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Problem 151

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claims/: The 2 claim pages of Problem 151, one per claimant's result; the problem's standing derives from them.


Statement. For a graph GG let τ(G)\tau(G) denote the minimal number of vertices that include at least one from each maximal clique of GG on at least two vertices (sometimes called the clique transversal number).

Let H(n)H(n) be maximal such that every triangle-free graph on nn vertices contains an independent set on H(n)H(n) vertices.

If GG is a graph on nn vertices then is

τ(G)≤n−H(n)?\tau(G)\leq n-H(n)?

Formulation. The site's wording (page last edited 2 December 2025). A maximal clique on at least two vertices is what the 1992 paper calls a clique, "a complete subgraph maximal under inclusion and having at least two vertices" (p. 279), so isolated vertices need not be met; τ(G)\tau(G) is the paper's clique-transversal number τC(G)\tau_C(G) and H(n)H(n) its r(n)r(n), the least independence number of a triangle-free graph on nn vertices. In a triangle-free graph the cliques are the edges, a clique transversal is a vertex cover, and τ(G)=n−α(G)\tau(G)=n-\alpha(G) (Lemma 1(b) of the paper, p. 282), so a triangle-free graph with independence number H(n)H(n) has τ(G)=n−H(n)\tau(G)=n-H(n) exactly, and the question is whether any graph on nn vertices does worse. Erdős's 1988 wording asks the same thing as a conjectured equality: with h(n)h(n) the largest τ(G)\tau(G) over graphs on nn vertices, "We conjecture that h(n)h(n) equals to the smallest integer for which every graph of nn vertices which has no triangles has a set of at least n−h(n)n-h(n) independent vertices", that is h(n)=n−H(n)h(n)=n-H(n); since h(n)≥n−H(n)h(n)\ge n-H(n) is the triangle-free case, the conjecture is the site's inequality. The question is exact in H(n)H(n): a bound $\tau(G)\le n-c\sqrt{n\log n}$ with an unspecified cc (Problem 610) has the right order but does not answer it, because H(n)H(n) is itself only known to within constant factors.

Status. Open. No proof, disproof or proof claim for the inequality was found in the search whose scope the Current assessment records. The best explicit upper bound valid for every nn is Theorem 3 of Erdős, Gallai and Tuza (Discrete Math. 108 (1992), refereed): τ(G)≤n−2n+2\tau(G)\le n-\sqrt{2n}+\sqrt2 for every graph on nn vertices, from a linear-time algorithm; their Theorem 1 gives n−2n+32n-\sqrt{2n}+\frac32 by averaging two lemmas. The best asymptotic bound is τ(G)≤n−cnlog⁡n\tau(G)\le n-c\sqrt{n\log n} for some c>0c>0 and all large nn, Corollary 2 of Joret, Micek, Reed and Smid (2021) with the one-line transfer recorded on Problem 610. The conjectured value is n−H(n)n-H(n) with H(n)H(n) of order nlog⁡n\sqrt{n\log n}: the 1992 paper records c1nlog⁡n≤H(n)≤c2nlog⁡nc_1\sqrt{n\log n}\le H(n)\le c_2\sqrt n\log n from Ajtai, Komlós and Szemerédi (1980, refereed; their Theorem 3, R(3,x)<100x2/ln⁡xR(3,x)<100x^2/\ln x, the bound on H(n)H(n) being its elementary rewriting) and Erdős (1961), and Kim's Theorem 1.1 (1995) gives H(n)≤9nlog⁡nH(n)\le9\sqrt{n\log n} for large nn. The 1992 authors write that "so far we could not construct examples worse than triangle-free ones" ([EGT92], p. 280), and Erdős that the conjecture "is perhaps completely wrongheaded". The asymptotic bound matches the order of n−H(n)n-H(n) but not its constant, so it leaves this problem open. This is a bounded negative finding, not a certificate of openness. The inequality holds for every chordal graph, by Tuza's bound τ(G)≤n/2\tau(G)\le n/2 for chordal graphs (Discrete Math. 86 (1990), Theorem 2(a), refereed), an accepted partial claim recorded on its claim page. A partial proof claim of 2026-09-28, the inequality for every graph on at most 39 vertices, is on the site's proof-claim tab; it is recorded as claimed on its claim page and derives nothing for the standing, which stays open.

