/3+C statement, not built here, is linked from the claim page. The claim page Bedert 2023 records the acceptance with this preprint qualification. The site's (LEAN) suffix is a catalog label explained under Formalization and the Lean label below.

Source. erdosproblems.com/13, accessed 2026-09-18: the problem page (labeled PROVED (LEAN), with the site's standard note for that label, that the answer is yes and the proof has been checked in Lean; a prize; last edited 8 April 2026; source keys [Er73], [Er75b], [Er77c], [Er80, p. 113], [Er92c], [Er95c], [Er97], [Er97b], [Er97e], [Er98], with [Be23] cited in the commentary; OEIS A002264), its empty discussion thread and its empty proof-claim tab. Cite as: T. F. Bloom, Erdős Problem #13, https://www.erdosproblems.com/13, accessed 2026-09-18.

References.

  • [Be23] Bedert, B., On a problem of Erdős and Sárközy about sequences with no term dividing the sum of two larger terms. arXiv:2301.07065v1 (17 January 2023), 43 pp.; Definition 1, p. 1; Theorems 1 and 2, p. 2. No journal version found. Library home: bedert_2023_problem_erdos_sarkozy_about_sequences_no.
  • [ErSa70] Erdős, P. and Sárközi, A., On the divisibility properties of sequences of integers. Proc. London Math. Soc. (3) 21 (1970), no. 1, 97--101; conjecture (1), p. 97, and the [13x]+1[\tfrac13x]+1 example with Szemerédi's remark, p. 98. Library home: erdos_1970_divisibility_properties_sequences_integers.
  • [Er92c] Erdős, P., Some of my forgotten problems in number theory. Hardy-Ramanujan J. (1992), 34--50; Section 4, printed p. 42: the conjecture k<[x/3]+1k<[x/3]+1, printed without a prize, and the rr-fold version. Library home: erdos_1992_my_forgotten_problems_number_theory.
  • [Er73] Erdős, P., Problems and results on combinatorial number theory (1973), 117--138; printed p. 133: "Probably max⁡k=x/3+o(1)\max k=x/3+\mathrm o(1)" [sic], read as O(1)O(1) since max⁡k\max k is an integer. Library home: erdos_1973_problems_results_combinatorial_number_theory.
  • [Er75b] Erdős, P., Problems and results in combinatorial number theory (1975), 295--310; printed p. 303: "n≤[X3]+1n\le[\tfrac X3]+1. The n+1n+1 integers 2n,2n+1,…,3n2n,2n+1,\ldots,3n show that our conjecture, if true, is best possible", with Szemerédi's partial result. Library home: erdos_1975_problems_results_combinatorial_number_theory.
  • [Er77c] Erdős, P., Problems and results on combinatorial number theory III (1977), 43--72; printed p. 53: "Then k≤[x3]+1k\le[\tfrac x3]+1. Equality, say, if x=3nx=3n and the aa's are the integers 2n,2n+1,…,3n2n,2n+1,\ldots,3n". Library home: erdos_1977_problems_results_combinatorial_number_theory_iii.
  • [Er80] Erdős, P., A survey of problems in combinatorial number theory. Ann. Discrete Math. 6 (1980), 89--115; printed p. 113: "The conjecture k≤[13x]+1k\le[\tfrac13x]+1 is still open". Library home: erdos_1980_survey_problems_combinatorial_number_theory.
  • [Er97b] Erdős, P., Some old and new problems in various branches of combinatorics. Discrete Math. 165/166 (1997), 227--231, DOI 10.1016/S0012-365X(96)00173-2; item 9, printed p. 230 (PDF p. 4 of the publisher's open-archive file): "Let a1<a2<⋯<ak≤ma_1<a_2<\cdots<a_k\le m be such that no aia_i divides the sum of two larger aa's. Is it true that max⁡k≤m/3+0(1)\max k\le m/3+0(1) [sic]? The integers 2m/3<ai≤m2m/3<a_i\le m show that our conjecture is the best possible if it is true." No prize is printed. Library home: erdos_1997_some_old_new_problems_various_branches_combinatorics; result page Item 9.
  • [Er95c], [Er97], [Er97e], [Er98]: Erdős's problem papers of 1995--1998 cited by the site; not held (see Problem 12 for the entries).