Source. erdosproblems.com/151, accessed 2026-09-19: the problem page (OPEN, with the site's note that no finite computation can settle the problem; last edited 2 December 2025; source keys [Er88, p. 82] and [EGT92, p. 280]; commentary citing Problem 610), its discussion thread, with one comment (8 September 2025) on that date and three (8 September 2025, 23 and 28 September 2026) on 2026-10-07, and its proof-claim tab, empty on that date and carrying one partial claim, posted 2026-09-28, on 2026-10-07. Cite as: T. F. Bloom, Erdős Problem #151, https://www.erdosproblems.com/151, accessed 2026-09-19.

References.

  • [EGT92] Erdős, P., Gallai, T. and Tuza, Zs., Covering the cliques of a graph with vertices. Discrete Math. 108 (1992), 279--289, doi:10.1016/0012-365X(92)90681-5; received 4 January 1991. The definition, p. 279; Problem 1 and the paragraph after it, p. 280; Problem 3 and the ⟨t⟩\langle t\rangle-property, p. 281; Lemma 1, p. 282; Theorem 1, p. 283; Theorem 3, p. 285. Library home: erdos_1992_covering_cliques_graph_vertices; paged at problem_1, theorem_1 and problem_3.
  • [Er88] Erdős, P., Problems and results in combinatorial analysis and graph theory. Discrete Math. 72 (1988), 81--92; Section 3, printed p. 82. Library home: erdos_1988_problems_results_combinatorial_analysis_graph_theory.
  • [AKS80] Ajtai, M., Komlós, J. and Szemerédi, E., A note on Ramsey numbers. J. Combin. Theory Ser. A 29 (1980), no. 3, 354--360, DOI 10.1016/0097-3165(80)90030-8; [EGT92]'s reference [2]. Theorem 2, printed p. 355 (PDF p. 2 of the publisher's open-archive file): α(G)≥0.01(n/t)ln⁡t\alpha(G)\ge0.01(n/t)\ln t for triangle-free graphs of average degree tt; Theorem 3, printed p. 358 (PDF p. 5 of the same file): R(3,x)<100x2/ln⁡xR(3,x)<100x^2/\ln x, from which H(n)≥c1nlog⁡nH(n)\ge c_1\sqrt{n\log n} follows by the elementary step recorded on its result page (the paper prints no bound on H(n)H(n)). Library home: ajtai_1980_note_ramsey_numbers; paged at theorem_2 and theorem_3.
  • [Er61] Erdős, P., Graph theory and probability. II. Canad. J. Math. 13 (1961), 346--352; [EGT92]'s reference [6], the upper bound H(n)≤c2nlog⁡nH(n)\le c_2\sqrt n\log n (triangle-free graphs on nn vertices with no independent set of [Anlog⁡n][A\sqrt n\log n] vertices). Library home: erdos_1961_graph_theory_probability (its card's account).
  • [Ki95] Kim, J. H., The Ramsey number R(3,t)R(3,t) has order of magnitude t2/log⁡tt^2/\log t. Random Structures Algorithms 7 (1995), 173--207; Theorem 1.1, typescript p. 1. Library home: kim_1995_ramsey_number_has_order_magnitude; paged at theorem_1_1. Not a site key for this problem.
  • [JMRS21] Joret, G., Micek, P., Reed, B. and Smid, M., Tight bounds on the clique chromatic number. Electron. J. Combin. 28 (2021), no. 3, Paper No. P3.51, doi:10.37236/9659; Corollary 2, p. 2. Library home: joret_2021_tight_bounds_clique_chromatic_number; paged at corollary_2. Not a site key for this problem; the Problem 610 source.
  • [Tu90] Tuza, Zs., Covering all cliques of a graph. Discrete Math. 86 (1990), 117--126, doi:10.1016/0012-365X(90)90354-K; [EGT92]'s reference [11], the chordal-graph results; Theorem 2(a), p. 119. Library home: tuza_1990_covering_all_cliques_graph. Claim page: Tuza 1990.
  • [BGMTU25] Boros, E., Gurvich, V., Milanič, M., Tikhanovsky, D. and Uno, Y., Conformality of minimal transversals of maximal cliques. arXiv:2405.10789 (v2 20 June 2025, 34 pp.); and [MiUn24] Milanič, M. and Uno, Y., The upper clique transversal problem. arXiv:2309.14103 (v3 13 August 2024, 29 pp.). Adjacent literature on clique transversals (conformality of the family of minimal transversals; the largest minimal transversal); neither concerns Problem 1. Library homes: boros_2025_conformality_minimal_transversals_maximal_cliques and milanic_2024_upper_clique_transversal_problem.

Formalization. None. formal-conjectures has no file ErdosProblems/151.lean (main, 2026-10-07); the site's page shows the statement as not formalized; the community database (teorth/erdosproblems, data/problems.yaml, 2026-09-19 and 2026-10-06) records the problem open (last update 31 August 2025), unformalized, with no formalized statement and an OEIS entry flagged as possible.

Current assessment

The question. The statement above; OPEN; last edited 2 December 2025. The commentary, in summary, calls τ(G)≤n−n\tau(G)\le n-\sqrt n easy, notes that the inequality is trivial for triangle-free GG, attributes the problem through [Er88] to Erdős and Gallai, who got nowhere with it even for K4K_4-free graphs, repeats Erdős's remark that the conjecture is "perhaps completely wrongheaded", records its later appearance as Problem 1 of [EGT92], and refers the general behavior of τ(G)\tau(G) to Problem 610. The thread has three comments. The comment of 8 September 2025 points to the 1992 paper's Problem 1, after which the site was updated; the comments of 23 and 28 September 2026 are Veljjanoski's SAT and integer-programming check of the inequality for every graph on at most 2222 vertices and his announcement of the write-up for n≤39n\le39. The proof-claim tab carries one partial claim, posted 2026-09-28 and recorded below. The community database record says open.

The origin. [Er88], Section 3, printed p. 82, presents the problem as one Erdős and Gallai had posed recently: h(n)h(n) is the least number of vertices that always suffice to meet every clique of a graph on nn vertices; the bound h(n)≤n−nh(n)\le n-\sqrt n is called easy; and the conjecture is the equality h(n)=n−H(n)h(n)=n-H(n) quoted in the Formulation above. Erdős motivates it by the triangle-free graphs: a triangle-free graph on nn vertices has at least n−h(n)n-h(n) independent vertices, and one with exactly that many has edges as its cliques, so meeting them all takes exactly h(n)h(n) vertices, the complement of a largest independent set; it therefore seemed not unreasonable that h(n)h(n) vertices always suffice. He reports no progress, calls the conjecture "perhaps completely wrongheaded", and adds that they could not handle even the K4K_4-free case, where only the triangles and the edges in no triangle need to be met. The section adds Gallai's chordal-graph conjecture, "indeed proved by Aigner, Andreae and Tuza", recorded on its claim page. [EGT92], p. 280 (problem_1): "Concerning the size of clique-transversals, so far we could not construct examples worse than triangle-free ones. Thus, we ask the following. Problem 1. Denote by r(n)r(n) the largest integer such that every triangle-free graph of order nn contains an independent set of r(n)r(n) vertices. Is $\tau_C(G)\le n-r(n)$ for all graphs GG on nn vertices?", followed by the bounds on r(n)r(n) and "we can only prove τC(G)≤n−2n+c\tau_C(G)\le n-\sqrt{2n}+c for a small constant cc, see Theorems 1 and 3". The site's two page pointers, p. 82 and p. 280, match these passages.

The bounds.