Formalization. The site's (LEAN) suffix is a catalog label; see "Formalization and the Lean label" below for the Lean files. The file ErdosProblems/13.lean of formal-conjectures, at the linked revision of 17 September 2026, defines IsForbiddenTripleFree (A : Finset ℕ) : Prop := ∀ a ∈ A, ∀ b ∈ A, ∀ c ∈ A, a < min b c → ¬ (a ∣ b + c) and declares erdos_13 : ∃ C : ℝ, ∀ N : ℕ, ∀ A ⊆ Icc 1 N, IsForbiddenTripleFree A → (A.card : ℝ) ≤ (N : ℝ) / 3 + C under category research solved with proof sorry and no formal_proof attribute, and the open variant erdos_13.variants.general (the rr-fold question with N/(r+1)+CN/(r+1)+C). On 18 September 2026 formal-conjectures registered Alexeev's Erdos13.lean (below) as the statement's formal_proof, so the file on main carries that attribute from that date. The community database (accessed 2026-09-18) lists the problem as "proved (Lean)", the statement as formalized and formal_status as Lean, as of last updates dated 23 August, 2 February and 23 August 2026, without recording when each state changed; it has no field for a formal proof's location. Nothing was built here.

Current assessment

The question (site formulation of 2026-09-18). The statement above; PROVED (LEAN), a prize, last edited 8 April 2026. The commentary attributes the question to Erdős and Sárközy, notes that the integers in (2N/3,N](2N/3,N] form such a set, and names Bedert's paper [Be23] as the proof that the answer is yes; it points to Problem 12 for the infinite version, to Problem 131 as related, and to [Er92c] for the rr-fold version, in which no element of AA divides a sum of rr larger elements and the question is whether ∣A∣≤N/(r+1)+O(1)|A|\le N/(r+1)+O(1). Thread and proof-claim tab: empty. The site's OEIS link A002264 is the sequence ⌊n/3⌋\lfloor n/3\rfloor.

The origin. Erdős and Sárközi 1970, p. 97, display (1): "We believe that if AA has property P then max⁡A(x)=[13x]+1\max A(x)=[\tfrac13x]+1"; p. 98: "It is perhaps surprising that we could not prove (1). To show that max⁡A(x)≥[13x]+1\max A(x)\ge[\tfrac13x]+1 is easy---it suffices to let AA be the [13x]+1[\tfrac13x]+1 greatest integers not exceeding xx. Szemerédi has proved (oral communication) that if A(x)>[13x]+1A(x)>[\tfrac13x]+1 then there are three distinct terms ai,aj,ala_i,a_j,a_l such that ai∣(aj+al)a_i\mid(a_j+a_l) but (aj+al)/ai≠2(a_j+a_l)/a_i\ne2", a conclusion Bedert (p. 2) calls "significantly weaker than what would be needed", since the dividing term need not be the smallest. Erdős repeated the finite conjecture, in substance k≤[x/3]+1k\le[x/3]+1, with the example 2n,…,3n2n,\ldots,3n in 1975 (p. 303: "The proof presents difficulties which we have not been able to overcome"), 1977 (p. 53) and 1980 (p. 113: "still open"), wrote "Probably max⁡k=x/3+o(1)\max k=x/3+\mathrm o(1)" [sic] in 1973 (p. 133) and "k<[x3]+1k<[\tfrac x3]+1. It is very annoying that we have not been able to prove or disprove this simple conjecture" in 1992 (p. 42), where he also asks the rr-fold version. Bedert's introduction says Erdős offered a prize in his final open problems paper for the N/3+CN/3+C form; [Er97b] (item 9, p. 230) prints the m/3+O(1)m/3+O(1) form with the example 2m/3<ai≤m2m/3<a_i\le m and no prize, so the final open problems paper is another of the 1997--1998 items, which are not held, and the prize is taken from the site.