  • Upper bound. Theorem 1 of [EGT92] (p. 283): every graph on nn vertices has a clique transversal of at most n−2n+32n-\sqrt{2n}+\frac32 vertices. The proof averages Lemma 1(a), n−τ≥Δ(G)n-\tau\ge\Delta(G) and n−τ≥α(G)n-\tau\ge\alpha(G), with Lemma 2, n−τ≥α+2n/α−(Δ+3)≥22n−(Δ+3)n-\tau\ge\alpha+2n/\alpha-(\Delta+3)\ge2\sqrt{2n}-(\Delta+3) (read and followed; the lemmas' proofs read for structure). Theorem 3 (p. 285) gets the better n−2n+2n-\sqrt{2n}+\sqrt2, since 2<32\sqrt2<\frac32, from the linear-time algorithm CLCOV (its proof not checked), the best explicit bound for every nn. The site's "easy" bound τ(G)≤n−n\tau(G)\le n-\sqrt n is Erdős's sentence; up to an additive 11 it follows from Lemma 1(a) alone, since a greedy independent set has at least n/(Δ+1)n/(\Delta+1) vertices and so max⁡(α,Δ)≥n−1\max(\alpha,\Delta)\ge\sqrt n-1 (an elementary remark recorded on this page). Read depth: claims checked for Lemma 1 and Theorems 1 and 3. Acceptance: Discrete Mathematics is refereed, and the paper is the site's own source.
  • Lower bound: the triangle-free graphs, where τ(G)=n−α(G)\tau(G)=n-\alpha(G) exactly (Lemma 1(b)), give h(n)≥n−H(n)h(n)\ge n-H(n); with Kim's Theorem 1.1 (typescript p. 1: triangle-free graphs on nn vertices with α≤9nlog⁡n\alpha\le9\sqrt{n\log n} for large nn) there are graphs with τ(G)≥n−9nlog⁡n\tau(G)\ge n-9\sqrt{n\log n}. No graph with τ(G)>n−H(n)\tau(G)>n-H(n) is known to the sources cited.
  • The order of H(n)H(n): c1nlog⁡n≤H(n)≤c2nlog⁡nc_1\sqrt{n\log n}\le H(n)\le c_2\sqrt n\log n as [EGT92] states it from [AKS80] and [Er61]; Kim's theorem sharpens the upper bound to 9nlog⁡n9\sqrt{n\log n}, so H(n)=Θ(nlog⁡n)H(n)=\Theta(\sqrt{n\log n}) with the constants open (the constant question is Problem 165's side of the matter). The conjecture therefore predicts τ(G)≤n−c1nlog⁡n\tau(G)\le n-c_1\sqrt{n\log n}, which the resolution of Problem 610 proves for some constant and all large nn, the best asymptotic bound, while the conjecture's exact statement needs the true H(n)H(n), which neither side supplies.

The K4K_4-free case. Erdős's "We could not make any progress even if we assumed that our G(n)G(n) has no K(4)K(4)" and [EGT92]'s "An interesting particular case of Problem 1 is to prove τC(G)≤n−r(n)\tau_C(G)\le n-r(n) for 'sparse' graphs; K4K_4-free ones, for instance" (p. 280) lead to their Problem 3 (p. 281), the Erdős--Rogers question of Problem 620, whose current bounds that page records; nothing found there resolves the K4K_4-free case of this problem.

Adjacent leads (not status). Two preprints on clique transversals: [BGMTU25] (card) characterizes the graphs whose minimal clique transversals form the maximal cliques of a graph (within triangle-free and split graphs), and [MiUn24] (card) studies the largest minimal clique transversal; both are structural or algorithmic and neither addresses Problem 1. The arXiv API's latest records for "clique transversal" (six, to 2025) are these two, a paper on transversals of maximum independent sets, one on conformal hypergraphs, one on a transversal game and one on chordal graphs; none is on this problem. The Aigner--Andreae manuscript of 1986 behind the chordal results is unpublished; Tuza's 1990 paper gives the published proof.

Search scope. None of the routes below found a proof, a counterexample, a bound closer to n−H(n)n-H(n) than the explicit n−2n+2n-\sqrt{2n}+\sqrt2 and the asymptotic n−cnlog⁡nn-c\sqrt{n\log n}, or a proof claim.

  • The site: problem page, discussion thread and proof-claim tab, read 2026-09-19; the formal-conjectures directory and tree at main on that date (no file 151); the community database on that date.
  • arXiv API: all:"clique transversal" sorted by date (six records, listed above; the hyphenated form returns the same six); two author queries for a possible arXiv version of the Ma--Tang note of Problem 1034 (unrelated to this page).
  • Crossref: the record of doi:10.37236/9659 ([JMRS21], the Problem 610 source); OpenAlex: its two citing works (both on random graphs, neither on clique transversals).
  • The "graphs problem collection" pages the site's Problem 610 page links (mathweb.ucsd.edu/~erdosproblems, "CliqueTransversal" and "CliqueTransversalUpperBound", read 2026-09-19): both state Problem 1 in the 1992 paper's words and say "So far, the best current bound [1] is τ(G)≤n−2n+c\tau(G)\le n-\sqrt{2n}+c for a small constant cc".
  • The primary sources: [EGT92] pp. 279--283, 285 and 288; [Er88] p. 82; Kim's Theorem 1.1 on its result page; the first pages of the two preprints.

Not searched: MathSciNet, zbMATH, Google Scholar, Semantic Scholar, X. Not held: the Aigner--Andreae manuscript, Erdős's 1994 and 1999 collections (source keys of Problems 610 and 611, not of this one).