Status-defining source. Bedert 2023, Theorem 1 (p. 2): there is an absolute constant CC such that for all n∈Nn\in\mathbb N, if A⊂{1,…,n}A\subset\{1,\ldots,n\} has property P then ∣A∣≤n3+C|A|\le\frac n3+C; and Theorem 2: for all sufficiently large nn such an AA has ∣A∣≤⌈n/3⌉|A|\le\lceil n/3\rceil, sharp for {⌊2n/3⌋+1,…,n}\{\lfloor2n/3\rfloor+1,\ldots,n\} (the abstract prints the large-nn bound as ⌊n/3⌋+1\lfloor n/3\rfloor+1, the same unless 3∣n3\mid n). The proof is a case analysis on ∣A∩(23n,n]∣|A\cap(\tfrac23n,n]| across three regimes (pp. 4--43). Acceptance evidence: the site's label and commentary (the page was edited to PROVED before 8 April 2026); the formal-conjectures entry research solved; an external Lean proof of the N/3+CN/3+C statement (below). Read depth: claims checked for Definition 1 and Theorems 1--2; the 40-page proof was not read.

Formalization and the Lean label. The site's (LEAN) suffix is a catalog label. The formal-conjectures file at the pinned commit is a statement with a sorry body and no formal_proof attribute. Boris Alexeev's collection lean-proofs holds, at its revision of 15 September 2026 that the claim page links, src/latest/ErdosProblems/Erdos13.lean, which describes itself as a Lean formalization of a solution to the problem, names Bedert as the informal author, the formal-conjectures authors as the statement's authors and Codex and GPT-5.6 Sol as the formal authors, and proves erdos_13 : ∃ C : ℝ, ∀ N : ℕ, ∀ A ⊆ Icc 1 N, IsForbiddenTripleFree A → (A.card : ℝ) ≤ (N : ℝ) / 3 + C from an internal bedert_bound; the file contains no sorry, no axiom declaration and no native_decide, and its closing #print axioms line carries no recorded output. It was not built or independently audited here, and no local kernel credit is claimed. The community database lists formal_status as Lean, as of a last update dated 23 August 2026, and has no field for a formal proof's location.

Search scope. None of the routes below found a journal version of [Be23], a review or dispute of its proof, or a result on the rr-fold variant.

  • The site: problem page, discussion thread and proof-claim tab; formal-conjectures at the pinned commit; the community database; the external Lean file at the pinned commit.
  • arXiv: the API record of 2301.07065 (v1 only, no journal reference); the queries abs:"property P" AND (Sárközy OR Sarkozy OR "two larger") (two records, both library sources) and abs:"non-dividing" OR abs:"nondividing" OR all:"divides the sum of two larger" (twelve records; only [Be23] on this problem).
  • Crossref: a bibliographic query for [Be23]'s title (no record); the record of [ErSa70].
  • zbMATH Open: a query for [Be23] (one result, the arXiv preprint).
  • Semantic Scholar: the citation list of arXiv:2301.07065 (no records).
  • The primary sources at the pages stated: [Be23] pp. 1--2, [ErSa70] pp. 97--98, [Er73] pp. 132--133, [Er75b] pp. 302--303, [Er77c] pp. 52--53, [Er80] p. 113 and [Er92c] p. 42.

Not searched: MathSciNet, Google Scholar, X. Not held: [Er95c], [Er97], [Er97e] and [Er98]; [Er97b] is cited from the publisher's open-archive file (see the reference).

Remaining gaps. (1) The status rests on an unrefereed preprint with documented site acceptance and an external, unbuilt Lean proof; a refereed version or an independent review is the reopening condition for the qualification. (2) The proof is compiled at statement level only. (3) Erdős's own distinct-terms conjecture, with maximum [x/3]+1[x/3]+1, is a separate variant that Bedert's theorem as stated does not decide. (4) The rr-fold generalization is open, with the source's printed x/rx/r against the site's N/(r+1)N/(r+1) recorded on the 1992 card.

Linked library material

These entries are derived from explicit links on library pages. They are navigation only and do not by themselves record mathematical progress.