Remaining gaps. (1) The conjecture is proved for triangle-free and chordal graphs, and claimed (unreviewed) for n≤39n\le39 and for graphs in which every edge lies in at most two triangles: no graph with τ(G)>n−H(n)\tau(G)>n-H(n) and no proof; reopening condition: a proof of τ(G)≤n−H(n)\tau(G)\le n-H(n) or a graph violating it, or a determination of H(n)H(n) to within an additive error small enough to compare with the general bounds. (2) H(n)H(n) itself is known only to within constant factors; the lower bound is Theorem 3 of [AKS80], its statement checked and its four-sentence proof followed, the rewriting as a bound on H(n)H(n) being an elementary step recorded on its result page, and the proof of the independence theorem behind it (Theorem 2) was followed for structure only. (3) Proof coverage: Theorem 1's derivation from the two lemmas was followed and the lemmas read for structure; nothing is independently reviewed; there is no resolving proof to compile. (4) There is no Lean statement of the problem.

Proof claims on the site. The site's proof-claim tab carries one claim, partial: Daniel Veljjanoski's write-up of 2026-09-28, which asserts the inequality for every graph on at most 39 vertices by a minimum-counterexample reduction and a new Euler-circuit argument for the case in which every edge lies in at most two triangles, and which says where the method stops (n≥40n\ge40). It is recorded, with its links and its own account of what was and was not checked, on its claim page as claimed; the site's label is unchanged (OPEN; page last edited 2 December 2025), and no step of the write-up has been checked. A partial claim derives nothing for the standing. The write-up credits its reduction to issue 9934 of a GitHub repository, posted on 25 September 2026 by the user AlyciaBHZ as a research log produced by Codex (a controller and command-line workers) with one advisory reply from a model the log records as gpt_6_pro. The log states the minimum-counterexample reduction and, through a cited theorem of Liang, Shan and Kang on clique-coloring claw-free graphs, excludes every counterexample on at most 2828 vertices; it says that it does not solve the problem for all orders and is not submitted as a partial result, and it is neither a dated manuscript nor a posting on the site's tab, so it has no claim page.

Known results

  • Erdős--Gallai--Tuza 1992, Problem 1: the question in the paper's words, with the bounds on r(n)r(n) and the authors' remark that no examples worse than triangle-free ones are known.
  • Erdős--Gallai--Tuza 1992, Theorem 1 (refereed): τ(G)≤n−2n+32\tau(G)\le n-\sqrt{2n}+\frac32; Theorem 3 (card): n−2n+2n-\sqrt{2n}+\sqrt2 in linear time; Lemma 1(b): τ(G)=n−α(G)\tau(G)=n-\alpha(G) for triangle-free GG.
  • [Er88], p. 82: the conjecture as Erdős and Gallai posed it, the "easy" h(n)≤n−nh(n)\le n-\sqrt n, and the K4K_4-free remark.
  • Kim 1995, Theorem 1.1 (refereed): H(n)≤9nlog⁡nH(n)\le9\sqrt{n\log n} for large nn, so triangle-free graphs reach τ(G)≥n−9nlog⁡n\tau(G)\ge n-9\sqrt{n\log n}; with Ajtai--Komlós--Szemerédi 1980, Theorem 3 (refereed), R(3,x)<100x2/ln⁡xR(3,x)<100x^2/\ln x, rewritten on its result page as H(n)≥⌊115nln⁡n⌋H(n)\ge\lfloor\frac1{15}\sqrt{n\ln n}\rfloor for large nn, H(n)=Θ(nlog⁡n)H(n)=\Theta(\sqrt{n\log n}).
  • Joret--Micek--Reed--Smid 2021, Corollary 2 (refereed) with the transfer on Problem 610: τ(G)≤n−cnlog⁡n\tau(G)\le n-c\sqrt{n\log n} for some c>0c>0 and large nn, the right order for this conjecture but not its constant.
  • Problem 3 and Problem 620: the question the 1992 paper poses concerning the K4K_4-free particular case, open in the refereed record and claimed by a 2026 preprint.
  • Tuza 1990, Theorem 2(a) (refereed; accepted partial claim): τ(G)≤n/2\tau(G)\le n/2 for every chordal graph, so the inequality holds for chordal graphs, since H(n)≤⌈n/2⌉H(n)\le\lceil n/2\rceil.
  • Veljjanoski 2026 (claimed, unreviewed): the inequality for every graph on at most 39 vertices and for every graph in which each edge lies in at most two triangles.

Linked library material

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